Chemistry Examples

$F e_{3} {(P o_{4})}_{2}$

Step 1

To find the mass of $1$ mole of $F e_{3} {(P o_{4})}_{2}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

Step 2

Fill in the atomic masses from the periodic table.

Step 3

Simplify the result.

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Step 3.1

Simplify each term.

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Step 3.1.1

Multiply $3$ by $55.84999847$ .

mass of $1$ mole of $F e_{3} {(P o_{4})}_{2} = 167.54999542 + 8 (209) g$

Step 3.1.2

Multiply $8$ by $209$ .

mass of $1$ mole of $F e_{3} {(P o_{4})}_{2} = 167.54999542 + 1672 g$

Step 3.2

Add $167.54999542$ and $1672$ .

mass of $1$ mole of $F e_{3} {(P o_{4})}_{2} = 1839.54999542 g$