Finite Math Examples

$x \cdot 1 + 4 x \cdot 2 = 14$ , $- 2 x \cdot 1 + 5 x \cdot 2 = 11$

Step 1

Divide each term in $9 x = 14$ by $9$ and simplify.

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Step 1.1

Divide each term in $9 x = 14$ by $9$ .

$\frac{9 x}{9} = \frac{14}{9}$

$8 x = 11$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $9$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{9 x}{9} = \frac{14}{9}$

$8 x = 11$

Step 1.2.1.2

Divide $x$ by $1$ .

$x = \frac{14}{9}$

$8 x = 11$

$x = \frac{14}{9}$

$8 x = 11$

$x = \frac{14}{9}$

$8 x = 11$

$x = \frac{14}{9}$

$8 x = 11$

Step 2

Replace all occurrences of $x$ with $\frac{14}{9}$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $8 x = 11$ with $\frac{14}{9}$ .

$8 (\frac{14}{9}) = 11$

$x = \frac{14}{9}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Multiply $8 (\frac{14}{9})$ .

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Step 2.2.1.1

Combine $8$ and $\frac{14}{9}$ .

$\frac{8 \cdot 14}{9} = 11$

$x = \frac{14}{9}$

Step 2.2.1.2

Multiply $8$ by $14$ .

$\frac{112}{9} = 11$

$x = \frac{14}{9}$

$\frac{112}{9} = 11$

$x = \frac{14}{9}$

$\frac{112}{9} = 11$

$x = \frac{14}{9}$

$\frac{112}{9} = 11$

$x = \frac{14}{9}$

Step 3

Since $\frac{112}{9} = 11$ is not true, there is no solution.

No solution

Step 4