Calculus Examples

$lim_{x \to \frac{π}{2}} (\frac{\sin (x)}{\cos^{2} (x)}) - \tan^{2} (x)$

Step 1

Combine terms.

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Step 1.1

To write $- \tan^{2} (x)$ as a fraction with a common denominator, multiply by $\frac{\cos^{2} (x)}{\cos^{2} (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\sin (x)}{\cos^{2} (x)} - \tan^{2} (x) \cdot \frac{\cos^{2} (x)}{\cos^{2} (x)}$

Step 1.2

Combine $- \tan^{2} (x)$ and $\frac{\cos^{2} (x)}{\cos^{2} (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\sin (x)}{\cos^{2} (x)} + \frac{- \tan^{2} (x) \cos^{2} (x)}{\cos^{2} (x)}$

Step 1.3

Combine the numerators over the common denominator.

$lim_{x \to \frac{π}{2}} \frac{\sin (x) - \tan^{2} (x) \cos^{2} (x)}{\cos^{2} (x)}$

Step 2

Apply L'Hospital's rule.

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Step 2.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 2.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to \frac{π}{2}} \sin (x) - \tan^{2} (x) \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2

Evaluate the limit of the numerator.

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Step 2.1.2.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} \tan^{2} (x) \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.2

Move the limit inside the trig function because sine is continuous.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} \tan^{2} (x) \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.3

Rewrite $\tan^{2} (x) \cos^{2} (x)$ as $\frac{\tan^{2} (x)}{\cos^{- 2} (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} \frac{\tan^{2} (x)}{\cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.4

Set up the limit as a left-sided limit.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\tan^{2} (x)}{\cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5

Evaluate the left-sided limit.

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Step 2.1.2.5.1

Apply L'Hospital's rule.

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Step 2.1.2.5.1.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 2.1.2.5.1.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{lim_{x \to {(\frac{π}{2})}^{-}} \tan^{2} (x)}{lim_{x \to {(\frac{π}{2})}^{-}} \cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.1.2

As the $x$ values approach $\frac{π}{2}$ from the left, the function values increase without bound.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{lim_{x \to {(\frac{π}{2})}^{-}} \cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.1.3

Evaluate the limit of the denominator.

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Step 2.1.2.5.1.1.3.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{lim_{x \to {(\frac{π}{2})}^{-}} \frac{1}{\cos^{2} (x)}}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.1.3.2

Since the numerator is positive and the denominator $\cos^{2} (x)$ approaches zero and is greater than zero for $x$ near $\frac{π}{2}$ to the left, the function increases without bound.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.1.3.3

Infinity divided by infinity is undefined.

Undefined

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.1.4

Infinity divided by infinity is undefined.

Undefined

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.2

Since $\frac{\infty}{\infty}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to {(\frac{π}{2})}^{-}} \frac{\tan^{2} (x)}{\cos^{- 2} (x)} = lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{d}{d x} [\tan^{2} (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}$

Step 2.1.2.5.1.3

Find the derivative of the numerator and denominator.

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Step 2.1.2.5.1.3.1

Differentiate the numerator and denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{d}{d x} [\tan^{2} (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \tan (x)$ .

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Step 2.1.2.5.1.3.2.1

To apply the Chain Rule, set $u$ as $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{d}{d u} [u^{2}] \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 u \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.2.3

Replace all occurrences of $u$ with $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \tan (x) \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.3

The derivative of $\tan (x)$ with respect to $x$ is $\sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \tan (x) \sec^{2} (x)}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.4

Reorder the factors of $2 \tan (x) \sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.5

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- 2}$ and $g (x) = \cos (x)$ .

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Step 2.1.2.5.1.3.5.1

To apply the Chain Rule, set $u$ as $\cos (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{d}{d u} [u^{- 2}] \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.5.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 u^{- 3} \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.5.3

Replace all occurrences of $u$ with $\cos (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 \cos^{- 3} (x) \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.6

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 \cos^{- 3} (x) \cdot - 1 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.7

Multiply $- 1$ by $- 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{2 \cos^{- 3} (x) \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.8

Simplify.

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Step 2.1.2.5.1.3.8.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{2 \frac{1}{\cos^{3} (x)} \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.8.2

Combine $2$ and $\frac{1}{\cos^{3} (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{2}{\cos^{3} (x)} \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.3.8.3

Combine $\frac{2}{\cos^{3} (x)}$ and $\sin (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{2 \sin (x)}{\cos^{3} (x)}}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.4

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} 2 \sec^{2} (x) \tan (x) \frac{\cos^{3} (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.5

Combine factors.

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Step 2.1.2.5.1.5.1

Combine $\frac{\cos^{3} (x)}{2 \sin (x)}$ and $2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \cdot 2}{2 \sin (x)} \sec^{2} (x) \tan (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.5.2

Combine $\frac{\cos^{3} (x) \cdot 2}{2 \sin (x)}$ and $\sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x)}{2 \sin (x)} \tan (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.5.3

Combine $\frac{\cos^{3} (x) \cdot 2 \sec^{2} (x)}{2 \sin (x)}$ and $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x) \tan (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.6

Cancel the common factor of $2$ .

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Step 2.1.2.5.1.6.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x) \tan (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.6.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \sec^{2} (x) \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7

Simplify the numerator.

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Step 2.1.2.5.1.7.1

Rewrite $\sec (x)$ in terms of sines and cosines.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) {(\frac{1}{\cos (x)})}^{2} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.2

Apply the product rule to $\frac{1}{\cos (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \frac{1^{2}}{\cos^{2} (x)} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.3

One to any power is one.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \frac{1}{\cos^{2} (x)} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.4

Rewrite $\tan (x)$ in terms of sines and cosines.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\cos^{3} (x) \frac{1}{\cos^{2} (x)} \frac{\sin (x)}{\cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.5

Combine exponents.

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Step 2.1.2.5.1.7.5.1

Combine $\cos^{3} (x)$ and $\frac{1}{\cos^{2} (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x)}{\cos^{2} (x)} \cdot \frac{\sin (x)}{\cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.5.2

Multiply $\frac{\cos^{3} (x)}{\cos^{2} (x)}$ by $\frac{\sin (x)}{\cos (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{2} (x) \cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.5.3

Multiply $\cos^{2} (x)$ by $\cos (x)$ by adding the exponents.

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Step 2.1.2.5.1.7.5.3.1

Multiply $\cos^{2} (x)$ by $\cos (x)$ .

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Step 2.1.2.5.1.7.5.3.1.1

Raise $\cos (x)$ to the power of $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{2} (x) \cos^{1} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.5.3.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x) \sin (x)}{{\cos (x)}^{2 + 1}}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.5.3.2

Add $2$ and $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.6

Reduce the expression by cancelling the common factors.

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Step 2.1.2.5.1.7.6.1

Reduce the expression $\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}$ by cancelling the common factors.

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Step 2.1.2.5.1.7.6.1.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.6.1.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\frac{\sin (x)}{1}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.7.6.2

Divide $\sin (x)$ by $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\sin (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.8

Cancel the common factor of $\sin (x)$ .

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Step 2.1.2.5.1.8.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} \frac{\sin (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.1.8.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{-}} 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.5.2

Evaluate the limit of $1$ which is constant as $x$ approaches $\frac{π}{2}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - 1 \cdot 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.6

Set up the limit as a right-sided limit.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\tan^{2} (x)}{\cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7

Evaluate the right-sided limit.

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Step 2.1.2.7.1

Apply L'Hospital's rule.

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Step 2.1.2.7.1.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 2.1.2.7.1.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{lim_{x \to {(\frac{π}{2})}^{+}} \tan^{2} (x)}{lim_{x \to {(\frac{π}{2})}^{+}} \cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.1.2

As the $x$ values approach $\frac{π}{2}$ from the right, the function values increase without bound.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{lim_{x \to {(\frac{π}{2})}^{+}} \cos^{- 2} (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.1.3

Evaluate the limit of the denominator.

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Step 2.1.2.7.1.1.3.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{lim_{x \to {(\frac{π}{2})}^{+}} \frac{1}{\cos^{2} (x)}}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.1.3.2

Since the numerator is positive and the denominator $\cos^{2} (x)$ approaches zero and is greater than zero for $x$ near $\frac{π}{2}$ to the right, the function increases without bound.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.1.3.3

Infinity divided by infinity is undefined.

Undefined

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.1.4

Infinity divided by infinity is undefined.

Undefined

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - \frac{\infty}{\infty}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.2

$lim_{x \to {(\frac{π}{2})}^{+}} \frac{\tan^{2} (x)}{\cos^{- 2} (x)} = lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{d}{d x} [\tan^{2} (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}$

Step 2.1.2.7.1.3

Find the derivative of the numerator and denominator.

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Step 2.1.2.7.1.3.1

Differentiate the numerator and denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{d}{d x} [\tan^{2} (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \tan (x)$ .

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Step 2.1.2.7.1.3.2.1

To apply the Chain Rule, set $u$ as $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{d}{d u} [u^{2}] \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 u \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.2.3

Replace all occurrences of $u$ with $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \tan (x) \frac{d}{d x} [\tan (x)]}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.3

The derivative of $\tan (x)$ with respect to $x$ is $\sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \tan (x) \sec^{2} (x)}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.4

Reorder the factors of $2 \tan (x) \sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{d}{d x} [\cos^{- 2} (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.5

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{- 2}$ and $g (x) = \cos (x)$ .

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Step 2.1.2.7.1.3.5.1

To apply the Chain Rule, set $u$ as $\cos (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{d}{d u} [u^{- 2}] \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.5.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = - 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 u^{- 3} \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.5.3

Replace all occurrences of $u$ with $\cos (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 \cos^{- 3} (x) \frac{d}{d x} [\cos (x)]}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.6

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{- 2 \cos^{- 3} (x) \cdot - 1 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.7

Multiply $- 1$ by $- 2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{2 \cos^{- 3} (x) \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.8

Simplify.

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Step 2.1.2.7.1.3.8.1

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{2 \frac{1}{\cos^{3} (x)} \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.8.2

Combine $2$ and $\frac{1}{\cos^{3} (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{2}{\cos^{3} (x)} \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.3.8.3

Combine $\frac{2}{\cos^{3} (x)}$ and $\sin (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{2 \sec^{2} (x) \tan (x)}{\frac{2 \sin (x)}{\cos^{3} (x)}}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.4

Multiply the numerator by the reciprocal of the denominator.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} 2 \sec^{2} (x) \tan (x) \frac{\cos^{3} (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.5

Combine factors.

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Step 2.1.2.7.1.5.1

Combine $\frac{\cos^{3} (x)}{2 \sin (x)}$ and $2$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \cdot 2}{2 \sin (x)} \sec^{2} (x) \tan (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.5.2

Combine $\frac{\cos^{3} (x) \cdot 2}{2 \sin (x)}$ and $\sec^{2} (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x)}{2 \sin (x)} \tan (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.5.3

Combine $\frac{\cos^{3} (x) \cdot 2 \sec^{2} (x)}{2 \sin (x)}$ and $\tan (x)$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x) \tan (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.6

Cancel the common factor of $2$ .

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Step 2.1.2.7.1.6.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \cdot 2 \sec^{2} (x) \tan (x)}{2 \sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.6.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \sec^{2} (x) \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7

Simplify the numerator.

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Step 2.1.2.7.1.7.1

Rewrite $\sec (x)$ in terms of sines and cosines.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) {(\frac{1}{\cos (x)})}^{2} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.2

Apply the product rule to $\frac{1}{\cos (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \frac{1^{2}}{\cos^{2} (x)} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.3

One to any power is one.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \frac{1}{\cos^{2} (x)} \tan (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.4

Rewrite $\tan (x)$ in terms of sines and cosines.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\cos^{3} (x) \frac{1}{\cos^{2} (x)} \frac{\sin (x)}{\cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.5

Combine exponents.

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Step 2.1.2.7.1.7.5.1

Combine $\cos^{3} (x)$ and $\frac{1}{\cos^{2} (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x)}{\cos^{2} (x)} \cdot \frac{\sin (x)}{\cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.5.2

Multiply $\frac{\cos^{3} (x)}{\cos^{2} (x)}$ by $\frac{\sin (x)}{\cos (x)}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{2} (x) \cos (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.5.3

Multiply $\cos^{2} (x)$ by $\cos (x)$ by adding the exponents.

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Step 2.1.2.7.1.7.5.3.1

Multiply $\cos^{2} (x)$ by $\cos (x)$ .

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Step 2.1.2.7.1.7.5.3.1.1

Raise $\cos (x)$ to the power of $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{2} (x) \cos^{1} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.5.3.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x) \sin (x)}{{\cos (x)}^{2 + 1}}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.5.3.2

Add $2$ and $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.6

Reduce the expression by cancelling the common factors.

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Step 2.1.2.7.1.7.6.1

Reduce the expression $\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}$ by cancelling the common factors.

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Step 2.1.2.7.1.7.6.1.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\cos^{3} (x) \sin (x)}{\cos^{3} (x)}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.6.1.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\frac{\sin (x)}{1}}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.7.6.2

Divide $\sin (x)$ by $1$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\sin (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.8

Cancel the common factor of $\sin (x)$ .

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Step 2.1.2.7.1.8.1

Cancel the common factor.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} \frac{\sin (x)}{\sin (x)}}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.1.8.2

Rewrite the expression.

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to {(\frac{π}{2})}^{+}} 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.7.2

Evaluate the limit of $1$ which is constant as $x$ approaches $\frac{π}{2}$ .

$\frac{\sin (lim_{x \to \frac{π}{2}} x) - 1 \cdot 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.8

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{\sin (\frac{π}{2}) - 1 \cdot 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.9

Simplify the answer.

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Step 2.1.2.9.1

Simplify each term.

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Step 2.1.2.9.1.1

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1 - 1 \cdot 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.9.1.2

Multiply $- 1$ by $1$ .

$\frac{1 - 1}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.2.9.2

Subtract $1$ from $1$ .

$\frac{0}{lim_{x \to \frac{π}{2}} \cos^{2} (x)}$

Step 2.1.3

Evaluate the limit of the denominator.

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Step 2.1.3.1

Evaluate the limit.

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Step 2.1.3.1.1

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{0}{{(lim_{x \to \frac{π}{2}} \cos (x))}^{2}}$

Step 2.1.3.1.2

Move the limit inside the trig function because cosine is continuous.

$\frac{0}{\cos^{2} (lim_{x \to \frac{π}{2}} x)}$

Step 2.1.3.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{0}{\cos^{2} (\frac{π}{2})}$

Step 2.1.3.3

Simplify the answer.

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Step 2.1.3.3.1

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{0}{0^{2}}$

Step 2.1.3.3.2

Raising $0$ to any positive power yields $0$ .

$\frac{0}{0}$

Step 2.1.3.3.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 2.1.3.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 2.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 2.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \frac{π}{2}} \frac{\sin (x) - \tan^{2} (x) \cos^{2} (x)}{\cos^{2} (x)} = lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [\sin (x) - \tan^{2} (x) \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3

Find the derivative of the numerator and denominator.

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Step 2.3.1

Differentiate the numerator and denominator.

$lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [\sin (x) - \tan^{2} (x) \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.2

By the Sum Rule, the derivative of $\sin (x) - \tan^{2} (x) \cos^{2} (x)$ with respect to $x$ is $\frac{d}{d x} [\sin (x)] + \frac{d}{d x} [- \tan^{2} (x) \cos^{2} (x)]$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [\sin (x)] + \frac{d}{d x} [- \tan^{2} (x) \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) + \frac{d}{d x} [- \tan^{2} (x) \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4

Evaluate $\frac{d}{d x} [- \tan^{2} (x) \cos^{2} (x)]$ .

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Step 2.3.4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- \tan^{2} (x) \cos^{2} (x)$ with respect to $x$ is $- \frac{d}{d x} [\tan^{2} (x) \cos^{2} (x)]$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - \frac{d}{d x} [\tan^{2} (x) \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \tan^{2} (x)$ and $g (x) = \cos^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) \frac{d}{d x} [\cos^{2} (x)] + \cos^{2} (x) \frac{d}{d x} [\tan^{2} (x)])}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.3

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \cos (x)$ .

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Step 2.3.4.3.1

To apply the Chain Rule, set $u_{1}$ as $\cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [\cos (x)]) + \cos^{2} (x) \frac{d}{d x} [\tan^{2} (x)])}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.3.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 u_{1} \frac{d}{d x} [\cos (x)]) + \cos^{2} (x) \frac{d}{d x} [\tan^{2} (x)])}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.3.3

Replace all occurrences of $u_{1}$ with $\cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) \frac{d}{d x} [\cos (x)]) + \cos^{2} (x) \frac{d}{d x} [\tan^{2} (x)])}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.4

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) (- \sin (x))) + \cos^{2} (x) \frac{d}{d x} [\tan^{2} (x)])}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.5

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \tan (x)$ .

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Step 2.3.4.5.1

To apply the Chain Rule, set $u_{2}$ as $\tan (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) (- \sin (x))) + \cos^{2} (x) (\frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d x} [\tan (x)]))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.5.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) (- \sin (x))) + \cos^{2} (x) (2 u_{2} \frac{d}{d x} [\tan (x)]))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.5.3

Replace all occurrences of $u_{2}$ with $\tan (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) (- \sin (x))) + \cos^{2} (x) (2 \tan (x) \frac{d}{d x} [\tan (x)]))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.6

The derivative of $\tan (x)$ with respect to $x$ is $\sec^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (2 \cos (x) (- \sin (x))) + \cos^{2} (x) (2 \tan (x) \sec^{2} (x)))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.7

Multiply $- 1$ by $2$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (- 2 \cos (x) \sin (x)) + \cos^{2} (x) (2 \tan (x) \sec^{2} (x)))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.4.8

Move $2$ to the left of $\cos^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (- 2 \cos (x) \sin (x)) + 2 \cos^{2} (x) \tan (x) \sec^{2} (x))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5

Simplify.

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Step 2.3.5.1

Apply the distributive property.

$lim_{x \to \frac{π}{2}} \frac{\cos (x) - (\tan^{2} (x) (- 2 \cos (x) \sin (x))) - (2 \cos^{2} (x) \tan (x) \sec^{2} (x))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.2

Combine terms.

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Step 2.3.5.2.1

Multiply $- 2$ by $- 1$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) + 2 (\tan^{2} (x) (\cos (x) \sin (x))) - (2 \cos^{2} (x) \tan (x) \sec^{2} (x))}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.2.2

Multiply $2$ by $- 1$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) + 2 \tan^{2} (x) \cos (x) \sin (x) - 2 \cos^{2} (x) \tan (x) \sec^{2} (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.3

Reorder terms.

$lim_{x \to \frac{π}{2}} \frac{2 \tan^{2} (x) \cos (x) \sin (x) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4

Simplify each term.

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Step 2.3.5.4.1

Add parentheses.

$lim_{x \to \frac{π}{2}} \frac{2 \tan^{2} (x) (\cos (x) \sin (x)) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.2

Reorder $2 \tan^{2} (x)$ and $\cos (x) \sin (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\cos (x) \sin (x) (2 \tan^{2} (x)) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.3

Add parentheses.

$lim_{x \to \frac{π}{2}} \frac{\cos (x) (\sin (x) \cdot 2) \tan^{2} (x) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.4

Reorder $\cos (x)$ and $\sin (x) \cdot 2$ .

$lim_{x \to \frac{π}{2}} \frac{\sin (x) \cdot 2 \cos (x) \tan^{2} (x) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.5

Reorder $\sin (x)$ and $2$ .

$lim_{x \to \frac{π}{2}} \frac{2 \cdot \sin (x) \cos (x) \tan^{2} (x) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.6

Apply the sine double-angle identity.

$lim_{x \to \frac{π}{2}} \frac{\sin (2 x) \tan^{2} (x) - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.7

Rewrite $\tan (x)$ in terms of sines and cosines.

$lim_{x \to \frac{π}{2}} \frac{\sin (2 x) {(\frac{\sin (x)}{\cos (x)})}^{2} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.8

Apply the product rule to $\frac{\sin (x)}{\cos (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\sin (2 x) \frac{\sin^{2} (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.9

Combine $\sin (2 x)$ and $\frac{\sin^{2} (x)}{\cos^{2} (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{\sin (2 x) \sin^{2} (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.10

Simplify the numerator.

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Step 2.3.5.4.10.1

Apply the sine double-angle identity.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin (x) \cos (x) \sin^{2} (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.10.2

Multiply $\sin (x)$ by $\sin^{2} (x)$ by adding the exponents.

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Step 2.3.5.4.10.2.1

Move $\sin^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 (\sin^{2} (x) \sin (x)) \cos (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.10.2.2

Multiply $\sin^{2} (x)$ by $\sin (x)$ .

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Step 2.3.5.4.10.2.2.1

Raise $\sin (x)$ to the power of $1$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 (\sin^{2} (x) \sin^{1} (x)) \cos (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.10.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 {\sin (x)}^{2 + 1} \cos (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.10.2.3

Add $2$ and $1$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x) \cos (x)}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.11

Cancel the common factor of $\cos (x)$ and $\cos^{2} (x)$ .

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Step 2.3.5.4.11.1

Factor $\cos (x)$ out of $2 \sin^{3} (x) \cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{\cos (x) (2 \sin^{3} (x))}{\cos^{2} (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.11.2

Cancel the common factors.

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Step 2.3.5.4.11.2.1

Factor $\cos (x)$ out of $\cos^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{\cos (x) (2 \sin^{3} (x))}{\cos (x) \cos (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.11.2.2

Cancel the common factor.

$lim_{x \to \frac{π}{2}} \frac{\frac{\cos (x) (2 \sin^{3} (x))}{\cos (x) \cos (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.11.2.3

Rewrite the expression.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \cos^{2} (x) \sec^{2} (x) \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.12

Rewrite $\sec (x)$ in terms of sines and cosines.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \cos^{2} (x) {(\frac{1}{\cos (x)})}^{2} \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.13

Apply the product rule to $\frac{1}{\cos (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \cos^{2} (x) \frac{1^{2}}{\cos^{2} (x)} \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.14

Cancel the common factor of $\cos^{2} (x)$ .

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Step 2.3.5.4.14.1

Factor $\cos^{2} (x)$ out of $- 2 \cos^{2} (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} + \cos^{2} (x) \cdot - 2 \frac{1^{2}}{\cos^{2} (x)} \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.14.2

Cancel the common factor.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} + \cos^{2} (x) \cdot - 2 \frac{1^{2}}{\cos^{2} (x)} \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.14.3

Rewrite the expression.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \cdot 1^{2} \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.15

One to any power is one.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \cdot 1 \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.16

Multiply $- 2$ by $1$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \tan (x) + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.17

Rewrite $\tan (x)$ in terms of sines and cosines.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - 2 \frac{\sin (x)}{\cos (x)} + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.18

Combine $- 2$ and $\frac{\sin (x)}{\cos (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} + \frac{- 2 \sin (x)}{\cos (x)} + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.5.4.19

Move the negative in front of the fraction.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{\frac{d}{d x} [\cos^{2} (x)]}$

Step 2.3.6

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \cos (x)$ .

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Step 2.3.6.1

To apply the Chain Rule, set $u$ as $\cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{\frac{d}{d u} [u^{2}] \frac{d}{d x} [\cos (x)]}$

Step 2.3.6.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{2 u \frac{d}{d x} [\cos (x)]}$

Step 2.3.6.3

Replace all occurrences of $u$ with $\cos (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{2 \cos (x) \frac{d}{d x} [\cos (x)]}$

Step 2.3.7

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{2 \cos (x) (- \sin (x))}$

Step 2.3.8

Multiply $- 1$ by $2$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x)}{\cos (x)} - \frac{2 \sin (x)}{\cos (x)} + \cos (x)}{- 2 \cos (x) \sin (x)}$

Step 2.4

Combine terms.

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Step 2.4.1

Combine the numerators over the common denominator.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x) - 2 \sin (x)}{\cos (x)} + \cos (x)}{- 2 \cos (x) \sin (x)}$

Step 2.4.2

To write $\cos (x)$ as a fraction with a common denominator, multiply by $\frac{\cos (x)}{\cos (x)}$ .

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x) - 2 \sin (x)}{\cos (x)} + \frac{\cos (x) \cos (x)}{\cos (x)}}{- 2 \cos (x) \sin (x)}$

Step 2.4.3

Combine the numerators over the common denominator.

$lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x) - 2 \sin (x) + \cos (x) \cos (x)}{\cos (x)}}{- 2 \cos (x) \sin (x)}$

Step 3

Evaluate the limit.

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Step 3.1

Move the term $\frac{1}{- 2}$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{\frac{2 \sin^{3} (x) - 2 \sin (x) + \cos (x) \cos (x)}{\cos (x)}}{\cos (x) \sin (x)}$

Step 3.2

Simplify the limit argument.

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Step 3.2.1

Multiply the numerator by the reciprocal of the denominator.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos (x) \cos (x)}{\cos (x)} \cdot \frac{1}{\cos (x) \sin (x)}$

Step 3.2.2

Combine factors.

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Step 3.2.2.1

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{1} (x) \cos (x)}{\cos (x)} \cdot \frac{1}{\cos (x) \sin (x)}$

Step 3.2.2.2

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{1} (x) \cos^{1} (x)}{\cos (x)} \cdot \frac{1}{\cos (x) \sin (x)}$

Step 3.2.2.3

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + {\cos (x)}^{1 + 1}}{\cos (x)} \cdot \frac{1}{\cos (x) \sin (x)}$

Step 3.2.2.4

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos (x)} \cdot \frac{1}{\cos (x) \sin (x)}$

Step 3.2.2.5

Multiply $\frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos (x)}$ by $\frac{1}{\cos (x) \sin (x)}$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos (x) \cos (x) \sin (x)}$

Step 3.2.2.6

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos^{1} (x) \cos (x) \sin (x)}$

Step 3.2.2.7

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos^{1} (x) \cos^{1} (x) \sin (x)}$

Step 3.2.2.8

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{{\cos (x)}^{1 + 1} \sin (x)}$

Step 3.2.2.9

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos^{2} (x) \sin (x)}$

Step 4

Apply L'Hospital's rule.

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Step 4.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 4.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2

Evaluate the limit of the numerator.

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Step 4.1.2.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 2 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \sin (x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.2

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{2 lim_{x \to \frac{π}{2}} \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \sin (x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.3

Move the exponent $3$ from $\sin^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{2 {(lim_{x \to \frac{π}{2}} \sin (x))}^{3} - lim_{x \to \frac{π}{2}} 2 \sin (x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.4

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} 2 \sin (x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.5

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 lim_{x \to \frac{π}{2}} \sin (x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.6

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \sin (lim_{x \to \frac{π}{2}} x) + lim_{x \to \frac{π}{2}} \cos^{2} (x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.7

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \sin (lim_{x \to \frac{π}{2}} x) + {(lim_{x \to \frac{π}{2}} \cos (x))}^{2}}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.8

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \sin (lim_{x \to \frac{π}{2}} x) + \cos^{2} (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.9

Evaluate the limits by plugging in $\frac{π}{2}$ for all occurrences of $x$ .

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Step 4.1.2.9.1

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (\frac{π}{2}) - 2 \sin (lim_{x \to \frac{π}{2}} x) + \cos^{2} (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.9.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (\frac{π}{2}) - 2 \sin (\frac{π}{2}) + \cos^{2} (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.9.3

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{2 \sin^{3} (\frac{π}{2}) - 2 \sin (\frac{π}{2}) + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10

Simplify the answer.

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Step 4.1.2.10.1

Simplify each term.

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Step 4.1.2.10.1.1

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{2 \cdot 1^{3} - 2 \sin (\frac{π}{2}) + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.2

One to any power is one.

$\frac{1}{- 2} \cdot \frac{2 \cdot 1 - 2 \sin (\frac{π}{2}) + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.3

Multiply $2$ by $1$ .

$\frac{1}{- 2} \cdot \frac{2 - 2 \sin (\frac{π}{2}) + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.4

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{2 - 2 \cdot 1 + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.5

Multiply $- 2$ by $1$ .

$\frac{1}{- 2} \cdot \frac{2 - 2 + \cos^{2} (\frac{π}{2})}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.6

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{2 - 2 + 0^{2}}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.1.7

Raising $0$ to any positive power yields $0$ .

$\frac{1}{- 2} \cdot \frac{2 - 2 + 0}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.2

Subtract $2$ from $2$ .

$\frac{1}{- 2} \cdot \frac{0 + 0}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.2.10.3

Add $0$ and $0$ .

$\frac{1}{- 2} \cdot \frac{0}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x)}$

Step 4.1.3

Evaluate the limit of the denominator.

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Step 4.1.3.1

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{0}{lim_{x \to \frac{π}{2}} \cos^{2} (x) \cdot lim_{x \to \frac{π}{2}} \sin (x)}$

Step 4.1.3.2

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{0}{{(lim_{x \to \frac{π}{2}} \cos (x))}^{2} \cdot lim_{x \to \frac{π}{2}} \sin (x)}$

Step 4.1.3.3

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{0}{\cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \sin (x)}$

Step 4.1.3.4

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{0}{\cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x)}$

Step 4.1.3.5

Evaluate the limits by plugging in $\frac{π}{2}$ for all occurrences of $x$ .

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Step 4.1.3.5.1

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{0}{\cos^{2} (\frac{π}{2}) \cdot \sin (lim_{x \to \frac{π}{2}} x)}$

Step 4.1.3.5.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{0}{\cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2})}$

Step 4.1.3.6

Simplify the answer.

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Step 4.1.3.6.1

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0^{2} \cdot \sin (\frac{π}{2})}$

Step 4.1.3.6.2

Raising $0$ to any positive power yields $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0 \cdot \sin (\frac{π}{2})}$

Step 4.1.3.6.3

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{0}{0 \cdot 1}$

Step 4.1.3.6.4

Multiply $0$ by $1$ .

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 4.1.3.6.5

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 4.1.3.7

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 4.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 4.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \frac{π}{2}} \frac{2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)}{\cos^{2} (x) \sin (x)} = lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3

Find the derivative of the numerator and denominator.

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Step 4.3.1

Differentiate the numerator and denominator.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.2

By the Sum Rule, the derivative of $2 \sin^{3} (x) - 2 \sin (x) + \cos^{2} (x)$ with respect to $x$ is $\frac{d}{d x} [2 \sin^{3} (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [2 \sin^{3} (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3

Evaluate $\frac{d}{d x} [2 \sin^{3} (x)]$ .

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Step 4.3.3.1

Since $2$ is constant with respect to $x$ , the derivative of $2 \sin^{3} (x)$ with respect to $x$ is $2 \frac{d}{d x} [\sin^{3} (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \frac{d}{d x} [\sin^{3} (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = \sin (x)$ .

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Step 4.3.3.2.1

To apply the Chain Rule, set $u_{1}$ as $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \frac{d}{d u_{1}} [{u_{1}}^{3}] \frac{d}{d x} [\sin (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 3$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \cdot 3 {u_{1}}^{2} \frac{d}{d x} [\sin (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3.2.3

Replace all occurrences of $u_{1}$ with $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \cdot 3 \sin^{2} (x) \frac{d}{d x} [\sin (x)] + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{2 \cdot 3 \sin^{2} (x) \cos (x) + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.3.4

Multiply $3$ by $2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) + \frac{d}{d x} [- 2 \sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.4

Evaluate $\frac{d}{d x} [- 2 \sin (x)]$ .

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Step 4.3.4.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 \sin (x)$ with respect to $x$ is $- 2 \frac{d}{d x} [\sin (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \frac{d}{d x} [\sin (x)] + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.4.2

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) + \frac{d}{d x} [\cos^{2} (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.5

Evaluate $\frac{d}{d x} [\cos^{2} (x)]$ .

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Step 4.3.5.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \cos (x)$ .

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Step 4.3.5.1.1

To apply the Chain Rule, set $u_{2}$ as $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) + \frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d x} [\cos (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.5.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) + 2 u_{2} \frac{d}{d x} [\cos (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.5.1.3

Replace all occurrences of $u_{2}$ with $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) + 2 \cos (x) \frac{d}{d x} [\cos (x)]}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.5.2

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) + 2 \cos (x) \cdot - 1 \sin (x)}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.5.3

Multiply $- 1$ by $2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) - 2 \cos (x) \sin (x)}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.6

Reorder terms.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\frac{d}{d x} [\cos^{2} (x) \sin (x)]}$

Step 4.3.7

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \cos^{2} (x)$ and $g (x) = \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{2} (x) \frac{d}{d x} [\sin (x)] + \sin (x) \frac{d}{d x} [\cos^{2} (x)]}$

Step 4.3.8

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{2} (x) \cos (x) + \sin (x) \frac{d}{d x} [\cos^{2} (x)]}$

Step 4.3.9

Multiply $\cos^{2} (x)$ by $\cos (x)$ by adding the exponents.

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Step 4.3.9.1

Multiply $\cos^{2} (x)$ by $\cos (x)$ .

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Step 4.3.9.1.1

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{2} (x) \cos^{1} (x) + \sin (x) \frac{d}{d x} [\cos^{2} (x)]}$

Step 4.3.9.1.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{{\cos (x)}^{2 + 1} + \sin (x) \frac{d}{d x} [\cos^{2} (x)]}$

Step 4.3.9.2

Add $2$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + \sin (x) \frac{d}{d x} [\cos^{2} (x)]}$

Step 4.3.10

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \cos (x)$ .

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Step 4.3.10.1

To apply the Chain Rule, set $u$ as $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + \sin (x) \frac{d}{d u} [u^{2}] \frac{d}{d x} [\cos (x)]}$

Step 4.3.10.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + \sin (x) \cdot 2 u \frac{d}{d x} [\cos (x)]}$

Step 4.3.10.3

Replace all occurrences of $u$ with $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + \sin (x) \cdot 2 \cos (x) \frac{d}{d x} [\cos (x)]}$

Step 4.3.11

Move $2$ to the left of $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + 2 \cdot \sin (x) \cos (x) \frac{d}{d x} [\cos (x)]}$

Step 4.3.12

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) + 2 \sin (x) \cos (x) \cdot - 1 \sin (x)}$

Step 4.3.13

Multiply $- 1$ by $2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) - 2 \sin (x) \cos (x) \sin (x)}$

Step 4.3.14

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) - 2 \sin^{1} (x) \sin (x) \cos (x)}$

Step 4.3.15

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) - 2 \sin^{1} (x) \sin^{1} (x) \cos (x)}$

Step 4.3.16

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) - 2 {\sin (x)}^{1 + 1} \cos (x)}$

Step 4.3.17

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{\cos^{3} (x) - 2 \sin^{2} (x) \cos (x)}$

Step 4.3.18

Reorder terms.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5

Apply L'Hospital's rule.

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Step 5.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 5.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2

Evaluate the limit of the numerator.

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Step 5.1.2.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 6 \sin^{2} (x) \cos (x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.2

Move the term $6$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{6 lim_{x \to \frac{π}{2}} \sin^{2} (x) \cos (x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.3

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{6 lim_{x \to \frac{π}{2}} \sin^{2} (x) \cdot lim_{x \to \frac{π}{2}} \cos (x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.4

Move the exponent $2$ from $\sin^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{6 {(lim_{x \to \frac{π}{2}} \sin (x))}^{2} \cdot lim_{x \to \frac{π}{2}} \cos (x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.5

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \cos (x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.6

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} 2 \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.7

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 lim_{x \to \frac{π}{2}} \cos (x) \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.8

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 lim_{x \to \frac{π}{2}} \cos (x) \cdot lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.9

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.10

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} 2 \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.11

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 2 lim_{x \to \frac{π}{2}} \cos (x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.12

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.13

Evaluate the limits by plugging in $\frac{π}{2}$ for all occurrences of $x$ .

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Step 5.1.2.13.1

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (\frac{π}{2}) \cdot \cos (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.13.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) - 2 \cos (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.13.3

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 2 \cos (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.13.4

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.13.5

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{6 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14

Simplify the answer.

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Step 5.1.2.14.1

Simplify each term.

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Step 5.1.2.14.1.1

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{6 \cdot 1^{2} \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.2

One to any power is one.

$\frac{1}{- 2} \cdot \frac{6 \cdot 1 \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.3

Multiply $6$ by $1$ .

$\frac{1}{- 2} \cdot \frac{6 \cdot \cos (\frac{π}{2}) - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.4

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{6 \cdot 0 - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.5

Multiply $6$ by $0$ .

$\frac{1}{- 2} \cdot \frac{0 - 2 \cos (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.6

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{0 - 2 \cdot 0 \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.7

Multiply $- 2$ by $0$ .

$\frac{1}{- 2} \cdot \frac{0 + 0 \cdot \sin (\frac{π}{2}) - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.8

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{0 + 0 \cdot 1 - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.9

Multiply $0$ by $1$ .

$\frac{1}{- 2} \cdot \frac{0 + 0 - 2 \cos (\frac{π}{2})}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.10

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{0 + 0 - 2 \cdot 0}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.1.11

Multiply $- 2$ by $0$ .

$\frac{1}{- 2} \cdot \frac{0 + 0 + 0}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.2

Add $0$ and $0$ .

$\frac{1}{- 2} \cdot \frac{0 + 0}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.2.14.3

Add $0$ and $0$ .

$\frac{1}{- 2} \cdot \frac{0}{lim_{x \to \frac{π}{2}} - 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)}$

Step 5.1.3

Evaluate the limit of the denominator.

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Step 5.1.3.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{0}{- lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) \cos (x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.2

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 lim_{x \to \frac{π}{2}} \sin^{2} (x) \cos (x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.3

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 lim_{x \to \frac{π}{2}} \sin^{2} (x) \cdot lim_{x \to \frac{π}{2}} \cos (x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.4

Move the exponent $2$ from $\sin^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{0}{- 2 {(lim_{x \to \frac{π}{2}} \sin (x))}^{2} \cdot lim_{x \to \frac{π}{2}} \cos (x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.5

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \cos (x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.6

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) + lim_{x \to \frac{π}{2}} \cos^{3} (x)}$

Step 5.1.3.7

Move the exponent $3$ from $\cos^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) + {(lim_{x \to \frac{π}{2}} \cos (x))}^{3}}$

Step 5.1.3.8

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) \cdot \cos (lim_{x \to \frac{π}{2}} x) + \cos^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 5.1.3.9

Evaluate the limits by plugging in $\frac{π}{2}$ for all occurrences of $x$ .

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Step 5.1.3.9.1

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (\frac{π}{2}) \cdot \cos (lim_{x \to \frac{π}{2}} x) + \cos^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 5.1.3.9.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) + \cos^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 5.1.3.9.3

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \sin^{2} (\frac{π}{2}) \cdot \cos (\frac{π}{2}) + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10

Simplify the answer.

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Step 5.1.3.10.1

Simplify each term.

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Step 5.1.3.10.1.1

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \cdot 1^{2} \cdot \cos (\frac{π}{2}) + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10.1.2

One to any power is one.

$\frac{1}{- 2} \cdot \frac{0}{- 2 \cdot 1 \cdot \cos (\frac{π}{2}) + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10.1.3

Multiply $- 2$ by $1$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \cdot \cos (\frac{π}{2}) + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10.1.4

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{0}{- 2 \cdot 0 + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10.1.5

Multiply $- 2$ by $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0 + \cos^{3} (\frac{π}{2})}$

Step 5.1.3.10.1.6

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0 + 0^{3}}$

Step 5.1.3.10.1.7

Raising $0$ to any positive power yields $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0 + 0}$

Step 5.1.3.10.2

Add $0$ and $0$ .

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 5.1.3.10.3

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 5.1.3.11

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 5.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{1}{- 2} \cdot \frac{0}{0}$

Step 5.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \frac{π}{2}} \frac{6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)}{- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)} = lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3

Find the derivative of the numerator and denominator.

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Step 5.3.1

Differentiate the numerator and denominator.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.2

By the Sum Rule, the derivative of $6 \sin^{2} (x) \cos (x) - 2 \cos (x) \sin (x) - 2 \cos (x)$ with respect to $x$ is $\frac{d}{d x} [6 \sin^{2} (x) \cos (x)] + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{\frac{d}{d x} [6 \sin^{2} (x) \cos (x)] + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3

Evaluate $\frac{d}{d x} [6 \sin^{2} (x) \cos (x)]$ .

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Step 5.3.3.1

Since $6$ is constant with respect to $x$ , the derivative of $6 \sin^{2} (x) \cos (x)$ with respect to $x$ is $6 \frac{d}{d x} [\sin^{2} (x) \cos (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \frac{d}{d x} [\sin^{2} (x) \cos (x)] + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \sin^{2} (x)$ and $g (x) = \cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \frac{d}{d x} [\cos (x)] + \cos (x) \frac{d}{d x} [\sin^{2} (x)]) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.3

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \frac{d}{d x} [\sin^{2} (x)]) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \sin (x)$ .

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Step 5.3.3.4.1

To apply the Chain Rule, set $u$ as $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \frac{d}{d u} [u^{2}] \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 u \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.4.3

Replace all occurrences of $u$ with $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 \sin (x) \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.5

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.6

Multiply $\sin^{2} (x)$ by $\sin (x)$ by adding the exponents.

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Step 5.3.3.6.1

Move $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin (x) \sin^{2} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.6.2

Multiply $\sin (x)$ by $\sin^{2} (x)$ .

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Step 5.3.3.6.2.1

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{1} (x) \sin^{2} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.6.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 ({\sin (x)}^{1 + 2} \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.6.3

Add $1$ and $2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (\sin^{3} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.7

Move $- 1$ to the left of $\sin^{3} (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- 1 \cdot \sin^{3} (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.8

Rewrite $- 1 \sin^{3} (x)$ as $- \sin^{3} (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.9

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{1} (x) \cos (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.10

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{1} (x) \cos^{1} (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.11

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) {\cos (x)}^{1 + 1}) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.3.12

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) + \frac{d}{d x} [- 2 \cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4

Evaluate $\frac{d}{d x} [- 2 \cos (x) \sin (x)]$ .

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Step 5.3.4.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 \cos (x) \sin (x)$ with respect to $x$ is $- 2 \frac{d}{d x} [\cos (x) \sin (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 \frac{d}{d x} [\cos (x) \sin (x)] + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.2

Differentiate using the Product Rule which states that $\frac{d}{d x} [f (x) g (x)]$ is $f (x) \frac{d}{d x} [g (x)] + g (x) \frac{d}{d x} [f (x)]$ where $f (x) = \cos (x)$ and $g (x) = \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos (x) \frac{d}{d x} [\sin (x)] + \sin (x) \frac{d}{d x} [\cos (x)]) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.3

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos (x) \cos (x) + \sin (x) \frac{d}{d x} [\cos (x)]) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.4

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos (x) \cos (x) + \sin (x) \cdot - 1 \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.5

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{1} (x) \cos (x) + \sin (x) \cdot - 1 \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.6

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{1} (x) \cos^{1} (x) + \sin (x) \cdot - 1 \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.7

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 ({\cos (x)}^{1 + 1} + \sin (x) \cdot - 1 \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.8

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) + \sin (x) \cdot - 1 \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.9

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{1} (x) \sin (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.10

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{1} (x) \sin^{1} (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.11

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - {\sin (x)}^{1 + 1}) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.4.12

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{2} (x)) + \frac{d}{d x} [- 2 \cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.5

Evaluate $\frac{d}{d x} [- 2 \cos (x)]$ .

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Step 5.3.5.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 \cos (x)$ with respect to $x$ is $- 2 \frac{d}{d x} [\cos (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{2} (x)) - 2 \frac{d}{d x} [\cos (x)]}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.5.2

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{2} (x)) - 2 \cdot - 1 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.5.3

Multiply $- 1$ by $- 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 2 (\cos^{2} (x) - \sin^{2} (x)) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6

Simplify.

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Step 5.3.6.1

Apply the distributive property.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \cdot - 1 \sin^{3} (x) + 6 \cdot 2 \sin (x) \cos^{2} (x) - 2 (\cos^{2} (x) - \sin^{2} (x)) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6.2

Apply the distributive property.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{6 \cdot - 1 \sin^{3} (x) + 6 \cdot 2 \sin (x) \cos^{2} (x) - 2 \cos^{2} (x) - 2 \cdot - 1 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6.3

Combine terms.

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Step 5.3.6.3.1

Multiply $- 1$ by $6$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{- 6 \sin^{3} (x) + 6 \cdot 2 \sin (x) \cos^{2} (x) - 2 \cos^{2} (x) - 2 \cdot - 1 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6.3.2

Multiply $2$ by $6$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{- 6 \sin^{3} (x) + 12 \sin (x) \cos^{2} (x) - 2 \cos^{2} (x) - 2 \cdot - 1 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6.3.3

Multiply $- 1$ by $- 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{- 6 \sin^{3} (x) + 12 \sin (x) \cos^{2} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.6.4

Reorder terms.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)]}$

Step 5.3.7

By the Sum Rule, the derivative of $- 2 \sin^{2} (x) \cos (x) + \cos^{3} (x)$ with respect to $x$ is $\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x)] + \frac{d}{d x} [\cos^{3} (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x)] + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8

Evaluate $\frac{d}{d x} [- 2 \sin^{2} (x) \cos (x)]$ .

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Step 5.3.8.1

Since $- 2$ is constant with respect to $x$ , the derivative of $- 2 \sin^{2} (x) \cos (x)$ with respect to $x$ is $- 2 \frac{d}{d x} [\sin^{2} (x) \cos (x)]$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 \frac{d}{d x} [\sin^{2} (x) \cos (x)] + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.2

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \frac{d}{d x} [\cos (x)] + \cos (x) \frac{d}{d x} [\sin^{2} (x)]) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.3

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \frac{d}{d x} [\sin^{2} (x)]) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = \sin (x)$ .

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Step 5.3.8.4.1

To apply the Chain Rule, set $u_{1}$ as $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 u_{1} \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.4.3

Replace all occurrences of $u_{1}$ with $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 \sin (x) \frac{d}{d x} [\sin (x)]) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.5

The derivative of $\sin (x)$ with respect to $x$ is $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{2} (x) \cdot - 1 \sin (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.6

Multiply $\sin^{2} (x)$ by $\sin (x)$ by adding the exponents.

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Step 5.3.8.6.1

Move $\sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin (x) \sin^{2} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.6.2

Multiply $\sin (x)$ by $\sin^{2} (x)$ .

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Step 5.3.8.6.2.1

Raise $\sin (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{1} (x) \sin^{2} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.6.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 ({\sin (x)}^{1 + 2} \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.6.3

Add $1$ and $2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (\sin^{3} (x) \cdot - 1 + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.7

Move $- 1$ to the left of $\sin^{3} (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- 1 \cdot \sin^{3} (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.8

Rewrite $- 1 \sin^{3} (x)$ as $- \sin^{3} (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + \cos (x) \cdot 2 \sin (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.9

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{1} (x) \cos (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.10

Raise $\cos (x)$ to the power of $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{1} (x) \cos^{1} (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.11

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) {\cos (x)}^{1 + 1}) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.8.12

Add $1$ and $1$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) + \frac{d}{d x} [\cos^{3} (x)]}$

Step 5.3.9

Evaluate $\frac{d}{d x} [\cos^{3} (x)]$ .

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Step 5.3.9.1

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{3}$ and $g (x) = \cos (x)$ .

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Step 5.3.9.1.1

To apply the Chain Rule, set $u_{2}$ as $\cos (x)$ .

Step 5.3.9.1.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 3$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) + 3 {u_{2}}^{2} \frac{d}{d x} [\cos (x)]}$

Step 5.3.9.1.3

Replace all occurrences of $u_{2}$ with $\cos (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) + 3 \cos^{2} (x) \frac{d}{d x} [\cos (x)]}$

Step 5.3.9.2

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

Step 5.3.9.3

Multiply $- 1$ by $3$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 (- \sin^{3} (x) + 2 \sin (x) \cos^{2} (x)) - 3 \cos^{2} (x) \sin (x)}$

Step 5.3.10

Simplify.

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Step 5.3.10.1

Apply the distributive property.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 2 \cdot - 1 \sin^{3} (x) - 2 \cdot 2 \sin (x) \cos^{2} (x) - 3 \cos^{2} (x) \sin (x)}$

Step 5.3.10.2

Combine terms.

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Step 5.3.10.2.1

Multiply $- 1$ by $- 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{2 \sin^{3} (x) - 2 \cdot 2 \sin (x) \cos^{2} (x) - 3 \cos^{2} (x) \sin (x)}$

Step 5.3.10.2.2

Multiply $2$ by $- 2$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{2 \sin^{3} (x) - 4 \sin (x) \cos^{2} (x) - 3 \cos^{2} (x) \sin (x)}$

Step 5.3.10.2.3

Reorder the factors of $- 4 \sin (x) \cos^{2} (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{2 \sin^{3} (x) - 4 \cos^{2} (x) \sin (x) - 3 \cos^{2} (x) \sin (x)}$

Step 5.3.10.2.4

Subtract $3 \cos^{2} (x) \sin (x)$ from $- 4 \cos^{2} (x) \sin (x)$ .

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{2 \sin^{3} (x) - 7 \cos^{2} (x) \sin (x)}$

Step 5.3.10.3

Reorder terms.

$\frac{1}{- 2} lim_{x \to \frac{π}{2}} \frac{12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{- 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6

Evaluate the limit.

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Step 6.1

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 12 \cos^{2} (x) \sin (x) - 6 \sin^{3} (x) - 2 \cos^{2} (x) + 2 \sin^{2} (x) + 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{lim_{x \to \frac{π}{2}} 12 \cos^{2} (x) \sin (x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.3

Move the term $12$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.4

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{12 lim_{x \to \frac{π}{2}} \cos^{2} (x) \cdot lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.5

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 {(lim_{x \to \frac{π}{2}} \cos (x))}^{2} \cdot lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.6

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \sin (x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.7

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} 6 \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.8

Move the term $6$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 lim_{x \to \frac{π}{2}} \sin^{3} (x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.9

Move the exponent $3$ from $\sin^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 {(lim_{x \to \frac{π}{2}} \sin (x))}^{3} - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.10

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - lim_{x \to \frac{π}{2}} 2 \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.11

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 lim_{x \to \frac{π}{2}} \cos^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.12

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 {(lim_{x \to \frac{π}{2}} \cos (x))}^{2} + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.13

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + lim_{x \to \frac{π}{2}} 2 \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.14

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 lim_{x \to \frac{π}{2}} \sin^{2} (x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.15

Move the exponent $2$ from $\sin^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 {(lim_{x \to \frac{π}{2}} \sin (x))}^{2} + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.16

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + lim_{x \to \frac{π}{2}} 2 \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.17

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 lim_{x \to \frac{π}{2}} \sin (x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.18

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{lim_{x \to \frac{π}{2}} - 7 \cos^{2} (x) \sin (x) + 2 \sin^{3} (x)}$

Step 6.19

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- lim_{x \to \frac{π}{2}} 7 \cos^{2} (x) \sin (x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.20

Move the term $7$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 lim_{x \to \frac{π}{2}} \cos^{2} (x) \sin (x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.21

Split the limit using the Product of Limits Rule on the limit as $x$ approaches $\frac{π}{2}$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 lim_{x \to \frac{π}{2}} \cos^{2} (x) \cdot lim_{x \to \frac{π}{2}} \sin (x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.22

Move the exponent $2$ from $\cos^{2} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 {(lim_{x \to \frac{π}{2}} \cos (x))}^{2} \cdot lim_{x \to \frac{π}{2}} \sin (x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.23

Move the limit inside the trig function because cosine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot lim_{x \to \frac{π}{2}} \sin (x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.24

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + lim_{x \to \frac{π}{2}} 2 \sin^{3} (x)}$

Step 6.25

Move the term $2$ outside of the limit because it is constant with respect to $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 lim_{x \to \frac{π}{2}} \sin^{3} (x)}$

Step 6.26

Move the exponent $3$ from $\sin^{3} (x)$ outside the limit using the Limits Power Rule.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 {(lim_{x \to \frac{π}{2}} \sin (x))}^{3}}$

Step 6.27

Move the limit inside the trig function because sine is continuous.

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7

Evaluate the limits by plugging in $\frac{π}{2}$ for all occurrences of $x$ .

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Step 7.1

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (lim_{x \to \frac{π}{2}} x) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.2

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (lim_{x \to \frac{π}{2}} x) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.3

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.4

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (lim_{x \to \frac{π}{2}} x) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.5

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (lim_{x \to \frac{π}{2}} x)}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.6

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (lim_{x \to \frac{π}{2}} x) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.7

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (lim_{x \to \frac{π}{2}} x) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.8

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (lim_{x \to \frac{π}{2}} x)}$

Step 7.9

Evaluate the limit of $x$ by plugging in $\frac{π}{2}$ for $x$ .

$\frac{1}{- 2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8

Simplify the answer.

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Step 8.1

Move the negative in front of the fraction.

$- \frac{1}{2} \cdot \frac{12 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2

Simplify the numerator.

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Step 8.2.1

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$- \frac{1}{2} \cdot \frac{12 \cdot 0^{2} \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.2

Raising $0$ to any positive power yields $0$ .

$- \frac{1}{2} \cdot \frac{12 \cdot 0 \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.3

Multiply $12$ by $0$ .

$- \frac{1}{2} \cdot \frac{0 \cdot \sin (\frac{π}{2}) - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.4

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{0 \cdot 1 - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.5

Multiply $0$ by $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 \sin^{3} (\frac{π}{2}) - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.6

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 \cdot 1^{3} - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.7

One to any power is one.

$- \frac{1}{2} \cdot \frac{0 - 6 \cdot 1 - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.8

Multiply $- 6$ by $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 - 2 \cos^{2} (\frac{π}{2}) + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.9

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$- \frac{1}{2} \cdot \frac{0 - 6 - 2 \cdot 0^{2} + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.10

Raising $0$ to any positive power yields $0$ .

$- \frac{1}{2} \cdot \frac{0 - 6 - 2 \cdot 0 + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.11

Multiply $- 2$ by $0$ .

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 \sin^{2} (\frac{π}{2}) + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.12

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 \cdot 1^{2} + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.13

One to any power is one.

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 \cdot 1 + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.14

Multiply $2$ by $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 + 2 \sin (\frac{π}{2})}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.15

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 + 2 \cdot 1}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.16

Multiply $2$ by $1$ .

$- \frac{1}{2} \cdot \frac{0 - 6 + 0 + 2 + 2}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.17

Subtract $6$ from $0$ .

$- \frac{1}{2} \cdot \frac{- 6 + 0 + 2 + 2}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.18

Add $- 6$ and $0$ .

$- \frac{1}{2} \cdot \frac{- 6 + 2 + 2}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.19

Add $- 6$ and $2$ .

$- \frac{1}{2} \cdot \frac{- 4 + 2}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.2.20

Add $- 4$ and $2$ .

$- \frac{1}{2} \cdot \frac{- 2}{- 7 \cos^{2} (\frac{π}{2}) \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3

Simplify the denominator.

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Step 8.3.1

The exact value of $\cos (\frac{π}{2})$ is $0$ .

$- \frac{1}{2} \cdot \frac{- 2}{- 7 \cdot 0^{2} \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3.2

Raising $0$ to any positive power yields $0$ .

$- \frac{1}{2} \cdot \frac{- 2}{- 7 \cdot 0 \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3.3

Multiply $- 7$ by $0$ .

$- \frac{1}{2} \cdot \frac{- 2}{0 \cdot \sin (\frac{π}{2}) + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3.4

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{- 2}{0 \cdot 1 + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3.5

Multiply $0$ by $1$ .

$- \frac{1}{2} \cdot \frac{- 2}{0 + 2 \sin^{3} (\frac{π}{2})}$

Step 8.3.6

The exact value of $\sin (\frac{π}{2})$ is $1$ .

$- \frac{1}{2} \cdot \frac{- 2}{0 + 2 \cdot 1^{3}}$

Step 8.3.7

One to any power is one.

$- \frac{1}{2} \cdot \frac{- 2}{0 + 2 \cdot 1}$

Step 8.3.8

Multiply $2$ by $1$ .

$- \frac{1}{2} \cdot \frac{- 2}{0 + 2}$

Step 8.3.9

Add $0$ and $2$ .

$- \frac{1}{2} \cdot \frac{- 2}{2}$

Step 8.4

Cancel the common factor of $- 2$ and $2$ .

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Step 8.4.1

Factor $2$ out of $- 2$ .

$- \frac{1}{2} \cdot \frac{2 \cdot - 1}{2}$

Step 8.4.2

Cancel the common factors.

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Step 8.4.2.1

Factor $2$ out of $2$ .

$- \frac{1}{2} \cdot \frac{2 \cdot - 1}{2 (1)}$

Step 8.4.2.2

Cancel the common factor.

$- \frac{1}{2} \cdot \frac{2 \cdot - 1}{2 \cdot 1}$

Step 8.4.2.3

Rewrite the expression.

$- \frac{1}{2} \cdot \frac{- 1}{1}$

Step 8.4.2.4

Divide $- 1$ by $1$ .

$- \frac{1}{2} \cdot - 1$

Step 8.5

Multiply $- \frac{1}{2} \cdot - 1$ .

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Step 8.5.1

Multiply $- 1$ by $- 1$ .

$1 (\frac{1}{2})$

Step 8.5.2

Multiply $\frac{1}{2}$ by $1$ .

$\frac{1}{2}$

Step 9

The result can be shown in multiple forms.

Exact Form:

$\frac{1}{2}$

Decimal Form:

$0.5$