Finite Math Examples

$3 x + 2 y - 1 z = 2$ , $2 x - 3 y + 1 z = - 2$ , $1 x - 1 y - z = - 4$

Step 1

Move all terms not containing $z$ to the right side of the equation.

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Step 1.1

Subtract $2 x$ from both sides of the equation.

$- 3 y + z = - 2 - 2 x$

$3 x + 2 y - 1 z = 2$

$x - 1 y - z = - 4$

Step 1.2

Add $3 y$ to both sides of the equation.

$z = - 2 - 2 x + 3 y$

$3 x + 2 y - 1 z = 2$

$x - 1 y - z = - 4$

$z = - 2 - 2 x + 3 y$

$3 x + 2 y - 1 z = 2$

$x - 1 y - z = - 4$

Step 2

Replace all occurrences of $z$ with $- 2 - 2 x + 3 y$ in each equation.

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Step 2.1

Replace all occurrences of $z$ in $3 x + 2 y - 1 z = 2$ with $- 2 - 2 x + 3 y$ .

$3 x + 2 y - 1 (- 2 - 2 x + 3 y) = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $3 x + 2 y - 1 (- 2 - 2 x + 3 y)$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$3 x + 2 y - 1 \cdot - 2 - 1 (- 2 x) - 1 (3 y) = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $- 1$ by $- 2$ .

$3 x + 2 y + 2 - 1 (- 2 x) - 1 (3 y) = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2.1.1.2.2

Multiply $- 2$ by $- 1$ .

$3 x + 2 y + 2 + 2 x - 1 (3 y) = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2.1.1.2.3

Multiply $3$ by $- 1$ .

$3 x + 2 y + 2 + 2 x - 3 y = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

$3 x + 2 y + 2 + 2 x - 3 y = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

$3 x + 2 y + 2 + 2 x - 3 y = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $3 x$ and $2 x$ .

$5 x + 2 y + 2 - 3 y = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.2.1.2.2

Subtract $3 y$ from $2 y$ .

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - 1 y - z = - 4$

Step 2.3

Replace all occurrences of $z$ in $x - 1 y - z = - 4$ with $- 2 - 2 x + 3 y$ .

$x - 1 y - (- 2 - 2 x + 3 y) = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $x - 1 y - (- 2 - 2 x + 3 y)$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Rewrite $- 1 y$ as $- y$ .

$x - y - (- 2 - 2 x + 3 y) = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.1.2

Apply the distributive property.

$x - y + 2 - (- 2 x) - (3 y) = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.1.3

Simplify.

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Step 2.4.1.1.3.1

Multiply $- 1$ by $- 2$ .

$x - y + 2 - (- 2 x) - (3 y) = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.1.3.2

Multiply $- 2$ by $- 1$ .

$x - y + 2 + 2 x - (3 y) = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.1.3.3

Multiply $3$ by $- 1$ .

$x - y + 2 + 2 x - 3 y = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - y + 2 + 2 x - 3 y = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x - y + 2 + 2 x - 3 y = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Add $x$ and $2 x$ .

$3 x - y + 2 - 3 y = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 2.4.1.2.2

Subtract $3 y$ from $- y$ .

$3 x - 4 y + 2 = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$3 x - 4 y + 2 = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$3 x - 4 y + 2 = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$3 x - 4 y + 2 = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$3 x - 4 y + 2 = - 4$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3

Solve for $x$ in $3 x - 4 y + 2 = - 4$ .

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Step 3.1

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1.1

Add $4 y$ to both sides of the equation.

$3 x + 2 = - 4 + 4 y$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.1.2

Subtract $2$ from both sides of the equation.

$3 x = - 4 + 4 y - 2$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.1.3

Subtract $2$ from $- 4$ .

$3 x = 4 y - 6$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$3 x = 4 y - 6$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.2

Divide each term in $3 x = 4 y - 6$ by $3$ and simplify.

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Step 3.2.1

Divide each term in $3 x = 4 y - 6$ by $3$ .

$\frac{3 x}{3} = \frac{4 y}{3} + \frac{- 6}{3}$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $3$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{4 y}{3} + \frac{- 6}{3}$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{4 y}{3} + \frac{- 6}{3}$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x = \frac{4 y}{3} + \frac{- 6}{3}$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x = \frac{4 y}{3} + \frac{- 6}{3}$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Divide $- 6$ by $3$ .

$x = \frac{4 y}{3} - 2$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x = \frac{4 y}{3} - 2$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x = \frac{4 y}{3} - 2$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

$x = \frac{4 y}{3} - 2$

$5 x - y + 2 = 2$

$z = - 2 - 2 x + 3 y$

Step 4

Replace all occurrences of $x$ with $\frac{4 y}{3} - 2$ in each equation.

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Step 4.1

Replace all occurrences of $x$ in $5 x - y + 2 = 2$ with $\frac{4 y}{3} - 2$ .

$5 (\frac{4 y}{3} - 2) - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $5 (\frac{4 y}{3} - 2) - y + 2$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$5 (\frac{4 y}{3}) + 5 \cdot - 2 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.1.2

Multiply $5 \frac{4 y}{3}$ .

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Step 4.2.1.1.2.1

Combine $5$ and $\frac{4 y}{3}$ .

$\frac{5 (4 y)}{3} + 5 \cdot - 2 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.1.2.2

Multiply $4$ by $5$ .

$\frac{20 y}{3} + 5 \cdot - 2 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{20 y}{3} + 5 \cdot - 2 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.1.3

Multiply $5$ by $- 2$ .

$\frac{20 y}{3} - 10 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{20 y}{3} - 10 - y + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.2

To write $- y$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{20 y}{3} - y \cdot \frac{3}{3} - 10 + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.3

Combine $- y$ and $\frac{3}{3}$ .

$\frac{20 y}{3} + \frac{- y \cdot 3}{3} - 10 + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.4

Combine the numerators over the common denominator.

$\frac{20 y - y \cdot 3}{3} - 10 + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5

Find the common denominator.

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Step 4.2.1.5.1

Write $- 10$ as a fraction with denominator $1$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10}{1} + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5.2

Multiply $\frac{- 10}{1}$ by $\frac{3}{3}$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10}{1} \cdot \frac{3}{3} + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5.3

Multiply $\frac{- 10}{1}$ by $\frac{3}{3}$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10 \cdot 3}{3} + 2 = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5.4

Write $2$ as a fraction with denominator $1$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10 \cdot 3}{3} + \frac{2}{1} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5.5

Multiply $\frac{2}{1}$ by $\frac{3}{3}$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10 \cdot 3}{3} + \frac{2}{1} \cdot \frac{3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.5.6

Multiply $\frac{2}{1}$ by $\frac{3}{3}$ .

$\frac{20 y - y \cdot 3}{3} + \frac{- 10 \cdot 3}{3} + \frac{2 \cdot 3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{20 y - y \cdot 3}{3} + \frac{- 10 \cdot 3}{3} + \frac{2 \cdot 3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.6

Combine the numerators over the common denominator.

$\frac{20 y - y \cdot 3 - 10 \cdot 3 + 2 \cdot 3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.7

Simplify each term.

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Step 4.2.1.7.1

Multiply $3$ by $- 1$ .

$\frac{20 y - 3 y - 10 \cdot 3 + 2 \cdot 3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.7.2

Multiply $- 10$ by $3$ .

$\frac{20 y - 3 y - 30 + 2 \cdot 3}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.7.3

Multiply $2$ by $3$ .

$\frac{20 y - 3 y - 30 + 6}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{20 y - 3 y - 30 + 6}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.8

Simplify by adding terms.

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Step 4.2.1.8.1

Subtract $3 y$ from $20 y$ .

$\frac{17 y - 30 + 6}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.2.1.8.2

Add $- 30$ and $6$ .

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - 2 x + 3 y$

Step 4.3

Replace all occurrences of $x$ in $z = - 2 - 2 x + 3 y$ with $\frac{4 y}{3} - 2$ .

$z = - 2 - 2 (\frac{4 y}{3} - 2) + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $- 2 - 2 (\frac{4 y}{3} - 2) + 3 y$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$z = - 2 - 2 \frac{4 y}{3} - 2 \cdot - 2 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.1.2

Multiply $- 2 \frac{4 y}{3}$ .

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Step 4.4.1.1.2.1

Combine $- 2$ and $\frac{4 y}{3}$ .

$z = - 2 + \frac{- 2 (4 y)}{3} - 2 \cdot - 2 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.1.2.2

Multiply $4$ by $- 2$ .

$z = - 2 + \frac{- 8 y}{3} - 2 \cdot - 2 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 + \frac{- 8 y}{3} - 2 \cdot - 2 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.1.3

Multiply $- 2$ by $- 2$ .

$z = - 2 + \frac{- 8 y}{3} + 4 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.1.4

Move the negative in front of the fraction.

$z = - 2 - \frac{8 y}{3} + 4 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = - 2 - \frac{8 y}{3} + 4 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.2

Add $- 2$ and $4$ .

$z = - \frac{8 y}{3} + 2 + 3 y$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.3

To write $3 y$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$z = - \frac{8 y}{3} + 3 y \cdot \frac{3}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.4

Simplify terms.

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Step 4.4.1.4.1

Combine $3 y$ and $\frac{3}{3}$ .

$z = - \frac{8 y}{3} + \frac{3 y \cdot 3}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.4.2

Combine the numerators over the common denominator.

$z = \frac{- 8 y + 3 y \cdot 3}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{- 8 y + 3 y \cdot 3}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5

Simplify each term.

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Step 4.4.1.5.1

Simplify the numerator.

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Step 4.4.1.5.1.1

Factor $y$ out of $- 8 y + 3 y \cdot 3$ .

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Step 4.4.1.5.1.1.1

Factor $y$ out of $- 8 y$ .

$z = \frac{y \cdot - 8 + 3 y \cdot 3}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5.1.1.2

Factor $y$ out of $3 y \cdot 3$ .

$z = \frac{y \cdot - 8 + y (3 \cdot 3)}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5.1.1.3

Factor $y$ out of $y \cdot - 8 + y (3 \cdot 3)$ .

$z = \frac{y (- 8 + 3 \cdot 3)}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y (- 8 + 3 \cdot 3)}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5.1.2

Multiply $3$ by $3$ .

$z = \frac{y (- 8 + 9)}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5.1.3

Add $- 8$ and $9$ .

$z = \frac{y \cdot 1}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y \cdot 1}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 4.4.1.5.2

Multiply $y$ by $1$ .

$z = \frac{y}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

$z = \frac{y}{3} + 2$

$\frac{17 y - 24}{3} = 2$

$x = \frac{4 y}{3} - 2$

Step 5

Solve for $y$ in $\frac{17 y - 24}{3} = 2$ .

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Step 5.1

Multiply both sides by $3$ .

$\frac{17 y - 24}{3} \cdot 3 = 2 \cdot 3$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.2

Simplify.

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Step 5.2.1

Simplify the left side.

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Step 5.2.1.1

Cancel the common factor of $3$ .

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Step 5.2.1.1.1

Cancel the common factor.

$\frac{17 y - 24}{3} \cdot 3 = 2 \cdot 3$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.2.1.1.2

Rewrite the expression.

$17 y - 24 = 2 \cdot 3$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$17 y - 24 = 2 \cdot 3$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$17 y - 24 = 2 \cdot 3$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.2.2

Simplify the right side.

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Step 5.2.2.1

Multiply $2$ by $3$ .

$17 y - 24 = 6$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$17 y - 24 = 6$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$17 y - 24 = 6$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.3

Solve for $y$ .

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Step 5.3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 5.3.1.1

Add $24$ to both sides of the equation.

$17 y = 6 + 24$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.3.1.2

Add $6$ and $24$ .

$17 y = 30$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$17 y = 30$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.3.2

Divide each term in $17 y = 30$ by $17$ and simplify.

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Step 5.3.2.1

Divide each term in $17 y = 30$ by $17$ .

$\frac{17 y}{17} = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.3.2.2

Simplify the left side.

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Step 5.3.2.2.1

Cancel the common factor of $17$ .

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Step 5.3.2.2.1.1

Cancel the common factor.

$\frac{17 y}{17} = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 5.3.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

$y = \frac{30}{17}$

$z = \frac{y}{3} + 2$

$x = \frac{4 y}{3} - 2$

Step 6

Replace all occurrences of $y$ with $\frac{30}{17}$ in each equation.

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Step 6.1

Replace all occurrences of $y$ in $z = \frac{y}{3} + 2$ with $\frac{30}{17}$ .

$z = \frac{\frac{30}{17}}{3} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $\frac{\frac{30}{17}}{3} + 2$ .

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Step 6.2.1.1

Simplify each term.

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Step 6.2.1.1.1

Multiply the numerator by the reciprocal of the denominator.

$z = \frac{30}{17} \cdot \frac{1}{3} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.1.2

Cancel the common factor of $3$ .

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Step 6.2.1.1.2.1

Factor $3$ out of $30$ .

$z = \frac{3 (10)}{17} \cdot \frac{1}{3} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.1.2.2

Cancel the common factor.

$z = \frac{3 \cdot 10}{17} \cdot \frac{1}{3} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.1.2.3

Rewrite the expression.

$z = \frac{10}{17} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

$z = \frac{10}{17} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

$z = \frac{10}{17} + 2$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.2

To write $2$ as a fraction with a common denominator, multiply by $\frac{17}{17}$ .

$z = \frac{10}{17} + 2 \cdot \frac{17}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.3

Combine $2$ and $\frac{17}{17}$ .

$z = \frac{10}{17} + \frac{2 \cdot 17}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.4

Combine the numerators over the common denominator.

$z = \frac{10 + 2 \cdot 17}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.5

Simplify the numerator.

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Step 6.2.1.5.1

Multiply $2$ by $17$ .

$z = \frac{10 + 34}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.2.1.5.2

Add $10$ and $34$ .

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{4 y}{3} - 2$

Step 6.3

Replace all occurrences of $y$ in $x = \frac{4 y}{3} - 2$ with $\frac{30}{17}$ .

$x = \frac{4 (\frac{30}{17})}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $\frac{4 (\frac{30}{17})}{3} - 2$ .

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Step 6.4.1.1

Simplify each term.

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Step 6.4.1.1.1

Combine $4$ and $\frac{30}{17}$ .

$x = \frac{\frac{4 \cdot 30}{17}}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.1.2

Multiply $4$ by $30$ .

$x = \frac{\frac{120}{17}}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.1.3

Multiply the numerator by the reciprocal of the denominator.

$x = \frac{120}{17} \cdot \frac{1}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.1.4

Cancel the common factor of $3$ .

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Step 6.4.1.1.4.1

Factor $3$ out of $120$ .

$x = \frac{3 (40)}{17} \cdot \frac{1}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.1.4.2

Cancel the common factor.

$x = \frac{3 \cdot 40}{17} \cdot \frac{1}{3} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.1.4.3

Rewrite the expression.

$x = \frac{40}{17} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{40}{17} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{40}{17} - 2$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.2

To write $- 2$ as a fraction with a common denominator, multiply by $\frac{17}{17}$ .

$x = \frac{40}{17} - 2 \cdot \frac{17}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.3

Combine $- 2$ and $\frac{17}{17}$ .

$x = \frac{40}{17} + \frac{- 2 \cdot 17}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.4

Combine the numerators over the common denominator.

$x = \frac{40 - 2 \cdot 17}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.5

Simplify the numerator.

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Step 6.4.1.5.1

Multiply $- 2$ by $17$ .

$x = \frac{40 - 34}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 6.4.1.5.2

Subtract $34$ from $40$ .

$x = \frac{6}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{6}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{6}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{6}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

$x = \frac{6}{17}$

$z = \frac{44}{17}$

$y = \frac{30}{17}$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(\frac{6}{17}, \frac{30}{17}, \frac{44}{17})$

Step 8

The result can be shown in multiple forms.

Point Form:

$(\frac{6}{17}, \frac{30}{17}, \frac{44}{17})$

Equation Form:

$x = \frac{6}{17}, y = \frac{30}{17}, z = \frac{44}{17}$