Calculus Examples

$2 \cos (θ) + \sqrt{2} = 0$

Step 1

Subtract $\sqrt{2}$ from both sides of the equation.

$2 \cos (θ) = - \sqrt{2}$

Step 2

Divide each term in $2 \cos (θ) = - \sqrt{2}$ by $2$ and simplify.

Tap for more steps...

Step 2.1

Divide each term in $2 \cos (θ) = - \sqrt{2}$ by $2$ .

$\frac{2 \cos (θ)}{2} = \frac{- \sqrt{2}}{2}$

Step 2.2

Simplify the left side.

Tap for more steps...

Step 2.2.1

Cancel the common factor of $2$ .

Tap for more steps...

Step 2.2.1.1

Cancel the common factor.

$\frac{2 \cos (θ)}{2} = \frac{- \sqrt{2}}{2}$

Step 2.2.1.2

Divide $\cos (θ)$ by $1$ .

$\cos (θ) = \frac{- \sqrt{2}}{2}$

Step 2.3

Simplify the right side.

Tap for more steps...

Step 2.3.1

Move the negative in front of the fraction.

$\cos (θ) = - \frac{\sqrt{2}}{2}$

Step 3

Take the inverse cosine of both sides of the equation to extract $θ$ from inside the cosine.

$θ = \arccos (- \frac{\sqrt{2}}{2})$

Step 4

Simplify the right side.

Tap for more steps...

Step 4.1

The exact value of $\arccos (- \frac{\sqrt{2}}{2})$ is $\frac{3 π}{4}$ .

$θ = \frac{3 π}{4}$

Step 5

The cosine function is negative in the second and third quadrants. To find the second solution, subtract the reference angle from $2 π$ to find the solution in the third quadrant.

$θ = 2 π - \frac{3 π}{4}$

Step 6

Simplify $2 π - \frac{3 π}{4}$ .

Tap for more steps...

Step 6.1

To write $2 π$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$θ = 2 π \cdot \frac{4}{4} - \frac{3 π}{4}$

Step 6.2

Combine fractions.

Tap for more steps...

Step 6.2.1

Combine $2 π$ and $\frac{4}{4}$ .

$θ = \frac{2 π \cdot 4}{4} - \frac{3 π}{4}$

Step 6.2.2

Combine the numerators over the common denominator.

$θ = \frac{2 π \cdot 4 - 3 π}{4}$

Step 6.3

Simplify the numerator.

Tap for more steps...

Step 6.3.1

Multiply $4$ by $2$ .

$θ = \frac{8 π - 3 π}{4}$

Step 6.3.2

Subtract $3 π$ from $8 π$ .

$θ = \frac{5 π}{4}$

Step 7

Find the period of $\cos (θ)$ .

Tap for more steps...

Step 7.1

The period of the function can be calculated using $\frac{2 π}{| b |}$ .

$\frac{2 π}{| b |}$

Step 7.2

Replace $b$ with $1$ in the formula for period.

$\frac{2 π}{| 1 |}$

Step 7.3

The absolute value is the distance between a number and zero. The distance between $0$ and $1$ is $1$ .

$\frac{2 π}{1}$

Step 7.4

Divide $2 π$ by $1$ .

$2 π$

Step 8

The period of the $\cos (θ)$ function is $2 π$ so values will repeat every $2 π$ radians in both directions.

$θ = \frac{3 π}{4} + 2 π n, \frac{5 π}{4} + 2 π n$ , for any integer $n$