Calculus Examples

$\sum_{i = 1}^{16} 2 i$

Step 1

Factor $2$ out of the summation.

$2 \sum_{k = 1}^{16} i$

Step 2

The formula for the summation of a polynomial with degree $1$ is:

$\sum_{k = 1}^{n} i = \frac{n (n + 1)}{2}$

Step 3

Substitute the values into the formula and make sure to multiply by the front term.

$(2) (\frac{16 (16 + 1)}{2})$

Step 4

Simplify.

Tap for more steps...

Simplify the expression.

Tap for more steps...

Add $16$ and $1$ .

$2 \frac{16 \cdot 17}{2}$

Multiply $16$ by $17$ .

$2 (\frac{272}{2})$

Cancel the common factor of $2$ .

Tap for more steps...

Cancel the common factor.

$2 (\frac{272}{2})$

Rewrite the expression.

$272$