Chemistry Examples

$B a {(N O_{3})}_{2}$

Step 1

To find the mass of $1$ mole of $B a {(N O_{3})}_{2}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $B a {(N O_{3})}_{2}$ $=$ $(mass of Ba)$ + $2 (mass of N)$ + $6 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $B a {(N O_{3})}_{2}$ $=$ $(137.33000183)$ + $2 (14.01000022)$ + $6 (16)$

Step 3

Simplify the result.

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Step 3.1

Simplify each term.

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Step 3.1.1

Multiply $2$ by $14.01000022$ .

mass of $1$ mole of $B a {(N O_{3})}_{2} = 137.33000183 + 28.02000045 + 6 (16) g$

Step 3.1.2

Multiply $6$ by $16$ .

mass of $1$ mole of $B a {(N O_{3})}_{2} = 137.33000183 + 28.02000045 + 96 g$

Step 3.2

Simplify by adding numbers.

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Step 3.2.1

Add $137.33000183$ and $28.02000045$ .

mass of $1$ mole of $B a {(N O_{3})}_{2} = 165.35000228 + 96 g$

Step 3.2.2

Add $165.35000228$ and $96$ .

mass of $1$ mole of $B a {(N O_{3})}_{2} = 261.35000228 g$