Calculus Examples

$\sec (π) \tan (π)$

Step 1

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because secant is negative in the second quadrant.

$- \sec (0) \tan (π)$

Step 2

The exact value of $\sec (0)$ is $1$ .

$- 1 \cdot 1 \tan (π)$

Step 3

Multiply $- 1$ by $1$ .

$- 1 \tan (π)$

Step 4

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the second quadrant.

$- 1 (- \tan (0))$

Step 5

The exact value of $\tan (0)$ is $0$ .

$- 1 (- 0)$

Step 6

Multiply $- 1 (- 0)$ .

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Step 6.1

Multiply $- 1$ by $0$ .

$- 1 \cdot 0$

Step 6.2

Multiply $- 1$ by $0$ .

$0$