Chemistry Examples

$52.8 mg C N$

Step 1

To find the mass of $1$ mole of $52.8 mg C N$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $52.8 mg C N$ $=$ $(mass of U)$ + $(mass of N)$ + $(mass of I)$ + $(mass of T>mg)$ + $(mass of C)$ + $(mass of N)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $52.8 mg C N$ $=$ $(238.02999877)$ + $(14.01000022)$ + $(126.90000152)$ + $(0)$ + $(12.01000022)$ + $(14.01000022)$

Step 3

Simplify the result.

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Step 3.1

Remove parentheses.

mass of $1$ mole of $52.8 mg C N = 238.02999877 + 14.01000022 + 126.90000152 + 0 + 12.01000022 + 14.01000022 g$

Step 3.2

Add $238.02999877$ and $14.01000022$ .

mass of $1$ mole of $52.8 mg C N = 252.039999 + 126.90000152 + 0 + 12.01000022 + 14.01000022 g$

Step 3.3

Add $252.039999$ and $126.90000152$ .

mass of $1$ mole of $52.8 mg C N = 378.94000053 + 0 + 12.01000022 + 14.01000022 g$

Step 3.4

Add $378.94000053$ and $0$ .

mass of $1$ mole of $52.8 mg C N = 378.94000053 + 12.01000022 + 14.01000022 g$

Step 3.5

Add $378.94000053$ and $12.01000022$ .

mass of $1$ mole of $52.8 mg C N = 390.95000076 + 14.01000022 g$

Step 3.6

Add $390.95000076$ and $14.01000022$ .

mass of $1$ mole of $52.8 mg C N = 404.96000099 g$