Finite Math Examples

$y = \frac{1}{3} x + 4$ , $3 y = x + 12$

Step 1

Combine $\frac{1}{3}$ and $x$ .

$y = \frac{x}{3} + 4$

$3 y = x + 12$

Step 2

Replace all occurrences of $y$ with $\frac{x}{3} + 4$ in each equation.

Tap for more steps...

Step 2.1

Replace all occurrences of $y$ in $3 y = x + 12$ with $\frac{x}{3} + 4$ .

$3 (\frac{x}{3} + 4) = x + 12$

$y = \frac{x}{3} + 4$

Step 2.2

Simplify the left side.

Tap for more steps...

Step 2.2.1

Simplify $3 (\frac{x}{3} + 4)$ .

Tap for more steps...

Step 2.2.1.1

Apply the distributive property.

$3 (\frac{x}{3}) + 3 \cdot 4 = x + 12$

$y = \frac{x}{3} + 4$

Step 2.2.1.2

Cancel the common factor of $3$ .

Tap for more steps...

Step 2.2.1.2.1

Cancel the common factor.

$3 (\frac{x}{3}) + 3 \cdot 4 = x + 12$

$y = \frac{x}{3} + 4$

Step 2.2.1.2.2

Rewrite the expression.

$x + 3 \cdot 4 = x + 12$

$y = \frac{x}{3} + 4$

$x + 3 \cdot 4 = x + 12$

$y = \frac{x}{3} + 4$

Step 2.2.1.3

Multiply $3$ by $4$ .

$x + 12 = x + 12$

$y = \frac{x}{3} + 4$

$x + 12 = x + 12$

$y = \frac{x}{3} + 4$

$x + 12 = x + 12$

$y = \frac{x}{3} + 4$

$x + 12 = x + 12$

$y = \frac{x}{3} + 4$

Step 3

Remove any equations from the system that are always true.

$y = \frac{x}{3} + 4$

Step 4