Calculus Examples

$f (x) = \frac{x}{25 + x^{2}}$

Step 1

Find the first derivative of the function.

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Step 1.1

Differentiate using the Quotient Rule which states that $\frac{d}{d x} [\frac{f (x)}{g (x)}]$ is $\frac{g (x) \frac{d}{d x} [f (x)] - f (x) \frac{d}{d x} [g (x)]}{{g (x)}^{2}}$ where $f (x) = x$ and $g (x) = 25 + x^{2}$ .

$\frac{(25 + x^{2}) \frac{d}{d x} [x] - x \frac{d}{d x} [25 + x^{2}]}{{(25 + x^{2})}^{2}}$

Step 1.2

Differentiate.

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Step 1.2.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$\frac{(25 + x^{2}) \cdot 1 - x \frac{d}{d x} [25 + x^{2}]}{{(25 + x^{2})}^{2}}$

Step 1.2.2

Multiply $25 + x^{2}$ by $1$ .

$\frac{25 + x^{2} - x \frac{d}{d x} [25 + x^{2}]}{{(25 + x^{2})}^{2}}$

Step 1.2.3

By the Sum Rule, the derivative of $25 + x^{2}$ with respect to $x$ is $\frac{d}{d x} [25] + \frac{d}{d x} [x^{2}]$ .

$\frac{25 + x^{2} - x (\frac{d}{d x} [25] + \frac{d}{d x} [x^{2}])}{{(25 + x^{2})}^{2}}$

Step 1.2.4

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$\frac{25 + x^{2} - x (0 + \frac{d}{d x} [x^{2}])}{{(25 + x^{2})}^{2}}$

Step 1.2.5

Add $0$ and $\frac{d}{d x} [x^{2}]$ .

$\frac{25 + x^{2} - x \frac{d}{d x} [x^{2}]}{{(25 + x^{2})}^{2}}$

Step 1.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$\frac{25 + x^{2} - x (2 x)}{{(25 + x^{2})}^{2}}$

Step 1.2.7

Multiply $2$ by $- 1$ .

$\frac{25 + x^{2} - 2 x \cdot x}{{(25 + x^{2})}^{2}}$

Step 1.3

Raise $x$ to the power of $1$ .

$\frac{25 + x^{2} - 2 (x^{1} x)}{{(25 + x^{2})}^{2}}$

Step 1.4

Raise $x$ to the power of $1$ .

$\frac{25 + x^{2} - 2 (x^{1} x^{1})}{{(25 + x^{2})}^{2}}$

Step 1.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{25 + x^{2} - 2 x^{1 + 1}}{{(25 + x^{2})}^{2}}$

Step 1.6

Add $1$ and $1$ .

$\frac{25 + x^{2} - 2 x^{2}}{{(25 + x^{2})}^{2}}$

Step 1.7

Subtract $2 x^{2}$ from $x^{2}$ .

$\frac{25 - x^{2}}{{(25 + x^{2})}^{2}}$

Step 1.8

Reorder terms.

$\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}}$

Step 2

Find the second derivative of the function.

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Step 2.1

$f'' (x) = \frac{{(x^{2} + 25)}^{2} \frac{d}{d x} (- x^{2} + 25) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{({(x^{2} + 25)}^{2})}^{2}}$

Step 2.2

Differentiate.

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Step 2.2.1

Multiply the exponents in ${({(x^{2} + 25)}^{2})}^{2}$ .

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Step 2.2.1.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} \frac{d}{d x} (- x^{2} + 25) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{2 \cdot 2}}$

Step 2.2.1.2

Multiply $2$ by $2$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} \frac{d}{d x} (- x^{2} + 25) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.2

By the Sum Rule, the derivative of $- x^{2} + 25$ with respect to $x$ is $\frac{d}{d x} [- x^{2}] + \frac{d}{d x} [25]$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (\frac{d}{d x} (- x^{2}) + \frac{d}{d x} (25)) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.3

Since $- 1$ is constant with respect to $x$ , the derivative of $- x^{2}$ with respect to $x$ is $- \frac{d}{d x} [x^{2}]$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- \frac{d}{d x} x^{2} + \frac{d}{d x} (25)) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.4

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- (2 x) + \frac{d}{d x} (25)) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.5

Multiply $2$ by $- 1$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x + \frac{d}{d x} (25)) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.6

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x + 0) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.2.7

Add $- 2 x$ and $0$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - (- x^{2} + 25) \frac{d}{d x} {(x^{2} + 25)}^{2}}{{(x^{2} + 25)}^{4}}$

Step 2.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = x^{2} + 25$ .

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Step 2.3.1

To apply the Chain Rule, set $u$ as $x^{2} + 25$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - (- x^{2} + 25) (\frac{d}{d u} (u^{2}) \frac{d}{d x} (x^{2} + 25))}{{(x^{2} + 25)}^{4}}$

Step 2.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - (- x^{2} + 25) (2 u \frac{d}{d x} (x^{2} + 25))}{{(x^{2} + 25)}^{4}}$

Step 2.3.3

Replace all occurrences of $u$ with $x^{2} + 25$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - (- x^{2} + 25) (2 (x^{2} + 25) \frac{d}{d x} (x^{2} + 25))}{{(x^{2} + 25)}^{4}}$

Step 2.4

Differentiate.

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Step 2.4.1

Multiply $2$ by $- 1$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) ((x^{2} + 25) \frac{d}{d x} (x^{2} + 25))}{{(x^{2} + 25)}^{4}}$

Step 2.4.2

By the Sum Rule, the derivative of $x^{2} + 25$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [25]$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) ((x^{2} + 25) (\frac{d}{d x} (x^{2}) + \frac{d}{d x} (25)))}{{(x^{2} + 25)}^{4}}$

Step 2.4.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) ((x^{2} + 25) (2 x + \frac{d}{d x} (25)))}{{(x^{2} + 25)}^{4}}$

Step 2.4.4

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) ((x^{2} + 25) (2 x + 0))}{{(x^{2} + 25)}^{4}}$

Step 2.4.5

Simplify the expression.

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Step 2.4.5.1

Add $2 x$ and $0$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) ((x^{2} + 25) (2 x))}{{(x^{2} + 25)}^{4}}$

Step 2.4.5.2

Move $2$ to the left of $x^{2} + 25$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 2 (- x^{2} + 25) (2 \cdot ((x^{2} + 25) x))}{{(x^{2} + 25)}^{4}}$

Step 2.4.5.3

Multiply $2$ by $- 2$ .

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) - 4 (- x^{2} + 25) ((x^{2} + 25) x)}{{(x^{2} + 25)}^{4}}$

Step 2.5

Simplify.

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Step 2.5.1

Apply the distributive property.

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) + (- 4 (- x^{2}) - 4 \cdot 25) ((x^{2} + 25) x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.2

Apply the distributive property.

$f'' (x) = \frac{{(x^{2} + 25)}^{2} (- 2 x) + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3

Simplify the numerator.

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Step 2.5.3.1

Simplify each term.

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Step 2.5.3.1.1

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 {(x^{2} + 25)}^{2} x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.2

Rewrite ${(x^{2} + 25)}^{2}$ as $(x^{2} + 25) (x^{2} + 25)$ .

$f'' (x) = \frac{- 2 ((x^{2} + 25) (x^{2} + 25)) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.3

Expand $(x^{2} + 25) (x^{2} + 25)$ using the FOIL Method.

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Step 2.5.3.1.3.1

Apply the distributive property.

$f'' (x) = \frac{- 2 (x^{2} (x^{2} + 25) + 25 (x^{2} + 25)) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.3.2

Apply the distributive property.

$f'' (x) = \frac{- 2 (x^{2} x^{2} + x^{2} \cdot 25 + 25 (x^{2} + 25)) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.3.3

Apply the distributive property.

$f'' (x) = \frac{- 2 (x^{2} x^{2} + x^{2} \cdot 25 + 25 x^{2} + 25 \cdot 25) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.4

Simplify and combine like terms.

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Step 2.5.3.1.4.1

Simplify each term.

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Step 2.5.3.1.4.1.1

Multiply $x^{2}$ by $x^{2}$ by adding the exponents.

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Step 2.5.3.1.4.1.1.1

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 (x^{2 + 2} + x^{2} \cdot 25 + 25 x^{2} + 25 \cdot 25) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.4.1.1.2

Add $2$ and $2$ .

$f'' (x) = \frac{- 2 (x^{4} + x^{2} \cdot 25 + 25 x^{2} + 25 \cdot 25) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.4.1.2

Move $25$ to the left of $x^{2}$ .

$f'' (x) = \frac{- 2 (x^{4} + 25 \cdot x^{2} + 25 x^{2} + 25 \cdot 25) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.4.1.3

Multiply $25$ by $25$ .

$f'' (x) = \frac{- 2 (x^{4} + 25 x^{2} + 25 x^{2} + 625) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.4.2

Add $25 x^{2}$ and $25 x^{2}$ .

$f'' (x) = \frac{- 2 (x^{4} + 50 x^{2} + 625) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.5

Apply the distributive property.

$f'' (x) = \frac{(- 2 x^{4} - 2 (50 x^{2}) - 2 \cdot 625) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.6

Simplify.

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Step 2.5.3.1.6.1

Multiply $50$ by $- 2$ .

$f'' (x) = \frac{(- 2 x^{4} - 100 x^{2} - 2 \cdot 625) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.6.2

Multiply $- 2$ by $625$ .

$f'' (x) = \frac{(- 2 x^{4} - 100 x^{2} - 1250) x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.7

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{4} x - 100 x^{2} x - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8

Simplify.

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Step 2.5.3.1.8.1

Multiply $x^{4}$ by $x$ by adding the exponents.

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Step 2.5.3.1.8.1.1

Move $x$ .

$f'' (x) = \frac{- 2 (x \cdot x^{4}) - 100 x^{2} x - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.1.2

Multiply $x$ by $x^{4}$ .

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Step 2.5.3.1.8.1.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 (x \cdot x^{4}) - 100 x^{2} x - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.1.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{1 + 4} - 100 x^{2} x - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.1.3

Add $1$ and $4$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{2} x - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.2

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 2.5.3.1.8.2.1

Move $x$ .

$f'' (x) = \frac{- 2 x^{5} - 100 (x \cdot x^{2}) - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.2.2

Multiply $x$ by $x^{2}$ .

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Step 2.5.3.1.8.2.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 x^{5} - 100 (x \cdot x^{2}) - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{1 + 2} - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.8.2.3

Add $1$ and $2$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (- 4 (- x^{2}) - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.9

Simplify each term.

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Step 2.5.3.1.9.1

Multiply $- 1$ by $- 4$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (4 x^{2} - 4 \cdot 25) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.9.2

Multiply $- 4$ by $25$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (4 x^{2} - 100) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.10

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 2.5.3.1.10.1

Multiply $x^{2}$ by $x$ .

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Step 2.5.3.1.10.1.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (4 x^{2} - 100) (x^{2} x + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.10.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (4 x^{2} - 100) (x^{2 + 1} + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.10.2

Add $2$ and $1$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + (4 x^{2} - 100) (x^{3} + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.11

Expand $(4 x^{2} - 100) (x^{3} + 25 x)$ using the FOIL Method.

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Step 2.5.3.1.11.1

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{2} (x^{3} + 25 x) - 100 (x^{3} + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.11.2

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{2} x^{3} + 4 x^{2} (25 x) - 100 (x^{3} + 25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.11.3

Apply the distributive property.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{2} x^{3} + 4 x^{2} (25 x) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12

Simplify and combine like terms.

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Step 2.5.3.1.12.1

Simplify each term.

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Step 2.5.3.1.12.1.1

Multiply $x^{2}$ by $x^{3}$ by adding the exponents.

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Step 2.5.3.1.12.1.1.1

Move $x^{3}$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 (x^{3} x^{2}) + 4 x^{2} (25 x) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{3 + 2} + 4 x^{2} (25 x) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.1.3

Add $3$ and $2$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 x^{2} (25 x) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.2

Rewrite using the commutative property of multiplication.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 \cdot (25 x^{2} x) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.3

Multiply $x^{2}$ by $x$ by adding the exponents.

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Step 2.5.3.1.12.1.3.1

Move $x$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 \cdot (25 (x \cdot x^{2})) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.3.2

Multiply $x$ by $x^{2}$ .

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Step 2.5.3.1.12.1.3.2.1

Raise $x$ to the power of $1$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 \cdot (25 (x \cdot x^{2})) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.3.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 \cdot (25 x^{1 + 2}) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.3.3

Add $1$ and $2$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 4 \cdot (25 x^{3}) - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.4

Multiply $4$ by $25$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 100 x^{3} - 100 x^{3} - 100 (25 x)}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.1.5

Multiply $25$ by $- 100$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 100 x^{3} - 100 x^{3} - 2500 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.2

Subtract $100 x^{3}$ from $100 x^{3}$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} + 0 - 2500 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.1.12.3

Add $4 x^{5}$ and $0$ .

$f'' (x) = \frac{- 2 x^{5} - 100 x^{3} - 1250 x + 4 x^{5} - 2500 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.2

Add $- 2 x^{5}$ and $4 x^{5}$ .

$f'' (x) = \frac{2 x^{5} - 100 x^{3} - 1250 x - 2500 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.3.3

Subtract $2500 x$ from $- 1250 x$ .

$f'' (x) = \frac{2 x^{5} - 100 x^{3} - 3750 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.4

Simplify the numerator.

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Step 2.5.4.1

Factor $2 x$ out of $2 x^{5} - 100 x^{3} - 3750 x$ .

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Step 2.5.4.1.1

Factor $2 x$ out of $2 x^{5}$ .

$f'' (x) = \frac{2 x (x^{4}) - 100 x^{3} - 3750 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.1.2

Factor $2 x$ out of $- 100 x^{3}$ .

$f'' (x) = \frac{2 x (x^{4}) + 2 x (- 50 x^{2}) - 3750 x}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.1.3

Factor $2 x$ out of $- 3750 x$ .

$f'' (x) = \frac{2 x (x^{4}) + 2 x (- 50 x^{2}) + 2 x (- 1875)}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.1.4

Factor $2 x$ out of $2 x (x^{4}) + 2 x (- 50 x^{2})$ .

$f'' (x) = \frac{2 x (x^{4} - 50 x^{2}) + 2 x (- 1875)}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.1.5

Factor $2 x$ out of $2 x (x^{4} - 50 x^{2}) + 2 x (- 1875)$ .

$f'' (x) = \frac{2 x (x^{4} - 50 x^{2} - 1875)}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.2

Rewrite $x^{4}$ as ${(x^{2})}^{2}$ .

$f'' (x) = \frac{2 x ({(x^{2})}^{2} - 50 x^{2} - 1875)}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.3

Let $u = x^{2}$ . Substitute $u$ for all occurrences of $x^{2}$ .

$f'' (x) = \frac{2 x (u^{2} - 50 u - 1875)}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.4

Factor $u^{2} - 50 u - 1875$ using the AC method.

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Step 2.5.4.4.1

Consider the form $x^{2} + b x + c$ . Find a pair of integers whose product is $c$ and whose sum is $b$ . In this case, whose product is $- 1875$ and whose sum is $- 50$ .

$- 75, 25$

Step 2.5.4.4.2

Write the factored form using these integers.

$f'' (x) = \frac{2 x ((u - 75) (u + 25))}{{(x^{2} + 25)}^{4}}$

Step 2.5.4.5

Replace all occurrences of $u$ with $x^{2}$ .

$f'' (x) = \frac{2 x (x^{2} - 75) (x^{2} + 25)}{{(x^{2} + 25)}^{4}}$

Step 2.5.5

Cancel the common factor of $x^{2} + 25$ and ${(x^{2} + 25)}^{4}$ .

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Step 2.5.5.1

Factor $x^{2} + 25$ out of $2 x (x^{2} - 75) (x^{2} + 25)$ .

$f'' (x) = \frac{(x^{2} + 25) (2 x (x^{2} - 75))}{{(x^{2} + 25)}^{4}}$

Step 2.5.5.2

Cancel the common factors.

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Step 2.5.5.2.1

Factor $x^{2} + 25$ out of ${(x^{2} + 25)}^{4}$ .

$f'' (x) = \frac{(x^{2} + 25) (2 x (x^{2} - 75))}{(x^{2} + 25) {(x^{2} + 25)}^{3}}$

Step 2.5.5.2.2

Cancel the common factor.

$f'' (x) = \frac{(x^{2} + 25) (2 x (x^{2} - 75))}{(x^{2} + 25) {(x^{2} + 25)}^{3}}$

Step 2.5.5.2.3

Rewrite the expression.

$f'' (x) = \frac{2 x (x^{2} - 75)}{{(x^{2} + 25)}^{3}}$

Step 3

To find the local maximum and minimum values of the function, set the derivative equal to $0$ and solve.

$\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}} = 0$

Step 4

Find the first derivative.

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Step 4.1

Find the first derivative.

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Step 4.1.1

$f' (x) = \frac{(25 + x^{2}) \frac{d}{d x} (x) - x \frac{d}{d x} (25 + x^{2})}{{(25 + x^{2})}^{2}}$

Step 4.1.2

Differentiate.

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Step 4.1.2.1

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$f' (x) = \frac{(25 + x^{2}) \cdot 1 - x \frac{d}{d x} (25 + x^{2})}{{(25 + x^{2})}^{2}}$

Step 4.1.2.2

Multiply $25 + x^{2}$ by $1$ .

$f' (x) = \frac{25 + x^{2} - x \frac{d}{d x} (25 + x^{2})}{{(25 + x^{2})}^{2}}$

Step 4.1.2.3

By the Sum Rule, the derivative of $25 + x^{2}$ with respect to $x$ is $\frac{d}{d x} [25] + \frac{d}{d x} [x^{2}]$ .

$f' (x) = \frac{25 + x^{2} - x (\frac{d}{d x} (25) + \frac{d}{d x} (x^{2}))}{{(25 + x^{2})}^{2}}$

Step 4.1.2.4

Since $25$ is constant with respect to $x$ , the derivative of $25$ with respect to $x$ is $0$ .

$f' (x) = \frac{25 + x^{2} - x (0 + \frac{d}{d x} (x^{2}))}{{(25 + x^{2})}^{2}}$

Step 4.1.2.5

Add $0$ and $\frac{d}{d x} [x^{2}]$ .

$f' (x) = \frac{25 + x^{2} - x \frac{d}{d x} x^{2}}{{(25 + x^{2})}^{2}}$

Step 4.1.2.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$f' (x) = \frac{25 + x^{2} - x (2 x)}{{(25 + x^{2})}^{2}}$

Step 4.1.2.7

Multiply $2$ by $- 1$ .

$f' (x) = \frac{25 + x^{2} - 2 x \cdot x}{{(25 + x^{2})}^{2}}$

Step 4.1.3

Raise $x$ to the power of $1$ .

$f' (x) = \frac{25 + x^{2} - 2 (x \cdot x)}{{(25 + x^{2})}^{2}}$

Step 4.1.4

Raise $x$ to the power of $1$ .

$f' (x) = \frac{25 + x^{2} - 2 (x \cdot x)}{{(25 + x^{2})}^{2}}$

Step 4.1.5

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$f' (x) = \frac{25 + x^{2} - 2 x^{1 + 1}}{{(25 + x^{2})}^{2}}$

Step 4.1.6

Add $1$ and $1$ .

$f' (x) = \frac{25 + x^{2} - 2 x^{2}}{{(25 + x^{2})}^{2}}$

Step 4.1.7

Subtract $2 x^{2}$ from $x^{2}$ .

$f' (x) = \frac{25 - x^{2}}{{(25 + x^{2})}^{2}}$

Step 4.1.8

Reorder terms.

$f' (x) = \frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}}$

Step 4.2

The first derivative of $f (x)$ with respect to $x$ is $\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}}$ .

$\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}}$

Step 5

Set the first derivative equal to $0$ then solve the equation $\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}} = 0$ .

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Step 5.1

Set the first derivative equal to $0$ .

$\frac{- x^{2} + 25}{{(x^{2} + 25)}^{2}} = 0$

Step 5.2

Set the numerator equal to zero.

$- x^{2} + 25 = 0$

Step 5.3

Solve the equation for $x$ .

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Step 5.3.1

Subtract $25$ from both sides of the equation.

$- x^{2} = - 25$

Step 5.3.2

Divide each term in $- x^{2} = - 25$ by $- 1$ and simplify.

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Step 5.3.2.1

Divide each term in $- x^{2} = - 25$ by $- 1$ .

$\frac{- x^{2}}{- 1} = \frac{- 25}{- 1}$

Step 5.3.2.2

Simplify the left side.

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Step 5.3.2.2.1

Dividing two negative values results in a positive value.

$\frac{x^{2}}{1} = \frac{- 25}{- 1}$

Step 5.3.2.2.2

Divide $x^{2}$ by $1$ .

$x^{2} = \frac{- 25}{- 1}$

Step 5.3.2.3

Simplify the right side.

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Step 5.3.2.3.1

Divide $- 25$ by $- 1$ .

$x^{2} = 25$

Step 5.3.3

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x = \pm \sqrt{25}$

Step 5.3.4

Simplify $\pm \sqrt{25}$ .

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Step 5.3.4.1

Rewrite $25$ as $5^{2}$ .

$x = \pm \sqrt{5^{2}}$

Step 5.3.4.2

Pull terms out from under the radical, assuming positive real numbers.

$x = \pm 5$

Step 5.3.5

The complete solution is the result of both the positive and negative portions of the solution.

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Step 5.3.5.1

First, use the positive value of the $\pm$ to find the first solution.

$x = 5$

Step 5.3.5.2

Next, use the negative value of the $\pm$ to find the second solution.

$x = - 5$

Step 5.3.5.3

The complete solution is the result of both the positive and negative portions of the solution.

$x = 5, - 5$

Step 6

Find the values where the derivative is undefined.

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Step 6.1

The domain of the expression is all real numbers except where the expression is undefined. In this case, there is no real number that makes the expression undefined.

Step 7

Critical points to evaluate.

$x = 5, - 5$

Step 8

Evaluate the second derivative at $x = 5$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{2 (5) ({(5)}^{2} - 75)}{{({(5)}^{2} + 25)}^{3}}$

Step 9

Evaluate the second derivative.

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Step 9.1

Multiply $2$ by $5$ .

$\frac{10 (5^{2} - 75)}{{(5^{2} + 25)}^{3}}$

Step 9.2

Simplify the denominator.

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Step 9.2.1

Raise $5$ to the power of $2$ .

$\frac{10 (5^{2} - 75)}{{(25 + 25)}^{3}}$

Step 9.2.2

Add $25$ and $25$ .

$\frac{10 (5^{2} - 75)}{50^{3}}$

Step 9.2.3

Raise $50$ to the power of $3$ .

$\frac{10 (5^{2} - 75)}{125000}$

Step 9.3

Simplify the numerator.

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Step 9.3.1

Raise $5$ to the power of $2$ .

$\frac{10 (25 - 75)}{125000}$

Step 9.3.2

Subtract $75$ from $25$ .

$\frac{10 \cdot - 50}{125000}$

Step 9.4

Reduce the expression by cancelling the common factors.

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Step 9.4.1

Multiply $10$ by $- 50$ .

$\frac{- 500}{125000}$

Step 9.4.2

Cancel the common factor of $- 500$ and $125000$ .

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Step 9.4.2.1

Factor $500$ out of $- 500$ .

$\frac{500 (- 1)}{125000}$

Step 9.4.2.2

Cancel the common factors.

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Step 9.4.2.2.1

Factor $500$ out of $125000$ .

$\frac{500 \cdot - 1}{500 \cdot 250}$

Step 9.4.2.2.2

Cancel the common factor.

$\frac{500 \cdot - 1}{500 \cdot 250}$

Step 9.4.2.2.3

Rewrite the expression.

$\frac{- 1}{250}$

Step 9.4.3

Move the negative in front of the fraction.

$- \frac{1}{250}$

Step 10

$x = 5$ is a local maximum because the value of the second derivative is negative. This is referred to as the second derivative test.

$x = 5$ is a local maximum

Step 11

Find the y-value when $x = 5$ .

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Step 11.1

Replace the variable $x$ with $5$ in the expression.

$f (5) = \frac{5}{25 + {(5)}^{2}}$

Step 11.2

Simplify the result.

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Step 11.2.1

Simplify the denominator.

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Step 11.2.1.1

Raise $5$ to the power of $2$ .

$f (5) = \frac{5}{25 + 25}$

Step 11.2.1.2

Add $25$ and $25$ .

$f (5) = \frac{5}{50}$

Step 11.2.2

Cancel the common factor of $5$ and $50$ .

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Step 11.2.2.1

Factor $5$ out of $5$ .

$f (5) = \frac{5 (1)}{50}$

Step 11.2.2.2

Cancel the common factors.

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Step 11.2.2.2.1

Factor $5$ out of $50$ .

$f (5) = \frac{5 \cdot 1}{5 \cdot 10}$

Step 11.2.2.2.2

Cancel the common factor.

$f (5) = \frac{5 \cdot 1}{5 \cdot 10}$

Step 11.2.2.2.3

Rewrite the expression.

$f (5) = \frac{1}{10}$

Step 11.2.3

The final answer is $\frac{1}{10}$ .

$y = \frac{1}{10}$

Step 12

Evaluate the second derivative at $x = - 5$ . If the second derivative is positive, then this is a local minimum. If it is negative, then this is a local maximum.

$\frac{2 (- 5) ({(- 5)}^{2} - 75)}{{({(- 5)}^{2} + 25)}^{3}}$

Step 13

Evaluate the second derivative.

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Step 13.1

Multiply $2$ by $- 5$ .

$\frac{- 10 ({(- 5)}^{2} - 75)}{{({(- 5)}^{2} + 25)}^{3}}$

Step 13.2

Simplify the denominator.

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Step 13.2.1

Raise $- 5$ to the power of $2$ .

$\frac{- 10 ({(- 5)}^{2} - 75)}{{(25 + 25)}^{3}}$

Step 13.2.2

Add $25$ and $25$ .

$\frac{- 10 ({(- 5)}^{2} - 75)}{50^{3}}$

Step 13.2.3

Raise $50$ to the power of $3$ .

$\frac{- 10 ({(- 5)}^{2} - 75)}{125000}$

Step 13.3

Simplify the numerator.

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Step 13.3.1

Raise $- 5$ to the power of $2$ .

$\frac{- 10 (25 - 75)}{125000}$

Step 13.3.2

Subtract $75$ from $25$ .

$\frac{- 10 \cdot - 50}{125000}$

Step 13.4

Reduce the expression by cancelling the common factors.

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Step 13.4.1

Multiply $- 10$ by $- 50$ .

$\frac{500}{125000}$

Step 13.4.2

Cancel the common factor of $500$ and $125000$ .

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Step 13.4.2.1

Factor $500$ out of $500$ .

$\frac{500 (1)}{125000}$

Step 13.4.2.2

Cancel the common factors.

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Step 13.4.2.2.1

Factor $500$ out of $125000$ .

$\frac{500 \cdot 1}{500 \cdot 250}$

Step 13.4.2.2.2

Cancel the common factor.

$\frac{500 \cdot 1}{500 \cdot 250}$

Step 13.4.2.2.3

Rewrite the expression.

$\frac{1}{250}$

Step 14

$x = - 5$ is a local minimum because the value of the second derivative is positive. This is referred to as the second derivative test.

$x = - 5$ is a local minimum

Step 15

Find the y-value when $x = - 5$ .

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Step 15.1

Replace the variable $x$ with $- 5$ in the expression.

$f (- 5) = \frac{- 5}{25 + {(- 5)}^{2}}$

Step 15.2

Simplify the result.

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Step 15.2.1

Simplify the denominator.

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Step 15.2.1.1

Raise $- 5$ to the power of $2$ .

$f (- 5) = \frac{- 5}{25 + 25}$

Step 15.2.1.2

Add $25$ and $25$ .

$f (- 5) = \frac{- 5}{50}$

Step 15.2.2

Reduce the expression by cancelling the common factors.

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Step 15.2.2.1

Cancel the common factor of $- 5$ and $50$ .

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Step 15.2.2.1.1

Factor $5$ out of $- 5$ .

$f (- 5) = \frac{5 (- 1)}{50}$

Step 15.2.2.1.2

Cancel the common factors.

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Step 15.2.2.1.2.1

Factor $5$ out of $50$ .

$f (- 5) = \frac{5 \cdot - 1}{5 \cdot 10}$

Step 15.2.2.1.2.2

Cancel the common factor.

$f (- 5) = \frac{5 \cdot - 1}{5 \cdot 10}$

Step 15.2.2.1.2.3

Rewrite the expression.

$f (- 5) = \frac{- 1}{10}$

Step 15.2.2.2

Move the negative in front of the fraction.

$f (- 5) = - \frac{1}{10}$

Step 15.2.3

The final answer is $- \frac{1}{10}$ .

$y = - \frac{1}{10}$

Step 16

These are the local extrema for $f (x) = \frac{x}{25 + x^{2}}$ .

$(5, \frac{1}{10})$ is a local maxima

$(- 5, - \frac{1}{10})$ is a local minima

Step 17