Calculus Examples

$f (x) = \sin (x) \cos (x)$

Step 1

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 2

Set up the integral to solve.

$F (x) = \int \sin (x) \cos (x) d x$

Step 3

Let $u = \sin (x)$ . Then $d u = \cos (x) d x$ , so $\frac{1}{\cos (x)} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 3.1

Let $u = \sin (x)$ . Find $\frac{d u}{d x}$ .

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Step 3.1.1

Differentiate $\sin (x)$ .

$\frac{d}{d x} [\sin (x)]$

Step 3.1.2

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\cos (x)$

Step 3.2

Rewrite the problem using $u$ and $d u$ .

$\int u d u$

Step 4

By the Power Rule, the integral of $u$ with respect to $u$ is $\frac{1}{2} u^{2}$ .

$\frac{1}{2} u^{2} + C$

Step 5

Replace all occurrences of $u$ with $\sin (x)$ .

$\frac{1}{2} \sin^{2} (x) + C$

Step 6

The answer is the antiderivative of the function $f (x) = \sin (x) \cos (x)$ .

$F (x) =$ $\frac{1}{2} \sin^{2} (x) + C$