Calculus Examples

$f (t) = \frac{e^{6 t} + e^{- 6 t}}{e^{4 t}}$

Step 1

Differentiate using the Quotient Rule which states that $\frac{d}{d t} [\frac{f (t)}{g (t)}]$ is $\frac{g (t) \frac{d}{d t} [f (t)] - f (t) \frac{d}{d t} [g (t)]}{{g (t)}^{2}}$ where $f (t) = e^{6 t} + e^{- 6 t}$ and $g (t) = e^{4 t}$ .

$\frac{e^{4 t} \frac{d}{d t} [e^{6 t} + e^{- 6 t}] - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{{(e^{4 t})}^{2}}$

Step 2

Differentiate using the Sum Rule.

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Step 2.1

Multiply the exponents in ${(e^{4 t})}^{2}$ .

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Step 2.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{e^{4 t} \frac{d}{d t} [e^{6 t} + e^{- 6 t}] - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{4 t \cdot 2}}$

Step 2.1.2

Multiply $2$ by $4$ .

$\frac{e^{4 t} \frac{d}{d t} [e^{6 t} + e^{- 6 t}] - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 2.2

By the Sum Rule, the derivative of $e^{6 t} + e^{- 6 t}$ with respect to $t$ is $\frac{d}{d t} [e^{6 t}] + \frac{d}{d t} [e^{- 6 t}]$ .

$\frac{e^{4 t} (\frac{d}{d t} [e^{6 t}] + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 3

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 6 t$ .

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Step 3.1

To apply the Chain Rule, set $u_{1}$ as $6 t$ .

$\frac{e^{4 t} (\frac{d}{d u_{1}} [e^{u_{1}}] \frac{d}{d t} [6 t] + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 3.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{1}} [a^{u_{1}}]$ is $a^{u_{1}} \ln (a)$ where $a$ = $e$ .

$\frac{e^{4 t} (e^{u_{1}} \frac{d}{d t} [6 t] + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 3.3

Replace all occurrences of $u_{1}$ with $6 t$ .

$\frac{e^{4 t} (e^{6 t} \frac{d}{d t} [6 t] + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 4

Differentiate.

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Step 4.1

Since $6$ is constant with respect to $t$ , the derivative of $6 t$ with respect to $t$ is $6 \frac{d}{d t} [t]$ .

$\frac{e^{4 t} (e^{6 t} (6 \frac{d}{d t} [t]) + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 4.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$\frac{e^{4 t} (e^{6 t} (6 \cdot 1) + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 4.3

Simplify the expression.

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Step 4.3.1

Multiply $6$ by $1$ .

$\frac{e^{4 t} (e^{6 t} \cdot 6 + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 4.3.2

Move $6$ to the left of $e^{6 t}$ .

$\frac{e^{4 t} (6 \cdot e^{6 t} + \frac{d}{d t} [e^{- 6 t}]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 5

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = - 6 t$ .

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Step 5.1

To apply the Chain Rule, set $u_{2}$ as $- 6 t$ .

$\frac{e^{4 t} (6 e^{6 t} + \frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d t} [- 6 t]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 5.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$\frac{e^{4 t} (6 e^{6 t} + e^{u_{2}} \frac{d}{d t} [- 6 t]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 5.3

Replace all occurrences of $u_{2}$ with $- 6 t$ .

$\frac{e^{4 t} (6 e^{6 t} + e^{- 6 t} \frac{d}{d t} [- 6 t]) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 6

Differentiate.

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Step 6.1

Since $- 6$ is constant with respect to $t$ , the derivative of $- 6 t$ with respect to $t$ is $- 6 \frac{d}{d t} [t]$ .

$\frac{e^{4 t} (6 e^{6 t} + e^{- 6 t} (- 6 \frac{d}{d t} [t])) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 6.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$\frac{e^{4 t} (6 e^{6 t} + e^{- 6 t} (- 6 \cdot 1)) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 6.3

Simplify the expression.

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Step 6.3.1

Multiply $- 6$ by $1$ .

$\frac{e^{4 t} (6 e^{6 t} + e^{- 6 t} \cdot - 6) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 6.3.2

Move $- 6$ to the left of $e^{- 6 t}$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 \cdot e^{- 6 t}) - (e^{6 t} + e^{- 6 t}) \frac{d}{d t} [e^{4 t}]}{e^{8 t}}$

Step 7

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = 4 t$ .

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Step 7.1

To apply the Chain Rule, set $u_{3}$ as $4 t$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - (e^{6 t} + e^{- 6 t}) (\frac{d}{d u_{3}} [e^{u_{3}}] \frac{d}{d t} [4 t])}{e^{8 t}}$

Step 7.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{3}} [a^{u_{3}}]$ is $a^{u_{3}} \ln (a)$ where $a$ = $e$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - (e^{6 t} + e^{- 6 t}) (e^{u_{3}} \frac{d}{d t} [4 t])}{e^{8 t}}$

Step 7.3

Replace all occurrences of $u_{3}$ with $4 t$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - (e^{6 t} + e^{- 6 t}) (e^{4 t} \frac{d}{d t} [4 t])}{e^{8 t}}$

Step 8

Differentiate.

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Step 8.1

Since $4$ is constant with respect to $t$ , the derivative of $4 t$ with respect to $t$ is $4 \frac{d}{d t} [t]$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - (e^{6 t} + e^{- 6 t}) (e^{4 t} (4 \frac{d}{d t} [t]))}{e^{8 t}}$

Step 8.2

Multiply $4$ by $- 1$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - 4 (e^{6 t} + e^{- 6 t}) (e^{4 t} (\frac{d}{d t} [t]))}{e^{8 t}}$

Step 8.3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - 4 (e^{6 t} + e^{- 6 t}) (e^{4 t} \cdot 1)}{e^{8 t}}$

Step 8.4

Multiply $e^{4 t}$ by $1$ .

$\frac{e^{4 t} (6 e^{6 t} - 6 e^{- 6 t}) - 4 (e^{6 t} + e^{- 6 t}) e^{4 t}}{e^{8 t}}$

Step 9

Simplify.

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Step 9.1

Apply the distributive property.

$\frac{e^{4 t} (6 e^{6 t}) + e^{4 t} (- 6 e^{- 6 t}) - 4 (e^{6 t} + e^{- 6 t}) e^{4 t}}{e^{8 t}}$

Step 9.2

Apply the distributive property.

$\frac{e^{4 t} (6 e^{6 t}) + e^{4 t} (- 6 e^{- 6 t}) + (- 4 e^{6 t} - 4 e^{- 6 t}) e^{4 t}}{e^{8 t}}$

Step 9.3

Apply the distributive property.

$\frac{e^{4 t} (6 e^{6 t}) + e^{4 t} (- 6 e^{- 6 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4

Simplify the numerator.

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Step 9.4.1

Simplify each term.

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Step 9.4.1.1

Rewrite using the commutative property of multiplication.

$\frac{6 e^{4 t} e^{6 t} + e^{4 t} (- 6 e^{- 6 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.2

Multiply $e^{4 t}$ by $e^{6 t}$ by adding the exponents.

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Step 9.4.1.2.1

Move $e^{6 t}$ .

$\frac{6 (e^{6 t} e^{4 t}) + e^{4 t} (- 6 e^{- 6 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{6 e^{6 t + 4 t} + e^{4 t} (- 6 e^{- 6 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.2.3

Add $6 t$ and $4 t$ .

$\frac{6 e^{10 t} + e^{4 t} (- 6 e^{- 6 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.3

Rewrite using the commutative property of multiplication.

$\frac{6 e^{10 t} - 6 e^{4 t} e^{- 6 t} - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.4

Multiply $e^{4 t}$ by $e^{- 6 t}$ by adding the exponents.

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Step 9.4.1.4.1

Move $e^{- 6 t}$ .

$\frac{6 e^{10 t} - 6 (e^{- 6 t} e^{4 t}) - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.4.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{6 e^{10 t} - 6 e^{- 6 t + 4 t} - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.4.3

Add $- 6 t$ and $4 t$ .

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{6 t} e^{4 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.5

Multiply $e^{6 t}$ by $e^{4 t}$ by adding the exponents.

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Step 9.4.1.5.1

Move $e^{4 t}$ .

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 (e^{4 t} e^{6 t}) - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.5.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{4 t + 6 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.5.3

Add $4 t$ and $6 t$ .

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{10 t} - 4 e^{- 6 t} e^{4 t}}{e^{8 t}}$

Step 9.4.1.6

Multiply $e^{- 6 t}$ by $e^{4 t}$ by adding the exponents.

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Step 9.4.1.6.1

Move $e^{4 t}$ .

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{10 t} - 4 (e^{4 t} e^{- 6 t})}{e^{8 t}}$

Step 9.4.1.6.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{10 t} - 4 e^{4 t - 6 t}}{e^{8 t}}$

Step 9.4.1.6.3

Subtract $6 t$ from $4 t$ .

$\frac{6 e^{10 t} - 6 e^{- 2 t} - 4 e^{10 t} - 4 e^{- 2 t}}{e^{8 t}}$

Step 9.4.2

Subtract $4 e^{10 t}$ from $6 e^{10 t}$ .

$\frac{2 e^{10 t} - 6 e^{- 2 t} - 4 e^{- 2 t}}{e^{8 t}}$

Step 9.4.3

Subtract $4 e^{- 2 t}$ from $- 6 e^{- 2 t}$ .

$\frac{2 e^{10 t} - 10 e^{- 2 t}}{e^{8 t}}$

Step 9.5

Factor $2$ out of $2 e^{10 t} - 10 e^{- 2 t}$ .

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Step 9.5.1

Factor $2$ out of $2 e^{10 t}$ .

$\frac{2 (e^{10 t}) - 10 e^{- 2 t}}{e^{8 t}}$

Step 9.5.2

Factor $2$ out of $- 10 e^{- 2 t}$ .

$\frac{2 (e^{10 t}) + 2 (- 5 e^{- 2 t})}{e^{8 t}}$

Step 9.5.3

Factor $2$ out of $2 (e^{10 t}) + 2 (- 5 e^{- 2 t})$ .

$\frac{2 (e^{10 t} - 5 e^{- 2 t})}{e^{8 t}}$