Calculus Examples

$lim_{x \to \infty} \frac{\sin^{2} (x)}{x^{2} + 1}$

Step 1

Since $\frac{0}{x^{2} + 1} \leq \frac{\sin^{2} (x)}{x^{2} + 1} \leq \frac{1}{x^{2} + 1}$ and $lim_{x \to \infty} \frac{0}{x^{2} + 1} = lim_{x \to \infty} \frac{1}{x^{2} + 1} = 0$ , apply the squeeze theorem.

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