Chemistry Examples

$N a H C O_{3}$

Step 1

To find the mass of $1$ mole of $N a H C O_{3}$ look up the atomic mass of each element and multiply it by the number of atoms contained in each element in the molecule.

mass of $1$ mole of $N a H C O_{3}$ $=$ $(mass of Na)$ + $(mass of H)$ + $(mass of C)$ + $3 (mass of O)$

Step 2

Fill in the atomic masses from the periodic table.

mass of $1$ mole of $N a H C O_{3}$ $=$ $(22.98999977)$ + $(1.00999999)$ + $(12.01000022)$ + $3 (16)$

Step 3

Simplify the result.

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Step 3.1

Remove parentheses.

mass of $1$ mole of $N a H C O_{3} = 22.98999977 + 1.00999999 + 12.01000022 + 3 (16) g$

Step 3.2

Multiply $3$ by $16$ .

mass of $1$ mole of $N a H C O_{3} = 22.98999977 + 1.00999999 + 12.01000022 + 48 g$

Step 3.3

Add $22.98999977$ and $1.00999999$ .

mass of $1$ mole of $N a H C O_{3} = 23.99999976 + 12.01000022 + 48 g$

Step 3.4

Add $23.99999976$ and $12.01000022$ .

mass of $1$ mole of $N a H C O_{3} = 36.00999999 + 48 g$

Step 3.5

Add $36.00999999$ and $48$ .

mass of $1$ mole of $N a H C O_{3} = 84.00999999 g$

Step 4

Find the mass percentage of $N a$ .

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Step 4.1

The mass composition percentage is the mass of $N a$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $N a = \frac{22.99}{84.00999999} \cdot 100$

Step 4.2

Divide $22.99$ by $84.00999999$ .

$0.27365789 \cdot 100$

Step 4.3

Multiply $0.27365789$ by $100$ .

$27.36578979$

Step 4.4

Set the number as a percent.

Mass percentage of $N a = 27.36578979 %$

Step 5

Find the mass percentage of $H$ .

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Step 5.1

The mass composition percentage is the mass of $H$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $H = \frac{1.01}{84.00999999} \cdot 100$

Step 5.2

Divide $1.01$ by $84.00999999$ .

$0.01202237 \cdot 100$

Step 5.3

Multiply $0.01202237$ by $100$ .

$1.20223782$

Step 5.4

Set the number as a percent.

Mass percentage of $H = 1.20223782 %$

Step 6

Find the mass percentage of $C$ .

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Step 6.1

The mass composition percentage is the mass of $C$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $C = \frac{12.01}{84.00999999} \cdot 100$

Step 6.2

Divide $12.01$ by $84.00999999$ .

$0.14295917 \cdot 100$

Step 6.3

Multiply $0.14295917$ by $100$ .

$14.29591715$

Step 6.4

Set the number as a percent.

Mass percentage of $C = 14.29591715 %$

Step 7

Find the mass percentage of $O$ .

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Step 7.1

The mass composition percentage is the mass of $O$ divided by the mass of the entire molecule converted to a percentage.

Mass percentage of $O = \frac{48}{84.00999999} \cdot 100$

Step 7.2

Divide $48$ by $84.00999999$ .

$0.57136055 \cdot 100$

Step 7.3

Multiply $0.57136055$ by $100$ .

$57.13605523$

Step 7.4

Set the number as a percent.

Mass percentage of $O = 57.13605523 %$

Step 8

Find the mass percentage of each element in the molecule.

Mass percentage of $N a = 27.36578979 %$

Mass percentage of $H = 1.20223782 %$

Mass percentage of $C = 14.29591715 %$

Mass percentage of $O = 57.13605523 %$