Calculus Examples

$f'' (x) = 6 + \cos (x)$

Step 1

The function $f' (x)$ can be found by evaluating the indefinite integral of the derivative $f'' (x)$ .

$f' (x) = \int f'' (x) d x$

Step 2

Split the single integral into multiple integrals.

$\int 6 d x + \int \cos (x) d x$

Step 3

Apply the constant rule.

$6 x + C + \int \cos (x) d x$

Step 4

The integral of $\cos (x)$ with respect to $x$ is $\sin (x)$ .

$6 x + C + \sin (x) + C$

Step 5

Simplify.

$6 x + \sin (x) + C$

Step 6

The function $f'$ if derived from the integral of the derivative of the function. This is valid by the fundamental theorem of calculus.

$f' (x) = 6 x + \sin (x) + C$

Step 7

The function $f (x)$ can be found by evaluating the indefinite integral of the derivative $f' (x)$ .

$f (x) = \int f' (x) d x$

Step 8

Split the single integral into multiple integrals.

$\int 6 x d x + \int \sin (x) d x + \int C d x$

Step 9

Since $6$ is constant with respect to $x$ , move $6$ out of the integral.

$6 \int x d x + \int \sin (x) d x + \int C d x$

Step 10

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$6 (\frac{1}{2} x^{2} + C) + \int \sin (x) d x + \int C d x$

Step 11

The integral of $\sin (x)$ with respect to $x$ is $- \cos (x)$ .

$6 (\frac{1}{2} x^{2} + C) - \cos (x) + C + \int C d x$

Step 12

Combine $\frac{1}{2}$ and $x^{2}$ .

$6 (\frac{x^{2}}{2} + C) - \cos (x) + C + \int C d x$

Step 13

Apply the constant rule.

$6 (\frac{x^{2}}{2} + C) - \cos (x) + C + C x + C$

Step 14

Simplify.

$3 x^{2} - \cos (x) + C x + C$

Step 15

The function $f$ if derived from the integral of the derivative of the function. This is valid by the fundamental theorem of calculus.

$f (x) = 3 x^{2} - \cos (x) + C x + C$