Finite Math Examples

4 P 2

${}_{4}P_{2}$

Step 1

Evaluate

4 P 2

${}_{4}P_{2}$ using the formula

n P r = \frac{n!}{(n - r)!}

${}_{n}P_{r} = \frac{n!}{(n - r)!}$ .

\frac{4!}{(4 - 2)!}

$\frac{4!}{(4 - 2)!}$

Step 2

Subtract

2

$2$ from

4

$4$ .

\frac{4!}{(2)!}

$\frac{4!}{(2)!}$

Step 3

Simplify

\frac{4!}{(2)!}

$\frac{4!}{(2)!}$ .

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Step 3.1

Rewrite

4!

$4!$ as

4 \cdot 3 \cdot 2!

$4 \cdot 3 \cdot 2!$ .

\frac{4 \cdot 3 \cdot 2!}{(2)!}

$\frac{4 \cdot 3 \cdot 2!}{(2)!}$

Step 3.2

Cancel the common factor of

2!

$2!$ .

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Step 3.2.1

Cancel the common factor.

$\frac{4 \cdot 3 \cdot 2!}{(2)!}$

Step 3.2.2

Divide

$4 \cdot 3$ by

$1$ .

$4 \cdot 3$

$4 \cdot 3$

Step 3.3

Multiply

$4$ by

$3$ .

$12$

$12$

${}_{4}P_{2}$

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$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$