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Solve by Substitution x+2y+5z=16 , 2x-3y+3z=4

$x + 2 y + 5 z = 16$ , $2 x - 3 y + 3 z = 4$

Step 1

$x + 2 y + 5 z = 16, 2 x - 3 y + 3 z = 4$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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