Finite Math Examples

$5.8$ , $7.8$ , $1.8$ , $3.2$ , $9.3$ , $5.7$ , $6.8$ , $7.5$ , $2.6$ , $2.4$ , $4.4$

Step 1

The mean of a set of numbers is the sum divided by the number of terms.

$\frac{5.8 + 7.8 + 1.8 + 3.2 + 9.3 + 5.7 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2

Simplify the numerator.

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Step 2.1

Add $5.8$ and $7.8$ .

$\frac{13.6 + 1.8 + 3.2 + 9.3 + 5.7 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.2

Add $13.6$ and $1.8$ .

$\frac{15.4 + 3.2 + 9.3 + 5.7 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.3

Add $15.4$ and $3.2$ .

$\frac{18.6 + 9.3 + 5.7 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.4

Add $18.6$ and $9.3$ .

$\frac{27.9 + 5.7 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.5

Add $27.9$ and $5.7$ .

$\frac{33.6 + 6.8 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.6

Add $33.6$ and $6.8$ .

$\frac{40.4 + 7.5 + 2.6 + 2.4 + 4.4}{11}$

Step 2.7

Add $40.4$ and $7.5$ .

$\frac{47.9 + 2.6 + 2.4 + 4.4}{11}$

Step 2.8

Add $47.9$ and $2.6$ .

$\frac{50.5 + 2.4 + 4.4}{11}$

Step 2.9

Add $50.5$ and $2.4$ .

$\frac{52.9 + 4.4}{11}$

Step 2.10

Add $52.9$ and $4.4$ .

$\frac{57.3}{11}$

Step 3

Divide $57.3$ by $11$ .

$5.2\overline{09}$

Step 4

Divide.

$5.2\overline{09}$

Step 5

The mean should be rounded to one more decimal place than the original data. If the original data were mixed, round to one decimal place more than the least precise.

$5.21$