Chemistry Examples

$4 (x - 1) - 1 = 2 (2 x - 3)$

Step 1

Simplify $4 (x - 1) - 1$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$4 x + 4 \cdot - 1 - 1 = 2 (2 x - 3)$

Step 1.1.2

Multiply $4$ by $- 1$ .

$4 x - 4 - 1 = 2 (2 x - 3)$

$4 x - 4 - 1 = 2 (2 x - 3)$

Step 1.2

Subtract $1$ from $- 4$ .

$4 x - 5 = 2 (2 x - 3)$

$4 x - 5 = 2 (2 x - 3)$

Step 2

Simplify $2 (2 x - 3)$ .

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Step 2.1

Apply the distributive property.

$4 x - 5 = 2 (2 x) + 2 \cdot - 3$

Step 2.2

Multiply.

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Step 2.2.1

Multiply $2$ by $2$ .

$4 x - 5 = 4 x + 2 \cdot - 3$

Step 2.2.2

Multiply $2$ by $- 3$ .

$4 x - 5 = 4 x - 6$

$4 x - 5 = 4 x - 6$

$4 x - 5 = 4 x - 6$

Step 3

Move all terms containing $x$ to the left side of the equation.

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Step 3.1

Subtract $4 x$ from both sides of the equation.

$4 x - 5 - 4 x = - 6$

Step 3.2

Combine the opposite terms in $4 x - 5 - 4 x$ .

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Step 3.2.1

Subtract $4 x$ from $4 x$ .

$0 - 5 = - 6$

Step 3.2.2

Subtract $5$ from $0$ .

$- 5 = - 6$

$- 5 = - 6$

$- 5 = - 6$

Step 4

Since $- 5 \neq - 6$ , there are no solutions.

No solution

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$