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Solve by Substitution x+y-4z=0 , 2x+y-3z=2

$x + y - 4 z = 0$ , $2 x + y - 3 z = 2$

Step 1

$x + y - 4 z = 0, 2 x + y - 3 z = 2$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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