Calculus Examples

Find the Symmetry y = natural log of sin(x)
y=ln(sin(x))y=ln(sin(x))
Step 1
There are three types of symmetry:
1. X-Axis Symmetry
2. Y-Axis Symmetry
3. Origin Symmetry
Step 2
If (x,y)(x,y) exists on the graph, then the graph is symmetric about the:
1. X-Axis if (x,-y)(x,y) exists on the graph
2. Y-Axis if (-x,y)(x,y) exists on the graph
3. Origin if (-x,-y)(x,y) exists on the graph
Step 3
Check if the graph is symmetric about the xx-axis by plugging in -yy for yy.
-y=ln(sin(x))y=ln(sin(x))
Step 4
Multiply both sides by -11.
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Step 4.1
Multiply each term by -11.
--y=-ln(sin(x))y=ln(sin(x))
Step 4.2
Multiply --yy.
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Step 4.2.1
Multiply -11 by -11.
1y=-ln(sin(x))1y=ln(sin(x))
Step 4.2.2
Multiply yy by 11.
y=-ln(sin(x))y=ln(sin(x))
y=-ln(sin(x))y=ln(sin(x))
y=-ln(sin(x))y=ln(sin(x))
Step 5
Since the equation is identical to the original equation, it is symmetric to the x-axis.
Symmetric with respect to the x-axis
Step 6
Check if the graph is symmetric about the yy-axis by plugging in -xx for xx.
y=ln(sin(-x))y=ln(sin(x))
Step 7
Since sin(-x)sin(x) is an odd function, rewrite sin(-x)sin(x) as -sin(x)sin(x).
y=ln(-sin(x))y=ln(sin(x))
Step 8
Since the equation is not identical to the original equation, it is not symmetric to the y-axis.
Not symmetric to the y-axis
Step 9
Check if the graph is symmetric about the origin by plugging in -xx for xx and -yy for yy.
-y=ln(sin(-x))y=ln(sin(x))
Step 10
Since sin(-x)sin(x) is an odd function, rewrite sin(-x)sin(x) as -sin(x)sin(x).
-y=ln(-sin(x))y=ln(sin(x))
Step 11
Since the equation is not identical to the original equation, it is not symmetric to the origin.
Not symmetric to the origin
Step 12
Determine the symmetry.
Symmetric with respect to the x-axis
Step 13
 [x2  12  π  xdx ]  x2  12  π  xdx