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Solve by Substitution x+3y+4z=16 , 2x-y+z=4

$x + 3 y + 4 z = 16$ , $2 x - y + z = 4$

Step 1

$x + 3 y + 4 z = 16, 2 x - y + z = 4$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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