Calculus Examples

$f (x) = x^{4} {(x - 24)}^{2}$

Step 1

Find the first derivative of the function.

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Step 1.1

Rewrite ${(x - 24)}^{2}$ as $(x - 24) (x - 24)$ .

$\frac{d}{d x} [x^{4} ((x - 24) (x - 24))]$

Step 1.2

Expand $(x - 24) (x - 24)$ using the FOIL Method.

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Step 1.2.1

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x (x - 24) - 24 (x - 24))]$

Step 1.2.2

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x \cdot x + x \cdot - 24 - 24 (x - 24))]$

Step 1.2.3

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x \cdot x + x \cdot - 24 - 24 x - 24 \cdot - 24)]$

Step 1.3

Simplify and combine like terms.

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Step 1.3.1

Simplify each term.

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Step 1.3.1.1

Multiply $x$ by $x$ .

$\frac{d}{d x} [x^{4} (x^{2} + x \cdot - 24 - 24 x - 24 \cdot - 24)]$

Step 1.3.1.2

Move $- 24$ to the left of $x$ .

$\frac{d}{d x} [x^{4} (x^{2} - 24 \cdot x - 24 x - 24 \cdot - 24)]$

Step 1.3.1.3

Multiply $- 24$ by $- 24$ .

$\frac{d}{d x} [x^{4} (x^{2} - 24 x - 24 x + 576)]$

Step 1.3.2

Subtract $24 x$ from $- 24 x$ .

$\frac{d}{d x} [x^{4} (x^{2} - 48 x + 576)]$

Step 1.4

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = x^{4}$ and $g (x) = x^{2} - 48 x + 576$ .

$x^{4} \frac{d}{d x} [x^{2} - 48 x + 576] + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5

Differentiate.

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Step 1.5.1

By the Sum Rule, the derivative of $x^{2} - 48 x + 576$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]$ .

$x^{4} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$x^{4} (2 x + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.3

Since $- 48$ is constant with respect to $x$ , the derivative of $- 48 x$ with respect to $x$ is $- 48 \frac{d}{d x} [x]$ .

$x^{4} (2 x - 48 \frac{d}{d x} [x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x^{4} (2 x - 48 \cdot 1 + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.5

Multiply $- 48$ by $1$ .

$x^{4} (2 x - 48 + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.6

Since $576$ is constant with respect to $x$ , the derivative of $576$ with respect to $x$ is $0$ .

$x^{4} (2 x - 48 + 0) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.7

Add $2 x - 48$ and $0$ .

$x^{4} (2 x - 48) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 1.5.8

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$x^{4} (2 x - 48) + (x^{2} - 48 x + 576) (4 x^{3})$

Step 1.5.9

Move $4$ to the left of $x^{2} - 48 x + 576$ .

$x^{4} (2 x - 48) + 4 \cdot (x^{2} - 48 x + 576) x^{3}$

Step 1.6

Simplify.

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Step 1.6.1

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + 4 (x^{2} - 48 x + 576) x^{3}$

Step 1.6.2

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + (4 x^{2} + 4 (- 48 x) + 4 \cdot 576) x^{3}$

Step 1.6.3

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4

Combine terms.

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Step 1.6.4.1

Multiply $x^{4}$ by $x$ by adding the exponents.

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Step 1.6.4.1.1

Move $x$ .

$x \cdot x^{4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.1.2

Multiply $x$ by $x^{4}$ .

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Step 1.6.4.1.2.1

Raise $x$ to the power of $1$ .

$x^{1} x^{4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{1 + 4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.1.3

Add $1$ and $4$ .

$x^{5} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.2

Move $2$ to the left of $x^{5}$ .

$2 \cdot x^{5} + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.3

Move $- 48$ to the left of $x^{4}$ .

$2 x^{5} - 48 \cdot x^{4} + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.4

Multiply $x^{2}$ by $x^{3}$ by adding the exponents.

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Step 1.6.4.4.1

Move $x^{3}$ .

$2 x^{5} - 48 x^{4} + 4 (x^{3} x^{2}) + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.4.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x^{5} - 48 x^{4} + 4 x^{3 + 2} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.4.3

Add $3$ and $2$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.5

Multiply $- 48$ by $4$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x \cdot x^{3} + 4 \cdot 576 x^{3}$

Step 1.6.4.6

Multiply $x$ by $x^{3}$ by adding the exponents.

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Step 1.6.4.6.1

Move $x^{3}$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 (x^{3} x) + 4 \cdot 576 x^{3}$

Step 1.6.4.6.2

Multiply $x^{3}$ by $x$ .

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Step 1.6.4.6.2.1

Raise $x$ to the power of $1$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 (x^{3} x^{1}) + 4 \cdot 576 x^{3}$

Step 1.6.4.6.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{3 + 1} + 4 \cdot 576 x^{3}$

Step 1.6.4.6.3

Add $3$ and $1$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{4} + 4 \cdot 576 x^{3}$

Step 1.6.4.7

Multiply $4$ by $576$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{4} + 2304 x^{3}$

Step 1.6.4.8

Add $2 x^{5}$ and $4 x^{5}$ .

$6 x^{5} - 48 x^{4} - 192 x^{4} + 2304 x^{3}$

Step 1.6.4.9

Subtract $192 x^{4}$ from $- 48 x^{4}$ .

$6 x^{5} - 240 x^{4} + 2304 x^{3}$

Step 2

Find the second derivative of the function.

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Step 2.1

By the Sum Rule, the derivative of $6 x^{5} - 240 x^{4} + 2304 x^{3}$ with respect to $x$ is $\frac{d}{d x} [6 x^{5}] + \frac{d}{d x} [- 240 x^{4}] + \frac{d}{d x} [2304 x^{3}]$ .

$f'' (x) = \frac{d}{d x} (6 x^{5}) + \frac{d}{d x} (- 240 x^{4}) + \frac{d}{d x} (2304 x^{3})$

Step 2.2

Evaluate $\frac{d}{d x} [6 x^{5}]$ .

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Step 2.2.1

Since $6$ is constant with respect to $x$ , the derivative of $6 x^{5}$ with respect to $x$ is $6 \frac{d}{d x} [x^{5}]$ .

$f'' (x) = 6 \frac{d}{d x} (x^{5}) + \frac{d}{d x} (- 240 x^{4}) + \frac{d}{d x} (2304 x^{3})$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 5$ .

$f'' (x) = 6 (5 x^{4}) + \frac{d}{d x} (- 240 x^{4}) + \frac{d}{d x} (2304 x^{3})$

Step 2.2.3

Multiply $5$ by $6$ .

$f'' (x) = 30 x^{4} + \frac{d}{d x} (- 240 x^{4}) + \frac{d}{d x} (2304 x^{3})$

Step 2.3

Evaluate $\frac{d}{d x} [- 240 x^{4}]$ .

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Step 2.3.1

Since $- 240$ is constant with respect to $x$ , the derivative of $- 240 x^{4}$ with respect to $x$ is $- 240 \frac{d}{d x} [x^{4}]$ .

$f'' (x) = 30 x^{4} - 240 \frac{d}{d x} x^{4} + \frac{d}{d x} (2304 x^{3})$

Step 2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$f'' (x) = 30 x^{4} - 240 (4 x^{3}) + \frac{d}{d x} (2304 x^{3})$

Step 2.3.3

Multiply $4$ by $- 240$ .

$f'' (x) = 30 x^{4} - 960 x^{3} + \frac{d}{d x} (2304 x^{3})$

Step 2.4

Evaluate $\frac{d}{d x} [2304 x^{3}]$ .

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Step 2.4.1

Since $2304$ is constant with respect to $x$ , the derivative of $2304 x^{3}$ with respect to $x$ is $2304 \frac{d}{d x} [x^{3}]$ .

$f'' (x) = 30 x^{4} - 960 x^{3} + 2304 \frac{d}{d x} (x^{3})$

Step 2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$f'' (x) = 30 x^{4} - 960 x^{3} + 2304 (3 x^{2})$

Step 2.4.3

Multiply $3$ by $2304$ .

$f'' (x) = 30 x^{4} - 960 x^{3} + 6912 x^{2}$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$6 x^{5} - 240 x^{4} + 2304 x^{3} = 0$

Step 4

Find the first derivative.

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Step 4.1

Find the first derivative.

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Step 4.1.1

Rewrite ${(x - 24)}^{2}$ as $(x - 24) (x - 24)$ .

$\frac{d}{d x} [x^{4} ((x - 24) (x - 24))]$

Step 4.1.2

Expand $(x - 24) (x - 24)$ using the FOIL Method.

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Step 4.1.2.1

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x (x - 24) - 24 (x - 24))]$

Step 4.1.2.2

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x \cdot x + x \cdot - 24 - 24 (x - 24))]$

Step 4.1.2.3

Apply the distributive property.

$\frac{d}{d x} [x^{4} (x \cdot x + x \cdot - 24 - 24 x - 24 \cdot - 24)]$

Step 4.1.3

Simplify and combine like terms.

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Step 4.1.3.1

Simplify each term.

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Step 4.1.3.1.1

Multiply $x$ by $x$ .

$\frac{d}{d x} [x^{4} (x^{2} + x \cdot - 24 - 24 x - 24 \cdot - 24)]$

Step 4.1.3.1.2

Move $- 24$ to the left of $x$ .

$\frac{d}{d x} [x^{4} (x^{2} - 24 \cdot x - 24 x - 24 \cdot - 24)]$

Step 4.1.3.1.3

Multiply $- 24$ by $- 24$ .

$\frac{d}{d x} [x^{4} (x^{2} - 24 x - 24 x + 576)]$

Step 4.1.3.2

Subtract $24 x$ from $- 24 x$ .

$\frac{d}{d x} [x^{4} (x^{2} - 48 x + 576)]$

Step 4.1.4

$x^{4} \frac{d}{d x} [x^{2} - 48 x + 576] + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5

Differentiate.

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Step 4.1.5.1

By the Sum Rule, the derivative of $x^{2} - 48 x + 576$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]$ .

$x^{4} (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$x^{4} (2 x + \frac{d}{d x} [- 48 x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.3

Since $- 48$ is constant with respect to $x$ , the derivative of $- 48 x$ with respect to $x$ is $- 48 \frac{d}{d x} [x]$ .

$x^{4} (2 x - 48 \frac{d}{d x} [x] + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$x^{4} (2 x - 48 \cdot 1 + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.5

Multiply $- 48$ by $1$ .

$x^{4} (2 x - 48 + \frac{d}{d x} [576]) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.6

Since $576$ is constant with respect to $x$ , the derivative of $576$ with respect to $x$ is $0$ .

$x^{4} (2 x - 48 + 0) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.7

Add $2 x - 48$ and $0$ .

$x^{4} (2 x - 48) + (x^{2} - 48 x + 576) \frac{d}{d x} [x^{4}]$

Step 4.1.5.8

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 4$ .

$x^{4} (2 x - 48) + (x^{2} - 48 x + 576) (4 x^{3})$

Step 4.1.5.9

Move $4$ to the left of $x^{2} - 48 x + 576$ .

$x^{4} (2 x - 48) + 4 \cdot (x^{2} - 48 x + 576) x^{3}$

Step 4.1.6

Simplify.

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Step 4.1.6.1

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + 4 (x^{2} - 48 x + 576) x^{3}$

Step 4.1.6.2

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + (4 x^{2} + 4 (- 48 x) + 4 \cdot 576) x^{3}$

Step 4.1.6.3

Apply the distributive property.

$x^{4} (2 x) + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4

Combine terms.

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Step 4.1.6.4.1

Multiply $x^{4}$ by $x$ by adding the exponents.

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Step 4.1.6.4.1.1

Move $x$ .

$x \cdot x^{4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.1.2

Multiply $x$ by $x^{4}$ .

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Step 4.1.6.4.1.2.1

Raise $x$ to the power of $1$ .

$x^{1} x^{4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x^{1 + 4} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.1.3

Add $1$ and $4$ .

$x^{5} \cdot 2 + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.2

Move $2$ to the left of $x^{5}$ .

$2 \cdot x^{5} + x^{4} \cdot - 48 + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.3

Move $- 48$ to the left of $x^{4}$ .

$2 x^{5} - 48 \cdot x^{4} + 4 x^{2} x^{3} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.4

Multiply $x^{2}$ by $x^{3}$ by adding the exponents.

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Step 4.1.6.4.4.1

Move $x^{3}$ .

$2 x^{5} - 48 x^{4} + 4 (x^{3} x^{2}) + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.4.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x^{5} - 48 x^{4} + 4 x^{3 + 2} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.4.3

Add $3$ and $2$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} + 4 (- 48 x) x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.5

Multiply $- 48$ by $4$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x \cdot x^{3} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.6

Multiply $x$ by $x^{3}$ by adding the exponents.

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Step 4.1.6.4.6.1

Move $x^{3}$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 (x^{3} x) + 4 \cdot 576 x^{3}$

Step 4.1.6.4.6.2

Multiply $x^{3}$ by $x$ .

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Step 4.1.6.4.6.2.1

Raise $x$ to the power of $1$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 (x^{3} x^{1}) + 4 \cdot 576 x^{3}$

Step 4.1.6.4.6.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{3 + 1} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.6.3

Add $3$ and $1$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{4} + 4 \cdot 576 x^{3}$

Step 4.1.6.4.7

Multiply $4$ by $576$ .

$2 x^{5} - 48 x^{4} + 4 x^{5} - 192 x^{4} + 2304 x^{3}$

Step 4.1.6.4.8

Add $2 x^{5}$ and $4 x^{5}$ .

$6 x^{5} - 48 x^{4} - 192 x^{4} + 2304 x^{3}$

Step 4.1.6.4.9

Subtract $192 x^{4}$ from $- 48 x^{4}$ .

$f' (x) = 6 x^{5} - 240 x^{4} + 2304 x^{3}$

Step 4.2

The first derivative of $f (x)$ with respect to $x$ is $6 x^{5} - 240 x^{4} + 2304 x^{3}$ .

$6 x^{5} - 240 x^{4} + 2304 x^{3}$

Step 5

Set the first derivative equal to $0$ then solve the equation $6 x^{5} - 240 x^{4} + 2304 x^{3} = 0$ .

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Step 5.1

Set the first derivative equal to $0$ .

$6 x^{5} - 240 x^{4} + 2304 x^{3} = 0$

Step 5.2

Factor the left side of the equation.

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Step 5.2.1

Factor $6 x^{3}$ out of $6 x^{5} - 240 x^{4} + 2304 x^{3}$ .

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Step 5.2.1.1

Factor $6 x^{3}$ out of $6 x^{5}$ .

$6 x^{3} (x^{2}) - 240 x^{4} + 2304 x^{3} = 0$

Step 5.2.1.2

Factor $6 x^{3}$ out of $- 240 x^{4}$ .

$6 x^{3} (x^{2}) + 6 x^{3} (- 40 x) + 2304 x^{3} = 0$

Step 5.2.1.3

Factor $6 x^{3}$ out of $2304 x^{3}$ .

$6 x^{3} (x^{2}) + 6 x^{3} (- 40 x) + 6 x^{3} (384) = 0$

Step 5.2.1.4

Factor $6 x^{3}$ out of $6 x^{3} (x^{2}) + 6 x^{3} (- 40 x)$ .

$6 x^{3} (x^{2} - 40 x) + 6 x^{3} (384) = 0$

Step 5.2.1.5

Factor $6 x^{3}$ out of $6 x^{3} (x^{2} - 40 x) + 6 x^{3} (384)$ .

$6 x^{3} (x^{2} - 40 x + 384) = 0$

Step 5.2.2

Factor.

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Step 5.2.2.1

Factor $x^{2} - 40 x + 384$ using the AC method.

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Step 5.2.2.1.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $384$ and whose sum is $- 40$ .

$- 24, - 16$

Step 5.2.2.1.2

Write the factored form using these integers.

$6 x^{3} ((x - 24) (x - 16)) = 0$

Step 5.2.2.2

Remove unnecessary parentheses.

$6 x^{3} (x - 24) (x - 16) = 0$

Step 5.3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x^{3} = 0$

$x - 24 = 0$

$x - 16 = 0$

Step 5.4

Set $x^{3}$ equal to $0$ and solve for $x$ .

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Step 5.4.1

Set $x^{3}$ equal to $0$ .

$x^{3} = 0$

Step 5.4.2

Solve $x^{3} = 0$ for $x$ .

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Step 5.4.2.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \sqrt[3]{0}$

Step 5.4.2.2

Simplify $\sqrt[3]{0}$ .

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Step 5.4.2.2.1

Rewrite $0$ as $0^{3}$ .

$x = \sqrt[3]{0^{3}}$

Step 5.4.2.2.2

Pull terms out from under the radical, assuming real numbers.

$x = 0$

Step 5.5

Set $x - 24$ equal to $0$ and solve for $x$ .

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Step 5.5.1

Set $x - 24$ equal to $0$ .

$x - 24 = 0$

Step 5.5.2

Add $24$ to both sides of the equation.

$x = 24$

Step 5.6

Set $x - 16$ equal to $0$ and solve for $x$ .

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Step 5.6.1

Set $x - 16$ equal to $0$ .

$x - 16 = 0$

Step 5.6.2

Add $16$ to both sides of the equation.

$x = 16$

Step 5.7

The final solution is all the values that make $6 x^{3} (x - 24) (x - 16) = 0$ true.

$x = 0, 24, 16$

Step 6

Find the values where the derivative is undefined.

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Step 6.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 7

Critical points to evaluate.

$x = 0, 24, 16$

Step 8

Evaluate the second derivative at $x = 0$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$30 {(0)}^{4} - 960 {(0)}^{3} + 6912 {(0)}^{2}$

Step 9

Evaluate the second derivative.

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Step 9.1

Simplify each term.

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Step 9.1.1

Raising $0$ to any positive power yields $0$ .

$30 \cdot 0 - 960 {(0)}^{3} + 6912 {(0)}^{2}$

Step 9.1.2

Multiply $30$ by $0$ .

$0 - 960 {(0)}^{3} + 6912 {(0)}^{2}$

Step 9.1.3

Raising $0$ to any positive power yields $0$ .

$0 - 960 \cdot 0 + 6912 {(0)}^{2}$

Step 9.1.4

Multiply $- 960$ by $0$ .

$0 + 0 + 6912 {(0)}^{2}$

Step 9.1.5

Raising $0$ to any positive power yields $0$ .

$0 + 0 + 6912 \cdot 0$

Step 9.1.6

Multiply $6912$ by $0$ .

$0 + 0 + 0$

Step 9.2

Simplify by adding numbers.

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Step 9.2.1

Add $0$ and $0$ .

$0 + 0$

Step 9.2.2

Add $0$ and $0$ .

$0$

Step 10

Since there is at least one point with $0$ or undefined second derivative, apply the first derivative test.

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Step 10.1

Split $(- \infty, \infty)$ into separate intervals around the $x$ values that make the first derivative $0$ or undefined.

$(- \infty, 0) \cup (0, 16) \cup (16, 24) \cup (24, \infty)$

Step 10.2

Substitute any number, such as $- 2$ , from the interval $(- \infty, 0)$ in the first derivative $6 x^{5} - 240 x^{4} + 2304 x^{3}$ to check if the result is negative or positive.

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Step 10.2.1

Replace the variable $x$ with $- 2$ in the expression.

$f' (- 2) = 6 {(- 2)}^{5} - 240 {(- 2)}^{4} + 2304 {(- 2)}^{3}$

Step 10.2.2

Simplify the result.

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Step 10.2.2.1

Simplify each term.

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Step 10.2.2.1.1

Raise $- 2$ to the power of $5$ .

$f' (- 2) = 6 \cdot - 32 - 240 {(- 2)}^{4} + 2304 {(- 2)}^{3}$

Step 10.2.2.1.2

Multiply $6$ by $- 32$ .

$f' (- 2) = - 192 - 240 {(- 2)}^{4} + 2304 {(- 2)}^{3}$

Step 10.2.2.1.3

Raise $- 2$ to the power of $4$ .

$f' (- 2) = - 192 - 240 \cdot 16 + 2304 {(- 2)}^{3}$

Step 10.2.2.1.4

Multiply $- 240$ by $16$ .

$f' (- 2) = - 192 - 3840 + 2304 {(- 2)}^{3}$

Step 10.2.2.1.5

Raise $- 2$ to the power of $3$ .

$f' (- 2) = - 192 - 3840 + 2304 \cdot - 8$

Step 10.2.2.1.6

Multiply $2304$ by $- 8$ .

$f' (- 2) = - 192 - 3840 - 18432$

Step 10.2.2.2

Simplify by subtracting numbers.

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Step 10.2.2.2.1

Subtract $3840$ from $- 192$ .

$f' (- 2) = - 4032 - 18432$

Step 10.2.2.2.2

Subtract $18432$ from $- 4032$ .

$f' (- 2) = - 22464$

Step 10.2.2.3

The final answer is $- 22464$ .

$- 22464$

Step 10.3

Substitute any number, such as $2$ , from the interval $(0, 16)$ in the first derivative $6 x^{5} - 240 x^{4} + 2304 x^{3}$ to check if the result is negative or positive.

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Step 10.3.1

Replace the variable $x$ with $2$ in the expression.

$f' (2) = 6 {(2)}^{5} - 240 {(2)}^{4} + 2304 {(2)}^{3}$

Step 10.3.2

Simplify the result.

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Step 10.3.2.1

Simplify each term.

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Step 10.3.2.1.1

Raise $2$ to the power of $5$ .

$f' (2) = 6 \cdot 32 - 240 {(2)}^{4} + 2304 {(2)}^{3}$

Step 10.3.2.1.2

Multiply $6$ by $32$ .

$f' (2) = 192 - 240 {(2)}^{4} + 2304 {(2)}^{3}$

Step 10.3.2.1.3

Raise $2$ to the power of $4$ .

$f' (2) = 192 - 240 \cdot 16 + 2304 {(2)}^{3}$

Step 10.3.2.1.4

Multiply $- 240$ by $16$ .

$f' (2) = 192 - 3840 + 2304 {(2)}^{3}$

Step 10.3.2.1.5

Raise $2$ to the power of $3$ .

$f' (2) = 192 - 3840 + 2304 \cdot 8$

Step 10.3.2.1.6

Multiply $2304$ by $8$ .

$f' (2) = 192 - 3840 + 18432$

Step 10.3.2.2

Simplify by adding and subtracting.

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Step 10.3.2.2.1

Subtract $3840$ from $192$ .

$f' (2) = - 3648 + 18432$

Step 10.3.2.2.2

Add $- 3648$ and $18432$ .

$f' (2) = 14784$

Step 10.3.2.3

The final answer is $14784$ .

$14784$

Step 10.4

Substitute any number, such as $20$ , from the interval $(16, 24)$ in the first derivative $6 x^{5} - 240 x^{4} + 2304 x^{3}$ to check if the result is negative or positive.

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Step 10.4.1

Replace the variable $x$ with $20$ in the expression.

$f' (20) = 6 {(20)}^{5} - 240 {(20)}^{4} + 2304 {(20)}^{3}$

Step 10.4.2

Simplify the result.

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Step 10.4.2.1

Simplify each term.

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Step 10.4.2.1.1

Raise $20$ to the power of $5$ .

$f' (20) = 6 \cdot 3200000 - 240 {(20)}^{4} + 2304 {(20)}^{3}$

Step 10.4.2.1.2

Multiply $6$ by $3200000$ .

$f' (20) = 19200000 - 240 {(20)}^{4} + 2304 {(20)}^{3}$

Step 10.4.2.1.3

Raise $20$ to the power of $4$ .

$f' (20) = 19200000 - 240 \cdot 160000 + 2304 {(20)}^{3}$

Step 10.4.2.1.4

Multiply $- 240$ by $160000$ .

$f' (20) = 19200000 - 38400000 + 2304 {(20)}^{3}$

Step 10.4.2.1.5

Raise $20$ to the power of $3$ .

$f' (20) = 19200000 - 38400000 + 2304 \cdot 8000$

Step 10.4.2.1.6

Multiply $2304$ by $8000$ .

$f' (20) = 19200000 - 38400000 + 18432000$

Step 10.4.2.2

Simplify by adding and subtracting.

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Step 10.4.2.2.1

Subtract $38400000$ from $19200000$ .

$f' (20) = - 19200000 + 18432000$

Step 10.4.2.2.2

Add $- 19200000$ and $18432000$ .

$f' (20) = - 768000$

Step 10.4.2.3

The final answer is $- 768000$ .

$- 768000$

Step 10.5

Substitute any number, such as $26$ , from the interval $(24, \infty)$ in the first derivative $6 x^{5} - 240 x^{4} + 2304 x^{3}$ to check if the result is negative or positive.

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Step 10.5.1

Replace the variable $x$ with $26$ in the expression.

$f' (26) = 6 {(26)}^{5} - 240 {(26)}^{4} + 2304 {(26)}^{3}$

Step 10.5.2

Simplify the result.

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Step 10.5.2.1

Simplify each term.

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Step 10.5.2.1.1

Raise $26$ to the power of $5$ .

$f' (26) = 6 \cdot 11881376 - 240 {(26)}^{4} + 2304 {(26)}^{3}$

Step 10.5.2.1.2

Multiply $6$ by $11881376$ .

$f' (26) = 71288256 - 240 {(26)}^{4} + 2304 {(26)}^{3}$

Step 10.5.2.1.3

Raise $26$ to the power of $4$ .

$f' (26) = 71288256 - 240 \cdot 456976 + 2304 {(26)}^{3}$

Step 10.5.2.1.4

Multiply $- 240$ by $456976$ .

$f' (26) = 71288256 - 109674240 + 2304 {(26)}^{3}$

Step 10.5.2.1.5

Raise $26$ to the power of $3$ .

$f' (26) = 71288256 - 109674240 + 2304 \cdot 17576$

Step 10.5.2.1.6

Multiply $2304$ by $17576$ .

$f' (26) = 71288256 - 109674240 + 40495104$

Step 10.5.2.2

Simplify by adding and subtracting.

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Step 10.5.2.2.1

Subtract $109674240$ from $71288256$ .

$f' (26) = - 38385984 + 40495104$

Step 10.5.2.2.2

Add $- 38385984$ and $40495104$ .

$f' (26) = 2109120$

Step 10.5.2.3

The final answer is $2109120$ .

$2109120$

Step 10.6

Since the first derivative changed signs from negative to positive around $x = 0$ , then $x = 0$ is a local minimum.

$x = 0$ is a local minimum

Step 10.7

Since the first derivative changed signs from positive to negative around $x = 16$ , then $x = 16$ is a local maximum.

$x = 16$ is a local maximum

Step 10.8

Since the first derivative changed signs from negative to positive around $x = 24$ , then $x = 24$ is a local minimum.

$x = 24$ is a local minimum

Step 10.9

These are the local extrema for $f (x) = x^{4} {(x - 24)}^{2}$ .

$x = 0$ is a local minimum

$x = 16$ is a local maximum

$x = 24$ is a local minimum

$x = 0$ is a local minimum

$x = 16$ is a local maximum

$x = 24$ is a local minimum

Step 11