Calculus Examples

Find the Integral arcsin(x)dx
arcsin(x)dx
Step 1
Integrate by parts using the formula udv=uv-vdu, where u=arcsin(x) and dv=1.
arcsin(x)x-x11-x2dx
Step 2
Combine x and 11-x2.
arcsin(x)x-x1-x2dx
Step 3
Let u=1-x2. Then du=-2xdx, so -12du=xdx. Rewrite using u and du.
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Step 3.1
Let u=1-x2. Find dudx.
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Step 3.1.1
Differentiate 1-x2.
ddx[1-x2]
Step 3.1.2
Differentiate.
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Step 3.1.2.1
By the Sum Rule, the derivative of 1-x2 with respect to x is ddx[1]+ddx[-x2].
ddx[1]+ddx[-x2]
Step 3.1.2.2
Since 1 is constant with respect to x, the derivative of 1 with respect to x is 0.
0+ddx[-x2]
0+ddx[-x2]
Step 3.1.3
Evaluate ddx[-x2].
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Step 3.1.3.1
Since -1 is constant with respect to x, the derivative of -x2 with respect to x is -ddx[x2].
0-ddx[x2]
Step 3.1.3.2
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=2.
0-(2x)
Step 3.1.3.3
Multiply 2 by -1.
0-2x
0-2x
Step 3.1.4
Subtract 2x from 0.
-2x
-2x
Step 3.2
Rewrite the problem using u and du.
arcsin(x)x-1u1-2du
arcsin(x)x-1u1-2du
Step 4
Simplify.
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Step 4.1
Move the negative in front of the fraction.
arcsin(x)x-1u(-12)du
Step 4.2
Multiply 1u by 12.
arcsin(x)x--1u2du
Step 4.3
Move 2 to the left of u.
arcsin(x)x--12udu
arcsin(x)x--12udu
Step 5
Since -1 is constant with respect to u, move -1 out of the integral.
arcsin(x)x--12udu
Step 6
Simplify.
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Step 6.1
Multiply -1 by -1.
arcsin(x)x+112udu
Step 6.2
Multiply 12udu by 1.
arcsin(x)x+12udu
arcsin(x)x+12udu
Step 7
Since 12 is constant with respect to u, move 12 out of the integral.
arcsin(x)x+121udu
Step 8
Apply basic rules of exponents.
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Step 8.1
Use axn=axn to rewrite u as u12.
arcsin(x)x+121u12du
Step 8.2
Move u12 out of the denominator by raising it to the -1 power.
arcsin(x)x+12(u12)-1du
Step 8.3
Multiply the exponents in (u12)-1.
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Step 8.3.1
Apply the power rule and multiply exponents, (am)n=amn.
arcsin(x)x+12u12-1du
Step 8.3.2
Combine 12 and -1.
arcsin(x)x+12u-12du
Step 8.3.3
Move the negative in front of the fraction.
arcsin(x)x+12u-12du
arcsin(x)x+12u-12du
arcsin(x)x+12u-12du
Step 9
By the Power Rule, the integral of u-12 with respect to u is 2u12.
arcsin(x)x+12(2u12+C)
Step 10
Rewrite arcsin(x)x+12(2u12+C) as arcsin(x)x+u12+C.
arcsin(x)x+u12+C
Step 11
Replace all occurrences of u with 1-x2.
arcsin(x)x+(1-x2)12+C
 [x2  12  π  xdx ]