Chemistry Examples

$N H_{4}$

Step 1

$N H_{4}$ is soluble because it contains ammonium $N H_{4}$ . All ammonium compounds are soluble .

$N H_{4}$ is soluble

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$