Calculus Examples

$4 \sin (3 x)$

Step 1

Write $4 \sin (3 x)$ as a function.

$f (x) = 4 \sin (3 x)$

Step 2

The function $F (x)$ can be found by finding the indefinite integral of the derivative $f (x)$ .

$F (x) = \int f (x) d x$

Step 3

Set up the integral to solve.

$F (x) = \int 4 \sin (3 x) d x$

Step 4

Since $4$ is constant with respect to $x$ , move $4$ out of the integral.

$4 \int \sin (3 x) d x$

Step 5

Let $u = 3 x$ . Then $d u = 3 d x$ , so $\frac{1}{3} d u = d x$ . Rewrite using $u$ and $d$ $u$ .

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Step 5.1

Let $u = 3 x$ . Find $\frac{d u}{d x}$ .

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Step 5.1.1

Differentiate $3 x$ .

$\frac{d}{d x} [3 x]$

Step 5.1.2

Since $3$ is constant with respect to $x$ , the derivative of $3 x$ with respect to $x$ is $3 \frac{d}{d x} [x]$ .

$3 \frac{d}{d x} [x]$

Step 5.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$3 \cdot 1$

Step 5.1.4

Multiply $3$ by $1$ .

$3$

Step 5.2

Rewrite the problem using $u$ and $d u$ .

$4 \int \sin (u) \frac{1}{3} d u$

Step 6

Combine $\sin (u)$ and $\frac{1}{3}$ .

$4 \int \frac{\sin (u)}{3} d u$

Step 7

Since $\frac{1}{3}$ is constant with respect to $u$ , move $\frac{1}{3}$ out of the integral.

$4 (\frac{1}{3} \int \sin (u) d u)$

Step 8

Combine $\frac{1}{3}$ and $4$ .

$\frac{4}{3} \int \sin (u) d u$

Step 9

The integral of $\sin (u)$ with respect to $u$ is $- \cos (u)$ .

$\frac{4}{3} (- \cos (u) + C)$

Step 10

Simplify.

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Step 10.1

Simplify.

$\frac{4}{3} (- \cos (u)) + C$

Step 10.2

Combine $\frac{4}{3}$ and $\cos (u)$ .

$- \frac{4 \cos (u)}{3} + C$

Step 11

Replace all occurrences of $u$ with $3 x$ .

$- \frac{4 \cos (3 x)}{3} + C$

Step 12

Reorder terms.

$- \frac{4}{3} \cos (3 x) + C$

Step 13

The answer is the antiderivative of the function $f (x) = 4 \sin (3 x)$ .

$F (x) =$ $- \frac{4}{3} \cos (3 x) + C$