Finite Math Examples

$x - 2 y + 3 z = 19$ , $2 x + y + z = 3$ , $- 3 x + 2 y - 2 z = - 17$

Step 1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1

Add $2 y$ to both sides of the equation.

$x + 3 z = 19 + 2 y$

$2 x + y + z = 3$

$- 3 x + 2 y - 2 z = - 17$

Step 1.2

Subtract $3 z$ from both sides of the equation.

$x = 19 + 2 y - 3 z$

$2 x + y + z = 3$

$- 3 x + 2 y - 2 z = - 17$

$x = 19 + 2 y - 3 z$

$2 x + y + z = 3$

$- 3 x + 2 y - 2 z = - 17$

Step 2

Replace all occurrences of $x$ with $19 + 2 y - 3 z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $2 x + y + z = 3$ with $19 + 2 y - 3 z$ .

$2 (19 + 2 y - 3 z) + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $2 (19 + 2 y - 3 z) + y + z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$2 \cdot 19 + 2 (2 y) + 2 (- 3 z) + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $2$ by $19$ .

$38 + 2 (2 y) + 2 (- 3 z) + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2.1.1.2.2

Multiply $2$ by $2$ .

$38 + 4 y + 2 (- 3 z) + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2.1.1.2.3

Multiply $- 3$ by $2$ .

$38 + 4 y - 6 z + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

$38 + 4 y - 6 z + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

$38 + 4 y - 6 z + y + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $4 y$ and $y$ .

$38 + 5 y - 6 z + z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.2.1.2.2

Add $- 6 z$ and $z$ .

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 3 x + 2 y - 2 z = - 17$

Step 2.3

Replace all occurrences of $x$ in $- 3 x + 2 y - 2 z = - 17$ with $19 + 2 y - 3 z$ .

$- 3 (19 + 2 y - 3 z) + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $- 3 (19 + 2 y - 3 z) + 2 y - 2 z$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$- 3 \cdot 19 - 3 (2 y) - 3 (- 3 z) + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Multiply $- 3$ by $19$ .

$- 57 - 3 (2 y) - 3 (- 3 z) + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4.1.1.2.2

Multiply $2$ by $- 3$ .

$- 57 - 6 y - 3 (- 3 z) + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4.1.1.2.3

Multiply $- 3$ by $- 3$ .

$- 57 - 6 y + 9 z + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 6 y + 9 z + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 6 y + 9 z + 2 y - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Add $- 6 y$ and $2 y$ .

$- 57 - 4 y + 9 z - 2 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 2.4.1.2.2

Subtract $2 z$ from $9 z$ .

$- 57 - 4 y + 7 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 4 y + 7 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 4 y + 7 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 4 y + 7 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 57 - 4 y + 7 z = - 17$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3

Solve for $y$ in $- 57 - 4 y + 7 z = - 17$ .

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Step 3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 3.1.1

Add $57$ to both sides of the equation.

$- 4 y + 7 z = - 17 + 57$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.1.2

Subtract $7 z$ from both sides of the equation.

$- 4 y = - 17 + 57 - 7 z$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.1.3

Add $- 17$ and $57$ .

$- 4 y = 40 - 7 z$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$- 4 y = 40 - 7 z$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.2

Divide each term in $- 4 y = 40 - 7 z$ by $- 4$ and simplify.

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Step 3.2.1

Divide each term in $- 4 y = 40 - 7 z$ by $- 4$ .

$\frac{- 4 y}{- 4} = \frac{40}{- 4} + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $- 4$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{- 4 y}{- 4} = \frac{40}{- 4} + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{40}{- 4} + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = \frac{40}{- 4} + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = \frac{40}{- 4} + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Divide $40$ by $- 4$ .

$y = - 10 + \frac{- 7 z}{- 4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 3.2.3.1.2

Dividing two negative values results in a positive value.

$y = - 10 + \frac{7 z}{4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = - 10 + \frac{7 z}{4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = - 10 + \frac{7 z}{4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = - 10 + \frac{7 z}{4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

$y = - 10 + \frac{7 z}{4}$

$38 + 5 y - 5 z = 3$

$x = 19 + 2 y - 3 z$

Step 4

Replace all occurrences of $y$ with $- 10 + \frac{7 z}{4}$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $38 + 5 y - 5 z = 3$ with $- 10 + \frac{7 z}{4}$ .

$38 + 5 (- 10 + \frac{7 z}{4}) - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $38 + 5 (- 10 + \frac{7 z}{4}) - 5 z$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$38 + 5 \cdot - 10 + 5 (\frac{7 z}{4}) - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.1.2

Multiply $5$ by $- 10$ .

$38 - 50 + 5 (\frac{7 z}{4}) - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.1.3

Multiply $5 \frac{7 z}{4}$ .

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Step 4.2.1.1.3.1

Combine $5$ and $\frac{7 z}{4}$ .

$38 - 50 + \frac{5 (7 z)}{4} - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.1.3.2

Multiply $7$ by $5$ .

$38 - 50 + \frac{35 z}{4} - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$38 - 50 + \frac{35 z}{4} - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$38 - 50 + \frac{35 z}{4} - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.2

Subtract $50$ from $38$ .

$- 12 + \frac{35 z}{4} - 5 z = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.3

To write $- 5 z$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- 12 + \frac{35 z}{4} - 5 z \cdot \frac{4}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.4

Simplify terms.

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Step 4.2.1.4.1

Combine $- 5 z$ and $\frac{4}{4}$ .

$- 12 + \frac{35 z}{4} + \frac{- 5 z \cdot 4}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.4.2

Combine the numerators over the common denominator.

$- 12 + \frac{35 z - 5 z \cdot 4}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$- 12 + \frac{35 z - 5 z \cdot 4}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5

Simplify the numerator.

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Step 4.2.1.5.1

Factor $5 z$ out of $35 z - 5 z \cdot 4$ .

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Step 4.2.1.5.1.1

Factor $5 z$ out of $35 z$ .

$- 12 + \frac{5 z (7) - 5 z \cdot 4}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5.1.2

Factor $5 z$ out of $- 5 z \cdot 4$ .

$- 12 + \frac{5 z (7) + 5 z (- 1 \cdot 4)}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5.1.3

Factor $5 z$ out of $5 z (7) + 5 z (- 1 \cdot 4)$ .

$- 12 + \frac{5 z (7 - 1 \cdot 4)}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$- 12 + \frac{5 z (7 - 1 \cdot 4)}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5.2

Multiply $- 1$ by $4$ .

$- 12 + \frac{5 z (7 - 4)}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5.3

Subtract $4$ from $7$ .

$- 12 + \frac{5 z \cdot 3}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.2.1.5.4

Multiply $3$ by $5$ .

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 + 2 y - 3 z$

Step 4.3

Replace all occurrences of $y$ in $x = 19 + 2 y - 3 z$ with $- 10 + \frac{7 z}{4}$ .

$x = 19 + 2 (- 10 + \frac{7 z}{4}) - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $19 + 2 (- 10 + \frac{7 z}{4}) - 3 z$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$x = 19 + 2 \cdot - 10 + 2 (\frac{7 z}{4}) - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.1.2

Multiply $2$ by $- 10$ .

$x = 19 - 20 + 2 (\frac{7 z}{4}) - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.1.3

Cancel the common factor of $2$ .

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Step 4.4.1.1.3.1

Factor $2$ out of $4$ .

$x = 19 - 20 + 2 (\frac{7 z}{2 (2)}) - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.1.3.2

Cancel the common factor.

$x = 19 - 20 + 2 (\frac{7 z}{2 \cdot 2}) - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.1.3.3

Rewrite the expression.

$x = 19 - 20 + \frac{7 z}{2} - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 - 20 + \frac{7 z}{2} - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = 19 - 20 + \frac{7 z}{2} - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.2

Subtract $20$ from $19$ .

$x = - 1 + \frac{7 z}{2} - 3 z$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.3

To write $- 3 z$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$x = - 1 + \frac{7 z}{2} - 3 z \cdot \frac{2}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.4

Simplify terms.

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Step 4.4.1.4.1

Combine $- 3 z$ and $\frac{2}{2}$ .

$x = - 1 + \frac{7 z}{2} + \frac{- 3 z \cdot 2}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.4.2

Combine the numerators over the common denominator.

$x = - 1 + \frac{7 z - 3 z \cdot 2}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{7 z - 3 z \cdot 2}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5

Simplify each term.

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Step 4.4.1.5.1

Simplify the numerator.

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Step 4.4.1.5.1.1

Factor $z$ out of $7 z - 3 z \cdot 2$ .

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Step 4.4.1.5.1.1.1

Factor $z$ out of $7 z$ .

$x = - 1 + \frac{z \cdot 7 - 3 z \cdot 2}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5.1.1.2

Factor $z$ out of $- 3 z \cdot 2$ .

$x = - 1 + \frac{z \cdot 7 + z (- 3 \cdot 2)}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5.1.1.3

Factor $z$ out of $z \cdot 7 + z (- 3 \cdot 2)$ .

$x = - 1 + \frac{z (7 - 3 \cdot 2)}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z (7 - 3 \cdot 2)}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5.1.2

Multiply $- 3$ by $2$ .

$x = - 1 + \frac{z (7 - 6)}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5.1.3

Subtract $6$ from $7$ .

$x = - 1 + \frac{z \cdot 1}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z \cdot 1}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 4.4.1.5.2

Multiply $z$ by $1$ .

$x = - 1 + \frac{z}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

$x = - 1 + \frac{z}{2}$

$- 12 + \frac{15 z}{4} = 3$

$y = - 10 + \frac{7 z}{4}$

Step 5

Solve for $z$ in $- 12 + \frac{15 z}{4} = 3$ .

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Step 5.1

Move all terms not containing $z$ to the right side of the equation.

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Step 5.1.1

Add $12$ to both sides of the equation.

$\frac{15 z}{4} = 3 + 12$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.1.2

Add $3$ and $12$ .

$\frac{15 z}{4} = 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$\frac{15 z}{4} = 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.2

Multiply both sides of the equation by $\frac{4}{15}$ .

$\frac{4}{15} \cdot \frac{15 z}{4} = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3

Simplify both sides of the equation.

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Step 5.3.1

Simplify the left side.

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Step 5.3.1.1

Simplify $\frac{4}{15} \cdot \frac{15 z}{4}$ .

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Step 5.3.1.1.1

Cancel the common factor of $4$ .

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Step 5.3.1.1.1.1

Cancel the common factor.

$\frac{4}{15} \cdot \frac{15 z}{4} = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.1.1.1.2

Rewrite the expression.

$\frac{1}{15} \cdot (15 z) = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$\frac{1}{15} \cdot (15 z) = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.1.1.2

Cancel the common factor of $15$ .

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Step 5.3.1.1.2.1

Factor $15$ out of $15 z$ .

$\frac{1}{15} \cdot (15 (z)) = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.1.1.2.2

Cancel the common factor.

$\frac{1}{15} \cdot (15 z) = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.1.1.2.3

Rewrite the expression.

$z = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.2

Simplify the right side.

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Step 5.3.2.1

Cancel the common factor of $15$ .

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Step 5.3.2.1.1

Cancel the common factor.

$z = \frac{4}{15} \cdot 15$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 5.3.2.1.2

Rewrite the expression.

$z = 4$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = 4$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = 4$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = 4$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

$z = 4$

$x = - 1 + \frac{z}{2}$

$y = - 10 + \frac{7 z}{4}$

Step 6

Replace all occurrences of $z$ with $4$ in each equation.

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Step 6.1

Replace all occurrences of $z$ in $x = - 1 + \frac{z}{2}$ with $4$ .

$x = - 1 + \frac{4}{2}$

$z = 4$

$y = - 10 + \frac{7 z}{4}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $- 1 + \frac{4}{2}$ .

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Step 6.2.1.1

Divide $4$ by $2$ .

$x = - 1 + 2$

$z = 4$

$y = - 10 + \frac{7 z}{4}$

Step 6.2.1.2

Add $- 1$ and $2$ .

$x = 1$

$z = 4$

$y = - 10 + \frac{7 z}{4}$

$x = 1$

$z = 4$

$y = - 10 + \frac{7 z}{4}$

$x = 1$

$z = 4$

$y = - 10 + \frac{7 z}{4}$

Step 6.3

Replace all occurrences of $z$ in $y = - 10 + \frac{7 z}{4}$ with $4$ .

$y = - 10 + \frac{7 (4)}{4}$

$x = 1$

$z = 4$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $- 10 + \frac{7 (4)}{4}$ .

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Step 6.4.1.1

Multiply $7$ by $4$ .

$y = - 10 + \frac{28}{4}$

$x = 1$

$z = 4$

Step 6.4.1.2

Divide $28$ by $4$ .

$y = - 10 + 7$

$x = 1$

$z = 4$

Step 6.4.1.3

Add $- 10$ and $7$ .

$y = - 3$

$x = 1$

$z = 4$

$y = - 3$

$x = 1$

$z = 4$

$y = - 3$

$x = 1$

$z = 4$

$y = - 3$

$x = 1$

$z = 4$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(1, - 3, 4)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(1, - 3, 4)$

Equation Form:

$x = 1, y = - 3, z = 4$