Chemistry Examples

$L i C I$

Step 1

To find the mass of $1$ mole of $L i C I$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $L i C I$ $=$ $(mass of Li)$ + $(mass of C)$ + $(mass of I)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $L i C I$ $=$ $(6.94000005)$ + $(12.01000022)$ + $(126.90000152)$

Step 3

Simplify the result.

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Step 3.1

Remove parentheses.

mass of $1$ mole of $L i C I = 6.94000005 + 12.01000022 + 126.90000152 g$

Step 3.2

Add $6.94000005$ and $12.01000022$ .

mass of $1$ mole of $L i C I = 18.95000028 + 126.90000152 g$

Step 3.3

Add $18.95000028$ and $126.90000152$ .

mass of $1$ mole of $L i C I = 145.85000181 g$

Step 4

One mole of any gas occupies $22.4 L$ at STP (standard temperature and pressure).

$V = 22.4 L$

Step 5

Density is mass over volume.

$\frac{145.85000181 g}{22.4 L}$

Step 6

Factor $145.85000181$ out of $145.85000181 g$ .

$\frac{145.85000181 (g)}{22.4 L}$

Step 7

Factor $22.4$ out of $22.4 L$ .

$\frac{145.85000181 (g)}{22.4 (L)}$

Step 8

Separate fractions.

$\frac{145.85000181}{22.4} \cdot \frac{g}{L}$

Step 9

Divide $145.85000181$ by $22.4$ .

$6.51116079 \frac{g}{L}$

Step 10

Combine $6.51116079$ and $\frac{g}{L}$ .

$\frac{6.51116079 g}{L}$