Finite Math Examples

$4 x - y - 3 z = 8$ , $2 x + y - z = 3$ , $6 x + y - 3 z = 2$

Step 1

Move all terms not containing $y$ to the right side of the equation.

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Step 1.1

Subtract $2 x$ from both sides of the equation.

$y - z = 3 - 2 x$

$4 x - y - 3 z = 8$

$6 x + y - 3 z = 2$

Step 1.2

Add $z$ to both sides of the equation.

$y = 3 - 2 x + z$

$4 x - y - 3 z = 8$

$6 x + y - 3 z = 2$

$y = 3 - 2 x + z$

$4 x - y - 3 z = 8$

$6 x + y - 3 z = 2$

Step 2

Replace all occurrences of $y$ with $3 - 2 x + z$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $4 x - y - 3 z = 8$ with $3 - 2 x + z$ .

$4 x - (3 - 2 x + z) - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $4 x - (3 - 2 x + z) - 3 z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$4 x - 1 \cdot 3 - (- 2 x) - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $- 1$ by $3$ .

$4 x - 3 - (- 2 x) - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.2.1.1.2.2

Multiply $- 2$ by $- 1$ .

$4 x - 3 + 2 x - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

$4 x - 3 + 2 x - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

$4 x - 3 + 2 x - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $4 x$ and $2 x$ .

$6 x - 3 - z - 3 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.2.1.2.2

Subtract $3 z$ from $- z$ .

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$6 x + y - 3 z = 2$

Step 2.3

Replace all occurrences of $y$ in $6 x + y - 3 z = 2$ with $3 - 2 x + z$ .

$6 x + 3 - 2 x + z - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $6 x + 3 - 2 x + z - 3 z$ .

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Step 2.4.1.1

Remove parentheses.

$6 x + 3 - 2 x + z - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 2.4.1.2

Subtract $2 x$ from $6 x$ .

$4 x + 3 + z - 3 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 2.4.1.3

Subtract $3 z$ from $z$ .

$4 x + 3 - 2 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$4 x + 3 - 2 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$4 x + 3 - 2 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$4 x + 3 - 2 z = 2$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3

Solve for $x$ in $4 x + 3 - 2 z = 2$ .

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Step 3.1

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1.1

Subtract $3$ from both sides of the equation.

$4 x - 2 z = 2 - 3$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.1.2

Add $2 z$ to both sides of the equation.

$4 x = 2 - 3 + 2 z$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.1.3

Subtract $3$ from $2$ .

$4 x = - 1 + 2 z$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$4 x = - 1 + 2 z$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2

Divide each term in $4 x = - 1 + 2 z$ by $4$ and simplify.

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Step 3.2.1

Divide each term in $4 x = - 1 + 2 z$ by $4$ .

$\frac{4 x}{4} = \frac{- 1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $4$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{4 x}{4} = \frac{- 1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = \frac{- 1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = \frac{- 1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Move the negative in front of the fraction.

$x = - \frac{1}{4} + \frac{2 z}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.3.1.2

Cancel the common factor of $2$ and $4$ .

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Step 3.2.3.1.2.1

Factor $2$ out of $2 z$ .

$x = - \frac{1}{4} + \frac{2 (z)}{4}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.3.1.2.2

Cancel the common factors.

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Step 3.2.3.1.2.2.1

Factor $2$ out of $4$ .

$x = - \frac{1}{4} + \frac{2 z}{2 \cdot 2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.3.1.2.2.2

Cancel the common factor.

$x = - \frac{1}{4} + \frac{2 z}{2 \cdot 2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 3.2.3.1.2.2.3

Rewrite the expression.

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

$x = - \frac{1}{4} + \frac{z}{2}$

$6 x - 3 - 4 z = 8$

$y = 3 - 2 x + z$

Step 4

Replace all occurrences of $x$ with $- \frac{1}{4} + \frac{z}{2}$ in each equation.

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Step 4.1

Replace all occurrences of $x$ in $6 x - 3 - 4 z = 8$ with $- \frac{1}{4} + \frac{z}{2}$ .

$6 (- \frac{1}{4} + \frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $6 (- \frac{1}{4} + \frac{z}{2}) - 3 - 4 z$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$6 (- \frac{1}{4}) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.2

Cancel the common factor of $2$ .

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Step 4.2.1.1.2.1

Move the leading negative in $- \frac{1}{4}$ into the numerator.

$6 (\frac{- 1}{4}) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.2.2

Factor $2$ out of $6$ .

$2 (3) (\frac{- 1}{4}) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.2.3

Factor $2$ out of $4$ .

$2 \cdot (3 (\frac{- 1}{2 \cdot 2})) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.2.4

Cancel the common factor.

$2 \cdot (3 (\frac{- 1}{2 \cdot 2})) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.2.5

Rewrite the expression.

$3 (\frac{- 1}{2}) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$3 (\frac{- 1}{2}) + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.3

Combine $3$ and $\frac{- 1}{2}$ .

$\frac{3 \cdot - 1}{2} + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.4

Multiply $3$ by $- 1$ .

$\frac{- 3}{2} + 6 (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.5

Cancel the common factor of $2$ .

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Step 4.2.1.1.5.1

Factor $2$ out of $6$ .

$\frac{- 3}{2} + 2 (3) (\frac{z}{2}) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.5.2

Cancel the common factor.

$\frac{- 3}{2} + 2 \cdot (3 (\frac{z}{2})) - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.5.3

Rewrite the expression.

$\frac{- 3}{2} + 3 z - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$\frac{- 3}{2} + 3 z - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.1.6

Move the negative in front of the fraction.

$- \frac{3}{2} + 3 z - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$- \frac{3}{2} + 3 z - 3 - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.2

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$3 z - \frac{3}{2} - 3 \cdot \frac{2}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.3

Combine $- 3$ and $\frac{2}{2}$ .

$3 z - \frac{3}{2} + \frac{- 3 \cdot 2}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.4

Combine the numerators over the common denominator.

$3 z + \frac{- 3 - 3 \cdot 2}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.5

Simplify the numerator.

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Step 4.2.1.5.1

Multiply $- 3$ by $2$ .

$3 z + \frac{- 3 - 6}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.5.2

Subtract $6$ from $- 3$ .

$3 z + \frac{- 9}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$3 z + \frac{- 9}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.6

Move the negative in front of the fraction.

$3 z - \frac{9}{2} - 4 z = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.2.1.7

Subtract $4 z$ from $3 z$ .

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 2 x + z$

Step 4.3

Replace all occurrences of $x$ in $y = 3 - 2 x + z$ with $- \frac{1}{4} + \frac{z}{2}$ .

$y = 3 - 2 (- \frac{1}{4} + \frac{z}{2}) + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $3 - 2 (- \frac{1}{4} + \frac{z}{2}) + z$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$y = 3 - 2 (- \frac{1}{4}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.2

Cancel the common factor of $2$ .

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Step 4.4.1.1.2.1

Move the leading negative in $- \frac{1}{4}$ into the numerator.

$y = 3 - 2 (\frac{- 1}{4}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.2.2

Factor $2$ out of $- 2$ .

$y = 3 + 2 (- 1) (\frac{- 1}{4}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.2.3

Factor $2$ out of $4$ .

$y = 3 + 2 \cdot (- 1 \frac{- 1}{2 \cdot 2}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.2.4

Cancel the common factor.

$y = 3 + 2 \cdot (- 1 \frac{- 1}{2 \cdot 2}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.2.5

Rewrite the expression.

$y = 3 - 1 (\frac{- 1}{2}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 1 (\frac{- 1}{2}) - 2 \frac{z}{2} + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.3

Cancel the common factor of $2$ .

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Step 4.4.1.1.3.1

Factor $2$ out of $- 2$ .

$y = 3 - 1 (\frac{- 1}{2}) + 2 (- 1) (\frac{z}{2}) + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.3.2

Cancel the common factor.

$y = 3 - 1 (\frac{- 1}{2}) + 2 \cdot (- 1 \frac{z}{2}) + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.3.3

Rewrite the expression.

$y = 3 - 1 (\frac{- 1}{2}) - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 - 1 (\frac{- 1}{2}) - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.4

Simplify each term.

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Step 4.4.1.1.4.1

Move the negative in front of the fraction.

$y = 3 - 1 (- \frac{1}{2}) - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.4.2

Multiply $- 1 (- \frac{1}{2})$ .

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Step 4.4.1.1.4.2.1

Multiply $- 1$ by $- 1$ .

$y = 3 + 1 (\frac{1}{2}) - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.4.2.2

Multiply $\frac{1}{2}$ by $1$ .

$y = 3 + \frac{1}{2} - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 + \frac{1}{2} - 1 z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.1.4.3

Rewrite $- 1 z$ as $- z$ .

$y = 3 + \frac{1}{2} - z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 + \frac{1}{2} - z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 + \frac{1}{2} - z + z$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.2

Combine the opposite terms in $3 + \frac{1}{2} - z + z$ .

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Step 4.4.1.2.1

Add $- z$ and $z$ .

$y = 3 + \frac{1}{2} + 0$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.2.2

Add $3 + \frac{1}{2}$ and $0$ .

$y = 3 + \frac{1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = 3 + \frac{1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.3

To write $3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = 3 \cdot \frac{2}{2} + \frac{1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.4

Combine $3$ and $\frac{2}{2}$ .

$y = \frac{3 \cdot 2}{2} + \frac{1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.5

Combine the numerators over the common denominator.

$y = \frac{3 \cdot 2 + 1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.6

Simplify the numerator.

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Step 4.4.1.6.1

Multiply $3$ by $2$ .

$y = \frac{6 + 1}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 4.4.1.6.2

Add $6$ and $1$ .

$y = \frac{7}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = \frac{7}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = \frac{7}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = \frac{7}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

$y = \frac{7}{2}$

$- z - \frac{9}{2} = 8$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5

Solve for $z$ in $- z - \frac{9}{2} = 8$ .

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Step 5.1

Move all terms not containing $z$ to the right side of the equation.

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Step 5.1.1

Add $\frac{9}{2}$ to both sides of the equation.

$- z = 8 + \frac{9}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.1.2

To write $8$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$- z = 8 \cdot \frac{2}{2} + \frac{9}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.1.3

Combine $8$ and $\frac{2}{2}$ .

$- z = \frac{8 \cdot 2}{2} + \frac{9}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.1.4

Combine the numerators over the common denominator.

$- z = \frac{8 \cdot 2 + 9}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.1.5

Simplify the numerator.

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Step 5.1.5.1

Multiply $8$ by $2$ .

$- z = \frac{16 + 9}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.1.5.2

Add $16$ and $9$ .

$- z = \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$- z = \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$- z = \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.2

Divide each term in $- z = \frac{25}{2}$ by $- 1$ and simplify.

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Step 5.2.1

Divide each term in $- z = \frac{25}{2}$ by $- 1$ .

$\frac{- z}{- 1} = \frac{\frac{25}{2}}{- 1}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.2.2

Simplify the left side.

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Step 5.2.2.1

Dividing two negative values results in a positive value.

$\frac{z}{1} = \frac{\frac{25}{2}}{- 1}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.2.2.2

Divide $z$ by $1$ .

$z = \frac{\frac{25}{2}}{- 1}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$z = \frac{\frac{25}{2}}{- 1}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.2.3

Simplify the right side.

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Step 5.2.3.1

Move the negative one from the denominator of $\frac{\frac{25}{2}}{- 1}$ .

$z = - 1 \cdot \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 5.2.3.2

Rewrite $- 1 \cdot \frac{25}{2}$ as $- \frac{25}{2}$ .

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} + \frac{z}{2}$

Step 6

Replace all occurrences of $z$ with $- \frac{25}{2}$ in each equation.

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Step 6.1

Replace all occurrences of $z$ in $x = - \frac{1}{4} + \frac{z}{2}$ with $- \frac{25}{2}$ .

$x = - \frac{1}{4} + \frac{- \frac{25}{2}}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $- \frac{1}{4} + \frac{- \frac{25}{2}}{2}$ .

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Step 6.2.1.1

Simplify each term.

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Step 6.2.1.1.1

Multiply the numerator by the reciprocal of the denominator.

$x = - \frac{1}{4} - \frac{25}{2} \cdot \frac{1}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.1.2

Multiply $- \frac{25}{2} \cdot \frac{1}{2}$ .

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Step 6.2.1.1.2.1

Multiply $\frac{1}{2}$ by $\frac{25}{2}$ .

$x = - \frac{1}{4} - \frac{25}{2 \cdot 2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.1.2.2

Multiply $2$ by $2$ .

$x = - \frac{1}{4} - \frac{25}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} - \frac{25}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{1}{4} - \frac{25}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2

Simplify terms.

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Step 6.2.1.2.1

Combine the numerators over the common denominator.

$x = \frac{- 1 - 25}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.2

Subtract $25$ from $- 1$ .

$x = \frac{- 26}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.3

Cancel the common factor of $- 26$ and $4$ .

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Step 6.2.1.2.3.1

Factor $2$ out of $- 26$ .

$x = \frac{2 (- 13)}{4}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.3.2

Cancel the common factors.

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Step 6.2.1.2.3.2.1

Factor $2$ out of $4$ .

$x = \frac{2 \cdot - 13}{2 \cdot 2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.3.2.2

Cancel the common factor.

$x = \frac{2 \cdot - 13}{2 \cdot 2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.3.2.3

Rewrite the expression.

$x = \frac{- 13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = \frac{- 13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = \frac{- 13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 6.2.1.2.4

Move the negative in front of the fraction.

$x = - \frac{13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

$x = - \frac{13}{2}$

$z = - \frac{25}{2}$

$y = \frac{7}{2}$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- \frac{13}{2}, \frac{7}{2}, - \frac{25}{2})$

Step 8

The result can be shown in multiple forms.

Point Form:

$(- \frac{13}{2}, \frac{7}{2}, - \frac{25}{2})$

Equation Form:

$x = - \frac{13}{2}, y = \frac{7}{2}, z = - \frac{25}{2}$