Calculus Examples

$g (t) = \frac{0.00331}{0.00331 + 0.99669 e^{- 3.8 t}}$

Step 1

Differentiate using the Constant Multiple Rule.

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Step 1.1

Since $0.00331$ is constant with respect to $t$ , the derivative of $\frac{0.00331}{0.00331 + 0.99669 e^{- 3.8 t}}$ with respect to $t$ is $0.00331 \frac{d}{d t} [\frac{1}{0.00331 + 0.99669 e^{- 3.8 t}}]$ .

$0.00331 \frac{d}{d t} [\frac{1}{0.00331 + 0.99669 e^{- 3.8 t}}]$

Step 1.2

Rewrite $\frac{1}{0.00331 + 0.99669 e^{- 3.8 t}}$ as ${(0.00331 + 0.99669 e^{- 3.8 t})}^{- 1}$ .

$0.00331 \frac{d}{d t} [{(0.00331 + 0.99669 e^{- 3.8 t})}^{- 1}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = t^{- 1}$ and $g (t) = 0.00331 + 0.99669 e^{- 3.8 t}$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as $0.00331 + 0.99669 e^{- 3.8 t}$ .

$0.00331 (\frac{d}{d u_{1}} [{u_{1}}^{- 1}] \frac{d}{d t} [0.00331 + 0.99669 e^{- 3.8 t}])$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = - 1$ .

$0.00331 (- {u_{1}}^{- 2} \frac{d}{d t} [0.00331 + 0.99669 e^{- 3.8 t}])$

Step 2.3

Replace all occurrences of $u_{1}$ with $0.00331 + 0.99669 e^{- 3.8 t}$ .

$0.00331 (- {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} \frac{d}{d t} [0.00331 + 0.99669 e^{- 3.8 t}])$

Step 3

Differentiate.

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Step 3.1

Multiply $- 1$ by $0.00331$ .

$- 0.00331 ({(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} \frac{d}{d t} [0.00331 + 0.99669 e^{- 3.8 t}])$

Step 3.2

By the Sum Rule, the derivative of $0.00331 + 0.99669 e^{- 3.8 t}$ with respect to $t$ is $\frac{d}{d t} [0.00331] + \frac{d}{d t} [0.99669 e^{- 3.8 t}]$ .

$- 0.00331 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (\frac{d}{d t} [0.00331] + \frac{d}{d t} [0.99669 e^{- 3.8 t}])$

Step 3.3

Since $0.00331$ is constant with respect to $t$ , the derivative of $0.00331$ with respect to $t$ is $0$ .

$- 0.00331 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (0 + \frac{d}{d t} [0.99669 e^{- 3.8 t}])$

Step 3.4

Add $0$ and $\frac{d}{d t} [0.99669 e^{- 3.8 t}]$ .

$- 0.00331 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} \frac{d}{d t} [0.99669 e^{- 3.8 t}]$

Step 3.5

Since $0.99669$ is constant with respect to $t$ , the derivative of $0.99669 e^{- 3.8 t}$ with respect to $t$ is $0.99669 \frac{d}{d t} [e^{- 3.8 t}]$ .

$- 0.00331 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (0.99669 \frac{d}{d t} [e^{- 3.8 t}])$

Step 3.6

Multiply $0.99669$ by $- 0.00331$ .

$- 0.00329904 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} \frac{d}{d t} [e^{- 3.8 t}]$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = e^{t}$ and $g (t) = - 3.8 t$ .

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Step 4.1

To apply the Chain Rule, set $u_{2}$ as $- 3.8 t$ .

$- 0.00329904 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (\frac{d}{d u_{2}} [e^{u_{2}}] \frac{d}{d t} [- 3.8 t])$

Step 4.2

Differentiate using the Exponential Rule which states that $\frac{d}{d u_{2}} [a^{u_{2}}]$ is $a^{u_{2}} \ln (a)$ where $a$ = $e$ .

$- 0.00329904 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (e^{u_{2}} \frac{d}{d t} [- 3.8 t])$

Step 4.3

Replace all occurrences of $u_{2}$ with $- 3.8 t$ .

$- 0.00329904 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (e^{- 3.8 t} \frac{d}{d t} [- 3.8 t])$

Step 5

Differentiate.

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Step 5.1

Since $- 3.8$ is constant with respect to $t$ , the derivative of $- 3.8 t$ with respect to $t$ is $- 3.8 \frac{d}{d t} [t]$ .

$- 0.00329904 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (e^{- 3.8 t} (- 3.8 \frac{d}{d t} [t]))$

Step 5.2

Multiply $- 3.8$ by $- 0.00329904$ .

$0.01253636 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (e^{- 3.8 t} (\frac{d}{d t} [t]))$

Step 5.3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$0.01253636 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} (e^{- 3.8 t} \cdot 1)$

Step 5.4

Simplify the expression.

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Step 5.4.1

Multiply $e^{- 3.8 t}$ by $1$ .

$0.01253636 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} e^{- 3.8 t}$

Step 5.4.2

Reorder the factors of $0.01253636 {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2} e^{- 3.8 t}$ .

$0.01253636 e^{- 3.8 t} {(0.00331 + 0.99669 e^{- 3.8 t})}^{- 2}$