Calculus Examples

$h (t) = 2 t^{3} - 25.9 t^{2} + 1110$

Step 1

Find the first derivative of the function.

Tap for more steps...

Step 1.1

By the Sum Rule, the derivative of $2 t^{3} - 25.9 t^{2} + 1110$ with respect to $t$ is $\frac{d}{d t} [2 t^{3}] + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$ .

$\frac{d}{d t} [2 t^{3}] + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$

Step 1.2

Evaluate $\frac{d}{d t} [2 t^{3}]$ .

Tap for more steps...

Step 1.2.1

Since $2$ is constant with respect to $t$ , the derivative of $2 t^{3}$ with respect to $t$ is $2 \frac{d}{d t} [t^{3}]$ .

$2 \frac{d}{d t} [t^{3}] + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$

Step 1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 3$ .

$2 (3 t^{2}) + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$

Step 1.2.3

Multiply $3$ by $2$ .

$6 t^{2} + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$

Step 1.3

Evaluate $\frac{d}{d t} [- 25.9 t^{2}]$ .

Tap for more steps...

Step 1.3.1

Since $- 25.9$ is constant with respect to $t$ , the derivative of $- 25.9 t^{2}$ with respect to $t$ is $- 25.9 \frac{d}{d t} [t^{2}]$ .

$6 t^{2} - 25.9 \frac{d}{d t} [t^{2}] + \frac{d}{d t} [1110]$

Step 1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 2$ .

$6 t^{2} - 25.9 (2 t) + \frac{d}{d t} [1110]$

Step 1.3.3

Multiply $2$ by $- 25.9$ .

$6 t^{2} - 51.8 t + \frac{d}{d t} [1110]$

Step 1.4

Differentiate using the Constant Rule.

Tap for more steps...

Step 1.4.1

Since $1110$ is constant with respect to $t$ , the derivative of $1110$ with respect to $t$ is $0$ .

$6 t^{2} - 51.8 t + 0$

Step 1.4.2

Add $6 t^{2} - 51.8 t$ and $0$ .

$6 t^{2} - 51.8 t$

Step 2

Find the second derivative of the function.

Tap for more steps...

Step 2.1

By the Sum Rule, the derivative of $6 t^{2} - 51.8 t$ with respect to $t$ is $\frac{d}{d t} [6 t^{2}] + \frac{d}{d t} [- 51.8 t]$ .

$h'' (t) = \frac{d}{d t} (6 t^{2}) + \frac{d}{d t} (- 51.8 t)$

Step 2.2

Evaluate $\frac{d}{d t} [6 t^{2}]$ .

Tap for more steps...

Step 2.2.1

Since $6$ is constant with respect to $t$ , the derivative of $6 t^{2}$ with respect to $t$ is $6 \frac{d}{d t} [t^{2}]$ .

$h'' (t) = 6 \frac{d}{d t} (t^{2}) + \frac{d}{d t} (- 51.8 t)$

Step 2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 2$ .

$h'' (t) = 6 (2 t) + \frac{d}{d t} (- 51.8 t)$

Step 2.2.3

Multiply $2$ by $6$ .

$h'' (t) = 12 t + \frac{d}{d t} (- 51.8 t)$

Step 2.3

Evaluate $\frac{d}{d t} [- 51.8 t]$ .

Tap for more steps...

Step 2.3.1

Since $- 51.8$ is constant with respect to $t$ , the derivative of $- 51.8 t$ with respect to $t$ is $- 51.8 \frac{d}{d t} [t]$ .

$h'' (t) = 12 t - 51.8 \frac{d}{d t} t$

Step 2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$h'' (t) = 12 t - 51.8 \cdot 1$

Step 2.3.3

Multiply $- 51.8$ by $1$ .

$h'' (t) = 12 t - 51.8$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$6 t^{2} - 51.8 t = 0$

Step 4

Find the first derivative.

Tap for more steps...

Step 4.1

Find the first derivative.

Tap for more steps...

Step 4.1.1

By the Sum Rule, the derivative of $2 t^{3} - 25.9 t^{2} + 1110$ with respect to $t$ is $\frac{d}{d t} [2 t^{3}] + \frac{d}{d t} [- 25.9 t^{2}] + \frac{d}{d t} [1110]$ .

$f' (t) = \frac{d}{d t} (2 t^{3}) + \frac{d}{d t} (- 25.9 t^{2}) + \frac{d}{d t} (1110)$

Step 4.1.2

Evaluate $\frac{d}{d t} [2 t^{3}]$ .

Tap for more steps...

Step 4.1.2.1

Since $2$ is constant with respect to $t$ , the derivative of $2 t^{3}$ with respect to $t$ is $2 \frac{d}{d t} [t^{3}]$ .

$f' (t) = 2 \frac{d}{d t} (t^{3}) + \frac{d}{d t} (- 25.9 t^{2}) + \frac{d}{d t} (1110)$

Step 4.1.2.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 3$ .

$f' (t) = 2 (3 t^{2}) + \frac{d}{d t} (- 25.9 t^{2}) + \frac{d}{d t} (1110)$

Step 4.1.2.3

Multiply $3$ by $2$ .

$f' (t) = 6 t^{2} + \frac{d}{d t} (- 25.9 t^{2}) + \frac{d}{d t} (1110)$

Step 4.1.3

Evaluate $\frac{d}{d t} [- 25.9 t^{2}]$ .

Tap for more steps...

Step 4.1.3.1

Since $- 25.9$ is constant with respect to $t$ , the derivative of $- 25.9 t^{2}$ with respect to $t$ is $- 25.9 \frac{d}{d t} [t^{2}]$ .

$f' (t) = 6 t^{2} - 25.9 \frac{d}{d t} t^{2} + \frac{d}{d t} (1110)$

Step 4.1.3.2

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 2$ .

$f' (t) = 6 t^{2} - 25.9 (2 t) + \frac{d}{d t} (1110)$

Step 4.1.3.3

Multiply $2$ by $- 25.9$ .

$f' (t) = 6 t^{2} - 51.8 t + \frac{d}{d t} (1110)$

Step 4.1.4

Differentiate using the Constant Rule.

Tap for more steps...

Step 4.1.4.1

Since $1110$ is constant with respect to $t$ , the derivative of $1110$ with respect to $t$ is $0$ .

$f' (t) = 6 t^{2} - 51.8 t + 0$

Step 4.1.4.2

Add $6 t^{2} - 51.8 t$ and $0$ .

$f' (t) = 6 t^{2} - 51.8 t$

Step 4.2

The first derivative of $h (t)$ with respect to $t$ is $6 t^{2} - 51.8 t$ .

$6 t^{2} - 51.8 t$

Step 5

Set the first derivative equal to $0$ then solve the equation $6 t^{2} - 51.8 t = 0$ .

Tap for more steps...

Step 5.1

Set the first derivative equal to $0$ .

$6 t^{2} - 51.8 t = 0$

Step 5.2

Factor $0.2 t$ out of $6 t^{2} - 51.8 t$ .

Tap for more steps...

Step 5.2.1

Factor $0.2 t$ out of $6 t^{2}$ .

$0.2 t (30 t) - 51.8 t = 0$

Step 5.2.2

Factor $0.2 t$ out of $- 51.8 t$ .

$0.2 t (30 t) + 0.2 t (- 259) = 0$

Step 5.2.3

Factor $0.2 t$ out of $0.2 t (30 t) + 0.2 t (- 259)$ .

$0.2 t (30 t - 259) = 0$

Step 5.3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$t = 0$

$30 t - 259 = 0$

Step 5.4

Set $t$ equal to $0$ .

$t = 0$

Step 5.5

Set $30 t - 259$ equal to $0$ and solve for $t$ .

Tap for more steps...

Step 5.5.1

Set $30 t - 259$ equal to $0$ .

$30 t - 259 = 0$

Step 5.5.2

Solve $30 t - 259 = 0$ for $t$ .

Tap for more steps...

Step 5.5.2.1

Add $259$ to both sides of the equation.

$30 t = 259$

Step 5.5.2.2

Divide each term in $30 t = 259$ by $30$ and simplify.

Tap for more steps...

Step 5.5.2.2.1

Divide each term in $30 t = 259$ by $30$ .

$\frac{30 t}{30} = \frac{259}{30}$

Step 5.5.2.2.2

Simplify the left side.

Tap for more steps...

Step 5.5.2.2.2.1

Cancel the common factor of $30$ .

Tap for more steps...

Step 5.5.2.2.2.1.1

Cancel the common factor.

$\frac{30 t}{30} = \frac{259}{30}$

Step 5.5.2.2.2.1.2

Divide $t$ by $1$ .

$t = \frac{259}{30}$

Step 5.6

The final solution is all the values that make $0.2 t (30 t - 259) = 0$ true.

$t = 0, \frac{259}{30}$

Step 6

Find the values where the derivative is undefined.

Tap for more steps...

Step 6.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 7

Critical points to evaluate.

$t = 0, \frac{259}{30}$

Step 8

Evaluate the second derivative at $t = 0$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$12 (0) - 51.8$

Step 9

Evaluate the second derivative.

Tap for more steps...

Step 9.1

Multiply $12$ by $0$ .

$0 - 51.8$

Step 9.2

Subtract $51.8$ from $0$ .

$- 51.8$

Step 10

$t = 0$ is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.

$t = 0$ is a local maximum

Step 11

Find the y-value when $t = 0$ .

Tap for more steps...

Step 11.1

Replace the variable $t$ with $0$ in the expression.

$h (0) = 2 {(0)}^{3} - 25.9 {(0)}^{2} + 1110$

Step 11.2

Simplify the result.

Tap for more steps...

Step 11.2.1

Simplify each term.

Tap for more steps...

Step 11.2.1.1

Raising $0$ to any positive power yields $0$ .

$h (0) = 2 \cdot 0 - 25.9 {(0)}^{2} + 1110$

Step 11.2.1.2

Multiply $2$ by $0$ .

$h (0) = 0 - 25.9 {(0)}^{2} + 1110$

Step 11.2.1.3

Raising $0$ to any positive power yields $0$ .

$h (0) = 0 - 25.9 \cdot 0 + 1110$

Step 11.2.1.4

Multiply $- 25.9$ by $0$ .

$h (0) = 0 + 0 + 1110$

Step 11.2.2

Simplify by adding numbers.

Tap for more steps...

Step 11.2.2.1

Add $0$ and $0$ .

$h (0) = 0 + 1110$

Step 11.2.2.2

Add $0$ and $1110$ .

$h (0) = 1110$

Step 11.2.3

The final answer is $1110$ .

$y = 1110$

Step 12

Evaluate the second derivative at $t = \frac{259}{30}$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$12 (\frac{259}{30}) - 51.8$

Step 13

Evaluate the second derivative.

Tap for more steps...

Step 13.1

Simplify each term.

Tap for more steps...

Step 13.1.1

Cancel the common factor of $6$ .

Tap for more steps...

Step 13.1.1.1

Factor $6$ out of $12$ .

$6 (2) \frac{259}{30} - 51.8$

Step 13.1.1.2

Factor $6$ out of $30$ .

$6 \cdot 2 \frac{259}{6 \cdot 5} - 51.8$

Step 13.1.1.3

Cancel the common factor.

$6 \cdot 2 \frac{259}{6 \cdot 5} - 51.8$

Step 13.1.1.4

Rewrite the expression.

$2 (\frac{259}{5}) - 51.8$

Step 13.1.2

Combine $2$ and $\frac{259}{5}$ .

$\frac{2 \cdot 259}{5} - 51.8$

Step 13.1.3

Multiply $2$ by $259$ .

$\frac{518}{5} - 51.8$

Step 13.2

To write $- 51.8$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$\frac{518}{5} - 51.8 \cdot \frac{5}{5}$

Step 13.3

Combine $- 51.8$ and $\frac{5}{5}$ .

$\frac{518}{5} + \frac{- 51.8 \cdot 5}{5}$

Step 13.4

Combine the numerators over the common denominator.

$\frac{518 - 51.8 \cdot 5}{5}$

Step 13.5

Simplify the numerator.

Tap for more steps...

Step 13.5.1

Multiply $- 51.8$ by $5$ .

$\frac{518 - 259}{5}$

Step 13.5.2

Subtract $259$ from $518$ .

$\frac{259}{5}$

Step 13.6

Cancel the common factor of $259$ and $5$ .

Tap for more steps...

Step 13.6.1

Rewrite $259$ as $1 (259)$ .

$\frac{1 (259)}{5}$

Step 13.6.2

Cancel the common factors.

Tap for more steps...

Step 13.6.2.1

Rewrite $5$ as $1 (5)$ .

$\frac{1 \cdot 259}{1 \cdot 5}$

Step 13.6.2.2

Cancel the common factor.

$\frac{1 \cdot 259}{1 \cdot 5}$

Step 13.6.2.3

Rewrite the expression.

$\frac{259}{5}$

Step 14

$t = \frac{259}{30}$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$t = \frac{259}{30}$ is a local minimum

Step 15

Find the y-value when $t = \frac{259}{30}$ .

Tap for more steps...

Step 15.1

Replace the variable $t$ with $\frac{259}{30}$ in the expression.

$h (\frac{259}{30}) = 2 {(\frac{259}{30})}^{3} - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2

Simplify the result.

Tap for more steps...

Step 15.2.1

Simplify each term.

Tap for more steps...

Step 15.2.1.1

Apply the product rule to $\frac{259}{30}$ .

$h (\frac{259}{30}) = 2 (\frac{259^{3}}{30^{3}}) - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.2

Raise $259$ to the power of $3$ .

$h (\frac{259}{30}) = 2 (\frac{17373979}{30^{3}}) - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.3

Raise $30$ to the power of $3$ .

$h (\frac{259}{30}) = 2 (\frac{17373979}{27000}) - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.4

Cancel the common factor of $2$ .

Tap for more steps...

Step 15.2.1.4.1

Factor $2$ out of $27000$ .

$h (\frac{259}{30}) = 2 (\frac{17373979}{2 (13500)}) - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.4.2

Cancel the common factor.

$h (\frac{259}{30}) = 2 (\frac{17373979}{2 \cdot 13500}) - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.4.3

Rewrite the expression.

$h (\frac{259}{30}) = \frac{17373979}{13500} - 25.9 {(\frac{259}{30})}^{2} + 1110$

Step 15.2.1.5

Apply the product rule to $\frac{259}{30}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} - 25.9 \frac{259^{2}}{30^{2}} + 1110$

Step 15.2.1.6

Raise $259$ to the power of $2$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} - 25.9 \frac{67081}{30^{2}} + 1110$

Step 15.2.1.7

Raise $30$ to the power of $2$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} - 25.9 (\frac{67081}{900}) + 1110$

Step 15.2.1.8

Multiply $- 25.9 (\frac{67081}{900})$ .

Tap for more steps...

Step 15.2.1.8.1

Combine $- 25.9$ and $\frac{67081}{900}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 25.9 \cdot 67081}{900} + 1110$

Step 15.2.1.8.2

Multiply $- 25.9$ by $67081$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1737397.9}{900} + 1110$

Step 15.2.1.9

Divide $- 1737397.9$ by $900$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} - 1930.442\overline{1} + 1110$

Step 15.2.2

Find the common denominator.

Tap for more steps...

Step 15.2.2.1

Write $- 1930.442\overline{1}$ as a fraction with denominator $1$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1}}{1} + 1110$

Step 15.2.2.2

Multiply $\frac{- 1930.442\overline{1}}{1}$ by $\frac{13500}{13500}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1}}{1} \cdot \frac{13500}{13500} + 1110$

Step 15.2.2.3

Multiply $\frac{- 1930.442\overline{1}}{1}$ by $\frac{13500}{13500}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1} \cdot 13500}{13500} + 1110$

Step 15.2.2.4

Write $1110$ as a fraction with denominator $1$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1} \cdot 13500}{13500} + \frac{1110}{1}$

Step 15.2.2.5

Multiply $\frac{1110}{1}$ by $\frac{13500}{13500}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1} \cdot 13500}{13500} + \frac{1110}{1} \cdot \frac{13500}{13500}$

Step 15.2.2.6

Multiply $\frac{1110}{1}$ by $\frac{13500}{13500}$ .

$h (\frac{259}{30}) = \frac{17373979}{13500} + \frac{- 1930.442\overline{1} \cdot 13500}{13500} + \frac{1110 \cdot 13500}{13500}$

Step 15.2.3

Combine the numerators over the common denominator.

$h (\frac{259}{30}) = \frac{17373979 - 1930.442\overline{1} \cdot 13500 + 1110 \cdot 13500}{13500}$

Step 15.2.4

Simplify each term.

Tap for more steps...

Step 15.2.4.1

Multiply $- 1930.442\overline{1}$ by $13500$ .

$h (\frac{259}{30}) = \frac{17373979 - 26060968.5 + 1110 \cdot 13500}{13500}$

Step 15.2.4.2

Multiply $1110$ by $13500$ .

$h (\frac{259}{30}) = \frac{17373979 - 26060968.5 + 14985000}{13500}$

Step 15.2.5

Simplify the expression.

Tap for more steps...

Step 15.2.5.1

Subtract $26060968.5$ from $17373979$ .

$h (\frac{259}{30}) = \frac{- 8686989.5 + 14985000}{13500}$

Step 15.2.5.2

Add $- 8686989.5$ and $14985000$ .

$h (\frac{259}{30}) = \frac{6298010.5}{13500}$

Step 15.2.5.3

Divide $6298010.5$ by $13500$ .

$h (\frac{259}{30}) = 466.519\overline{296}$

Step 15.2.6

The final answer is $466.519\overline{296}$ .

$y = 466.519\overline{296}$

Step 16

These are the local extrema for $h (t) = 2 t^{3} - 25.9 t^{2} + 1110$ .

$(0, 1110)$ is a local maxima

$(\frac{259}{30}, 466.519\overline{296})$ is a local minima

Step 17