Calculus Examples

- 3 (y - 5) = 24

$- 3 (y - 5) = 24$

Step 1

Divide each term in

- 3 (y - 5) = 24

$- 3 (y - 5) = 24$ by

- 3

$- 3$ and simplify.

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Step 1.1

Divide each term in

- 3 (y - 5) = 24

$- 3 (y - 5) = 24$ by

- 3

$- 3$ .

\frac{- 3 (y - 5)}{- 3} = \frac{24}{- 3}

$\frac{- 3 (y - 5)}{- 3} = \frac{24}{- 3}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of

- 3

$- 3$ .

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Step 1.2.1.1

Cancel the common factor.

\frac{- 3 (y - 5)}{- 3} = \frac{24}{- 3}

$\frac{- 3 (y - 5)}{- 3} = \frac{24}{- 3}$

Step 1.2.1.2

Divide

y - 5

$y - 5$ by

1

$1$ .

y - 5 = \frac{24}{- 3}

$y - 5 = \frac{24}{- 3}$

y - 5 = \frac{24}{- 3}

$y - 5 = \frac{24}{- 3}$

y - 5 = \frac{24}{- 3}

$y - 5 = \frac{24}{- 3}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Divide

24

$24$ by

- 3

$- 3$ .

y - 5 = - 8

$y - 5 = - 8$

y - 5 = - 8

$y - 5 = - 8$

y - 5 = - 8

$y - 5 = - 8$

Step 2

Move all terms not containing

y

$y$ to the right side of the equation.

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Step 2.1

Add

5

$5$ to both sides of the equation.

y = - 8 + 5

$y = - 8 + 5$

Step 2.2

Add

- 8

$- 8$ and

5

$5$ .

y = - 3

$y = - 3$

y = - 3

$y = - 3$

- 3 (y - 5) = 24

$- 3 (y - 5) = 24$

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[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$