Chemistry Examples

$P b {(C N O)}_{2}$

Step 1

To find the mass of $1$ mole of $P b {(C N O)}_{2}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $P b {(C N O)}_{2}$ $=$ $(mass of Pb)$ + $2 (mass of C)$ + $2 (mass of N)$ + $2 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $P b {(C N O)}_{2}$ $=$ $(207.19999694)$ + $2 (12.01000022)$ + $2 (14.01000022)$ + $2 (16)$

Step 3

Simplify the result.

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Step 3.1

Simplify each term.

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Step 3.1.1

Multiply $2$ by $12.01000022$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 207.19999694 + 24.02000045 + 2 (14.01000022) + 2 (16) g$

Step 3.1.2

Multiply $2$ by $14.01000022$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 207.19999694 + 24.02000045 + 28.02000045 + 2 (16) g$

Step 3.1.3

Multiply $2$ by $16$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 207.19999694 + 24.02000045 + 28.02000045 + 32 g$

Step 3.2

Simplify by adding numbers.

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Step 3.2.1

Add $207.19999694$ and $24.02000045$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 231.2199974 + 28.02000045 + 32 g$

Step 3.2.2

Add $231.2199974$ and $28.02000045$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 259.23999786 + 32 g$

Step 3.2.3

Add $259.23999786$ and $32$ .

mass of $1$ mole of $P b {(C N O)}_{2} = 291.23999786 g$