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Solve by Substitution x+2y+4z=6 , x+y+2z=3

$x + 2 y + 4 z = 6$ , $x + y + 2 z = 3$

Step 1

$x + 2 y + 4 z = 6, x + y + 2 z = 3$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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