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Solve by Substitution x+2y+3z=90 , 3y+z=36

$x + 2 y + 3 z = 90$ , $3 y + z = 36$

Step 1

$x + 2 y + 3 z = 90, 3 y + z = 36$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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