Calculus Examples

$lim_{x \to \frac{- 2}{3}} \frac{6 x^{3} - 17 x^{2} - 5 x + 6}{9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1

Apply L'Hospital's rule.

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Step 1.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 1.1.1

Take the limit of the numerator and the limit of the denominator.

$\frac{lim_{x \to \frac{- 2}{3}} 6 x^{3} - 17 x^{2} - 5 x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2

Evaluate the limit of the numerator.

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Step 1.1.2.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{- 2}{3}$ .

$\frac{lim_{x \to \frac{- 2}{3}} 6 x^{3} - lim_{x \to \frac{- 2}{3}} 17 x^{2} - lim_{x \to \frac{- 2}{3}} 5 x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.2

Move the term $6$ outside of the limit because it is constant with respect to $x$ .

$\frac{6 lim_{x \to \frac{- 2}{3}} x^{3} - lim_{x \to \frac{- 2}{3}} 17 x^{2} - lim_{x \to \frac{- 2}{3}} 5 x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.3

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{6 {(lim_{x \to \frac{- 2}{3}} x)}^{3} - lim_{x \to \frac{- 2}{3}} 17 x^{2} - lim_{x \to \frac{- 2}{3}} 5 x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.4

Move the term $17$ outside of the limit because it is constant with respect to $x$ .

$\frac{6 {(lim_{x \to \frac{- 2}{3}} x)}^{3} - 17 lim_{x \to \frac{- 2}{3}} x^{2} - lim_{x \to \frac{- 2}{3}} 5 x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.5

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{6 {(lim_{x \to \frac{- 2}{3}} x)}^{3} - 17 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - lim_{x \to \frac{- 2}{3}} 5 x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.6

Move the term $5$ outside of the limit because it is constant with respect to $x$ .

$\frac{6 {(lim_{x \to \frac{- 2}{3}} x)}^{3} - 17 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + lim_{x \to \frac{- 2}{3}} 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.7

Evaluate the limit of $6$ which is constant as $x$ approaches $\frac{- 2}{3}$ .

$\frac{6 {(lim_{x \to \frac{- 2}{3}} x)}^{3} - 17 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8

Evaluate the limits by plugging in $\frac{- 2}{3}$ for all occurrences of $x$ .

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Step 1.1.2.8.1

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{6 {(\frac{- 2}{3})}^{3} - 17 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8.2

Move the negative in front of the fraction.

$\frac{6 {(- \frac{2}{3})}^{3} - 17 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8.3

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{6 {(- \frac{2}{3})}^{3} - 17 {(\frac{- 2}{3})}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8.4

Move the negative in front of the fraction.

$\frac{6 {(- \frac{2}{3})}^{3} - 17 {(- \frac{2}{3})}^{2} - 5 lim_{x \to \frac{- 2}{3}} x + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8.5

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{6 {(- \frac{2}{3})}^{3} - 17 {(- \frac{2}{3})}^{2} - 5 (\frac{- 2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.8.6

Move the negative in front of the fraction.

$\frac{6 {(- \frac{2}{3})}^{3} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9

Simplify the answer.

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Step 1.1.2.9.1

Simplify each term.

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Step 1.1.2.9.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.1.2.9.1.1.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{6 ({(- 1)}^{3} {(\frac{2}{3})}^{3}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.1.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{6 ({(- 1)}^{3} \frac{2^{3}}{3^{3}}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.2

Raise $- 1$ to the power of $3$ .

$\frac{6 (- \frac{2^{3}}{3^{3}}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.3

Raise $2$ to the power of $3$ .

$\frac{6 (- \frac{8}{3^{3}}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.4

Raise $3$ to the power of $3$ .

$\frac{6 (- \frac{8}{27}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.5

Cancel the common factor of $3$ .

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Step 1.1.2.9.1.5.1

Move the leading negative in $- \frac{8}{27}$ into the numerator.

$\frac{6 (\frac{- 8}{27}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.5.2

Factor $3$ out of $6$ .

$\frac{3 (2) \frac{- 8}{27} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.5.3

Factor $3$ out of $27$ .

$\frac{3 \cdot 2 \frac{- 8}{3 \cdot 9} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.5.4

Cancel the common factor.

$\frac{3 \cdot 2 \frac{- 8}{3 \cdot 9} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.5.5

Rewrite the expression.

$\frac{2 (\frac{- 8}{9}) - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.6

Combine $2$ and $\frac{- 8}{9}$ .

$\frac{\frac{2 \cdot - 8}{9} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.7

Multiply $2$ by $- 8$ .

$\frac{\frac{- 16}{9} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.8

Move the negative in front of the fraction.

$\frac{- \frac{16}{9} - 17 {(- \frac{2}{3})}^{2} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.9

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.1.2.9.1.9.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{- \frac{16}{9} - 17 ({(- 1)}^{2} {(\frac{2}{3})}^{2}) - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.9.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{- \frac{16}{9} - 17 ({(- 1)}^{2} \frac{2^{2}}{3^{2}}) - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.10

Raise $- 1$ to the power of $2$ .

$\frac{- \frac{16}{9} - 17 (1 \frac{2^{2}}{3^{2}}) - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.11

Multiply $\frac{2^{2}}{3^{2}}$ by $1$ .

$\frac{- \frac{16}{9} - 17 \frac{2^{2}}{3^{2}} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.12

Raise $2$ to the power of $2$ .

$\frac{- \frac{16}{9} - 17 \frac{4}{3^{2}} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.13

Raise $3$ to the power of $2$ .

$\frac{- \frac{16}{9} - 17 (\frac{4}{9}) - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.14

Multiply $- 17 (\frac{4}{9})$ .

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Step 1.1.2.9.1.14.1

Combine $- 17$ and $\frac{4}{9}$ .

$\frac{- \frac{16}{9} + \frac{- 17 \cdot 4}{9} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.14.2

Multiply $- 17$ by $4$ .

$\frac{- \frac{16}{9} + \frac{- 68}{9} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.15

Move the negative in front of the fraction.

$\frac{- \frac{16}{9} - \frac{68}{9} - 5 (- \frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.16

Multiply $- 5 (- \frac{2}{3})$ .

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Step 1.1.2.9.1.16.1

Multiply $- 1$ by $- 5$ .

$\frac{- \frac{16}{9} - \frac{68}{9} + 5 (\frac{2}{3}) + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.16.2

Combine $5$ and $\frac{2}{3}$ .

$\frac{- \frac{16}{9} - \frac{68}{9} + \frac{5 \cdot 2}{3} + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.1.16.3

Multiply $5$ by $2$ .

$\frac{- \frac{16}{9} - \frac{68}{9} + \frac{10}{3} + 6}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.2

Combine the numerators over the common denominator.

$\frac{6 + \frac{- 16 - 68}{9} + \frac{10}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.3

Subtract $68$ from $- 16$ .

$\frac{6 + \frac{- 84}{9} + \frac{10}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4

Find the common denominator.

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Step 1.1.2.9.4.1

Write $6$ as a fraction with denominator $1$ .

$\frac{\frac{6}{1} + \frac{- 84}{9} + \frac{10}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4.2

Multiply $\frac{6}{1}$ by $\frac{9}{9}$ .

$\frac{\frac{6}{1} \cdot \frac{9}{9} + \frac{- 84}{9} + \frac{10}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4.3

Multiply $\frac{6}{1}$ by $\frac{9}{9}$ .

$\frac{\frac{6 \cdot 9}{9} + \frac{- 84}{9} + \frac{10}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4.4

Multiply $\frac{10}{3}$ by $\frac{3}{3}$ .

$\frac{\frac{6 \cdot 9}{9} + \frac{- 84}{9} + \frac{10}{3} \cdot \frac{3}{3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4.5

Multiply $\frac{10}{3}$ by $\frac{3}{3}$ .

$\frac{\frac{6 \cdot 9}{9} + \frac{- 84}{9} + \frac{10 \cdot 3}{3 \cdot 3}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.4.6

Multiply $3$ by $3$ .

$\frac{\frac{6 \cdot 9}{9} + \frac{- 84}{9} + \frac{10 \cdot 3}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.5

Combine the numerators over the common denominator.

$\frac{\frac{6 \cdot 9 - 84 + 10 \cdot 3}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.6

Simplify each term.

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Step 1.1.2.9.6.1

Multiply $6$ by $9$ .

$\frac{\frac{54 - 84 + 10 \cdot 3}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.6.2

Multiply $10$ by $3$ .

$\frac{\frac{54 - 84 + 30}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.7

Subtract $84$ from $54$ .

$\frac{\frac{- 30 + 30}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.8

Add $- 30$ and $30$ .

$\frac{\frac{0}{9}}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.2.9.9

Divide $0$ by $9$ .

$\frac{0}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + 36 x^{2} - 4 x - 16}$

Step 1.1.3

Evaluate the limit of the denominator.

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Step 1.1.3.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{- 2}{3}$ .

$\frac{0}{lim_{x \to \frac{- 2}{3}} 9 x^{3} + lim_{x \to \frac{- 2}{3}} 36 x^{2} - lim_{x \to \frac{- 2}{3}} 4 x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.2

Move the term $9$ outside of the limit because it is constant with respect to $x$ .

$\frac{0}{9 lim_{x \to \frac{- 2}{3}} x^{3} + lim_{x \to \frac{- 2}{3}} 36 x^{2} - lim_{x \to \frac{- 2}{3}} 4 x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.3

Move the exponent $3$ from $x^{3}$ outside the limit using the Limits Power Rule.

$\frac{0}{9 {(lim_{x \to \frac{- 2}{3}} x)}^{3} + lim_{x \to \frac{- 2}{3}} 36 x^{2} - lim_{x \to \frac{- 2}{3}} 4 x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.4

Move the term $36$ outside of the limit because it is constant with respect to $x$ .

$\frac{0}{9 {(lim_{x \to \frac{- 2}{3}} x)}^{3} + 36 lim_{x \to \frac{- 2}{3}} x^{2} - lim_{x \to \frac{- 2}{3}} 4 x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.5

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{0}{9 {(lim_{x \to \frac{- 2}{3}} x)}^{3} + 36 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - lim_{x \to \frac{- 2}{3}} 4 x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.6

Move the term $4$ outside of the limit because it is constant with respect to $x$ .

$\frac{0}{9 {(lim_{x \to \frac{- 2}{3}} x)}^{3} + 36 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - lim_{x \to \frac{- 2}{3}} 16}$

Step 1.1.3.7

Evaluate the limit of $16$ which is constant as $x$ approaches $\frac{- 2}{3}$ .

$\frac{0}{9 {(lim_{x \to \frac{- 2}{3}} x)}^{3} + 36 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 16}$

Step 1.1.3.8

Evaluate the limits by plugging in $\frac{- 2}{3}$ for all occurrences of $x$ .

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Step 1.1.3.8.1

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{0}{9 {(\frac{- 2}{3})}^{3} + 36 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 16}$

Step 1.1.3.8.2

Move the negative in front of the fraction.

$\frac{0}{9 {(- \frac{2}{3})}^{3} + 36 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 16}$

Step 1.1.3.8.3

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{0}{9 {(- \frac{2}{3})}^{3} + 36 {(\frac{- 2}{3})}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 16}$

Step 1.1.3.8.4

Move the negative in front of the fraction.

$\frac{0}{9 {(- \frac{2}{3})}^{3} + 36 {(- \frac{2}{3})}^{2} - 4 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 16}$

Step 1.1.3.8.5

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{0}{9 {(- \frac{2}{3})}^{3} + 36 {(- \frac{2}{3})}^{2} - 4 (\frac{- 2}{3}) - 1 \cdot 16}$

Step 1.1.3.8.6

Move the negative in front of the fraction.

$\frac{0}{9 {(- \frac{2}{3})}^{3} + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9

Simplify the answer.

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Step 1.1.3.9.1

Simplify each term.

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Step 1.1.3.9.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.1.3.9.1.1.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{0}{9 ({(- 1)}^{3} {(\frac{2}{3})}^{3}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.1.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{0}{9 ({(- 1)}^{3} \frac{2^{3}}{3^{3}}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.2

Raise $- 1$ to the power of $3$ .

$\frac{0}{9 (- \frac{2^{3}}{3^{3}}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.3

Raise $2$ to the power of $3$ .

$\frac{0}{9 (- \frac{8}{3^{3}}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.4

Raise $3$ to the power of $3$ .

$\frac{0}{9 (- \frac{8}{27}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.5

Cancel the common factor of $9$ .

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Step 1.1.3.9.1.5.1

Move the leading negative in $- \frac{8}{27}$ into the numerator.

$\frac{0}{9 (\frac{- 8}{27}) + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.5.2

Factor $9$ out of $27$ .

$\frac{0}{9 \frac{- 8}{9 (3)} + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.5.3

Cancel the common factor.

$\frac{0}{9 \frac{- 8}{9 \cdot 3} + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.5.4

Rewrite the expression.

$\frac{0}{\frac{- 8}{3} + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.6

Move the negative in front of the fraction.

$\frac{0}{- \frac{8}{3} + 36 {(- \frac{2}{3})}^{2} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.7

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 1.1.3.9.1.7.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{0}{- \frac{8}{3} + 36 ({(- 1)}^{2} {(\frac{2}{3})}^{2}) - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.7.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{0}{- \frac{8}{3} + 36 ({(- 1)}^{2} \frac{2^{2}}{3^{2}}) - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.8

Raise $- 1$ to the power of $2$ .

$\frac{0}{- \frac{8}{3} + 36 (1 \frac{2^{2}}{3^{2}}) - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.9

Multiply $\frac{2^{2}}{3^{2}}$ by $1$ .

$\frac{0}{- \frac{8}{3} + 36 \frac{2^{2}}{3^{2}} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.10

Raise $2$ to the power of $2$ .

$\frac{0}{- \frac{8}{3} + 36 \frac{4}{3^{2}} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.11

Raise $3$ to the power of $2$ .

$\frac{0}{- \frac{8}{3} + 36 (\frac{4}{9}) - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.12

Cancel the common factor of $9$ .

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Step 1.1.3.9.1.12.1

Factor $9$ out of $36$ .

$\frac{0}{- \frac{8}{3} + 9 (4) \frac{4}{9} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.12.2

Cancel the common factor.

$\frac{0}{- \frac{8}{3} + 9 \cdot 4 \frac{4}{9} - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.12.3

Rewrite the expression.

$\frac{0}{- \frac{8}{3} + 4 \cdot 4 - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.13

Multiply $4$ by $4$ .

$\frac{0}{- \frac{8}{3} + 16 - 4 (- \frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.14

Multiply $- 4 (- \frac{2}{3})$ .

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Step 1.1.3.9.1.14.1

Multiply $- 1$ by $- 4$ .

$\frac{0}{- \frac{8}{3} + 16 + 4 (\frac{2}{3}) - 1 \cdot 16}$

Step 1.1.3.9.1.14.2

Combine $4$ and $\frac{2}{3}$ .

$\frac{0}{- \frac{8}{3} + 16 + \frac{4 \cdot 2}{3} - 1 \cdot 16}$

Step 1.1.3.9.1.14.3

Multiply $4$ by $2$ .

$\frac{0}{- \frac{8}{3} + 16 + \frac{8}{3} - 1 \cdot 16}$

Step 1.1.3.9.1.15

Multiply $- 1$ by $16$ .

$\frac{0}{- \frac{8}{3} + 16 + \frac{8}{3} - 16}$

Step 1.1.3.9.2

Combine the numerators over the common denominator.

$\frac{0}{16 - 16 + \frac{- 8 + 8}{3}}$

Step 1.1.3.9.3

Add $- 8$ and $8$ .

$\frac{0}{16 - 16 + \frac{0}{3}}$

Step 1.1.3.9.4

Find the common denominator.

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Step 1.1.3.9.4.1

Write $16$ as a fraction with denominator $1$ .

$\frac{0}{\frac{16}{1} - 16 + \frac{0}{3}}$

Step 1.1.3.9.4.2

Multiply $\frac{16}{1}$ by $\frac{3}{3}$ .

$\frac{0}{\frac{16}{1} \cdot \frac{3}{3} - 16 + \frac{0}{3}}$

Step 1.1.3.9.4.3

Multiply $\frac{16}{1}$ by $\frac{3}{3}$ .

$\frac{0}{\frac{16 \cdot 3}{3} - 16 + \frac{0}{3}}$

Step 1.1.3.9.4.4

Write $- 16$ as a fraction with denominator $1$ .

$\frac{0}{\frac{16 \cdot 3}{3} + \frac{- 16}{1} + \frac{0}{3}}$

Step 1.1.3.9.4.5

Multiply $\frac{- 16}{1}$ by $\frac{3}{3}$ .

$\frac{0}{\frac{16 \cdot 3}{3} + \frac{- 16}{1} \cdot \frac{3}{3} + \frac{0}{3}}$

Step 1.1.3.9.4.6

Multiply $\frac{- 16}{1}$ by $\frac{3}{3}$ .

$\frac{0}{\frac{16 \cdot 3}{3} + \frac{- 16 \cdot 3}{3} + \frac{0}{3}}$

Step 1.1.3.9.5

Combine the numerators over the common denominator.

$\frac{0}{\frac{16 \cdot 3 - 16 \cdot 3}{3}}$

Step 1.1.3.9.6

Simplify each term.

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Step 1.1.3.9.6.1

Multiply $16$ by $3$ .

$\frac{0}{\frac{48 - 16 \cdot 3}{3}}$

Step 1.1.3.9.6.2

Multiply $- 16$ by $3$ .

$\frac{0}{\frac{48 - 48}{3}}$

Step 1.1.3.9.7

Subtract $48$ from $48$ .

$\frac{0}{\frac{0}{3}}$

Step 1.1.3.9.8

Divide $0$ by $3$ .

$\frac{0}{0}$

Step 1.1.3.9.9

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.1.3.10

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$\frac{0}{0}$

Step 1.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to \frac{- 2}{3}} \frac{6 x^{3} - 17 x^{2} - 5 x + 6}{9 x^{3} + 36 x^{2} - 4 x - 16} = lim_{x \to \frac{- 2}{3}} \frac{\frac{d}{d x} [6 x^{3} - 17 x^{2} - 5 x + 6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3

Find the derivative of the numerator and denominator.

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Step 1.3.1

Differentiate the numerator and denominator.

$lim_{x \to \frac{- 2}{3}} \frac{\frac{d}{d x} [6 x^{3} - 17 x^{2} - 5 x + 6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.2

By the Sum Rule, the derivative of $6 x^{3} - 17 x^{2} - 5 x + 6$ with respect to $x$ is $\frac{d}{d x} [6 x^{3}] + \frac{d}{d x} [- 17 x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]$ .

$lim_{x \to \frac{- 2}{3}} \frac{\frac{d}{d x} [6 x^{3}] + \frac{d}{d x} [- 17 x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.3

Evaluate $\frac{d}{d x} [6 x^{3}]$ .

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Step 1.3.3.1

Since $6$ is constant with respect to $x$ , the derivative of $6 x^{3}$ with respect to $x$ is $6 \frac{d}{d x} [x^{3}]$ .

$lim_{x \to \frac{- 2}{3}} \frac{6 \frac{d}{d x} [x^{3}] + \frac{d}{d x} [- 17 x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.3.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to \frac{- 2}{3}} \frac{6 (3 x^{2}) + \frac{d}{d x} [- 17 x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.3.3

Multiply $3$ by $6$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} + \frac{d}{d x} [- 17 x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.4

Evaluate $\frac{d}{d x} [- 17 x^{2}]$ .

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Step 1.3.4.1

Since $- 17$ is constant with respect to $x$ , the derivative of $- 17 x^{2}$ with respect to $x$ is $- 17 \frac{d}{d x} [x^{2}]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 17 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.4.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 17 (2 x) + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.4.3

Multiply $2$ by $- 17$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x + \frac{d}{d x} [- 5 x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.5

Evaluate $\frac{d}{d x} [- 5 x]$ .

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Step 1.3.5.1

Since $- 5$ is constant with respect to $x$ , the derivative of $- 5 x$ with respect to $x$ is $- 5 \frac{d}{d x} [x]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5 \frac{d}{d x} [x] + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.5.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5 \cdot 1 + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.5.3

Multiply $- 5$ by $1$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5 + \frac{d}{d x} [6]}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.6

Since $6$ is constant with respect to $x$ , the derivative of $6$ with respect to $x$ is $0$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5 + 0}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.7

Add $18 x^{2} - 34 x - 5$ and $0$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{\frac{d}{d x} [9 x^{3} + 36 x^{2} - 4 x - 16]}$

Step 1.3.8

By the Sum Rule, the derivative of $9 x^{3} + 36 x^{2} - 4 x - 16$ with respect to $x$ is $\frac{d}{d x} [9 x^{3}] + \frac{d}{d x} [36 x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{\frac{d}{d x} [9 x^{3}] + \frac{d}{d x} [36 x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.9

Evaluate $\frac{d}{d x} [9 x^{3}]$ .

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Step 1.3.9.1

Since $9$ is constant with respect to $x$ , the derivative of $9 x^{3}$ with respect to $x$ is $9 \frac{d}{d x} [x^{3}]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{9 \frac{d}{d x} [x^{3}] + \frac{d}{d x} [36 x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.9.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 3$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{9 (3 x^{2}) + \frac{d}{d x} [36 x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.9.3

Multiply $3$ by $9$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + \frac{d}{d x} [36 x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.10

Evaluate $\frac{d}{d x} [36 x^{2}]$ .

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Step 1.3.10.1

Since $36$ is constant with respect to $x$ , the derivative of $36 x^{2}$ with respect to $x$ is $36 \frac{d}{d x} [x^{2}]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 36 \frac{d}{d x} [x^{2}] + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.10.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 36 (2 x) + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.10.3

Multiply $2$ by $36$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x + \frac{d}{d x} [- 4 x] + \frac{d}{d x} [- 16]}$

Step 1.3.11

Evaluate $\frac{d}{d x} [- 4 x]$ .

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Step 1.3.11.1

Since $- 4$ is constant with respect to $x$ , the derivative of $- 4 x$ with respect to $x$ is $- 4 \frac{d}{d x} [x]$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x - 4 \frac{d}{d x} [x] + \frac{d}{d x} [- 16]}$

Step 1.3.11.2

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 1$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x - 4 \cdot 1 + \frac{d}{d x} [- 16]}$

Step 1.3.11.3

Multiply $- 4$ by $1$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x - 4 + \frac{d}{d x} [- 16]}$

Step 1.3.12

Since $- 16$ is constant with respect to $x$ , the derivative of $- 16$ with respect to $x$ is $0$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x - 4 + 0}$

Step 1.3.13

Add $27 x^{2} + 72 x - 4$ and $0$ .

$lim_{x \to \frac{- 2}{3}} \frac{18 x^{2} - 34 x - 5}{27 x^{2} + 72 x - 4}$

Step 2

Evaluate the limit.

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Step 2.1

Split the limit using the Limits Quotient Rule on the limit as $x$ approaches $\frac{- 2}{3}$ .

$\frac{lim_{x \to \frac{- 2}{3}} 18 x^{2} - 34 x - 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.2

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{- 2}{3}$ .

$\frac{lim_{x \to \frac{- 2}{3}} 18 x^{2} - lim_{x \to \frac{- 2}{3}} 34 x - lim_{x \to \frac{- 2}{3}} 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.3

Move the term $18$ outside of the limit because it is constant with respect to $x$ .

$\frac{18 lim_{x \to \frac{- 2}{3}} x^{2} - lim_{x \to \frac{- 2}{3}} 34 x - lim_{x \to \frac{- 2}{3}} 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.4

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - lim_{x \to \frac{- 2}{3}} 34 x - lim_{x \to \frac{- 2}{3}} 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.5

Move the term $34$ outside of the limit because it is constant with respect to $x$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - lim_{x \to \frac{- 2}{3}} 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.6

Evaluate the limit of $5$ which is constant as $x$ approaches $\frac{- 2}{3}$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + 72 x - 4}$

Step 2.7

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $\frac{- 2}{3}$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{lim_{x \to \frac{- 2}{3}} 27 x^{2} + lim_{x \to \frac{- 2}{3}} 72 x - lim_{x \to \frac{- 2}{3}} 4}$

Step 2.8

Move the term $27$ outside of the limit because it is constant with respect to $x$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 lim_{x \to \frac{- 2}{3}} x^{2} + lim_{x \to \frac{- 2}{3}} 72 x - lim_{x \to \frac{- 2}{3}} 4}$

Step 2.9

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + lim_{x \to \frac{- 2}{3}} 72 x - lim_{x \to \frac{- 2}{3}} 4}$

Step 2.10

Move the term $72$ outside of the limit because it is constant with respect to $x$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - lim_{x \to \frac{- 2}{3}} 4}$

Step 2.11

Evaluate the limit of $4$ which is constant as $x$ approaches $\frac{- 2}{3}$ .

$\frac{18 {(lim_{x \to \frac{- 2}{3}} x)}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3

Evaluate the limits by plugging in $\frac{- 2}{3}$ for all occurrences of $x$ .

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Step 3.1

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{18 {(\frac{- 2}{3})}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.2

Move the negative in front of the fraction.

$\frac{18 {(- \frac{2}{3})}^{2} - 34 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.3

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (\frac{- 2}{3}) - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.4

Move the negative in front of the fraction.

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(lim_{x \to \frac{- 2}{3}} x)}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.5

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(\frac{- 2}{3})}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.6

Move the negative in front of the fraction.

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 lim_{x \to \frac{- 2}{3}} x - 1 \cdot 4}$

Step 3.7

Evaluate the limit of $x$ by plugging in $\frac{- 2}{3}$ for $x$ .

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (\frac{- 2}{3}) - 1 \cdot 4}$

Step 3.8

Move the negative in front of the fraction.

$\frac{18 {(- \frac{2}{3})}^{2} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4

Simplify the answer.

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 4.1.1.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{18 ({(- 1)}^{2} {(\frac{2}{3})}^{2}) - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.1.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{18 ({(- 1)}^{2} \frac{2^{2}}{3^{2}}) - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.2

Raise $- 1$ to the power of $2$ .

$\frac{18 (1 \frac{2^{2}}{3^{2}}) - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.3

Multiply $\frac{2^{2}}{3^{2}}$ by $1$ .

$\frac{18 \frac{2^{2}}{3^{2}} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.4

Raise $2$ to the power of $2$ .

$\frac{18 \frac{4}{3^{2}} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.5

Raise $3$ to the power of $2$ .

$\frac{18 (\frac{4}{9}) - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.6

Cancel the common factor of $9$ .

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Step 4.1.6.1

Factor $9$ out of $18$ .

$\frac{9 (2) \frac{4}{9} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.6.2

Cancel the common factor.

$\frac{9 \cdot 2 \frac{4}{9} - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.6.3

Rewrite the expression.

$\frac{2 \cdot 4 - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.7

Multiply $2$ by $4$ .

$\frac{8 - 34 (- \frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.8

Multiply $- 34 (- \frac{2}{3})$ .

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Step 4.1.8.1

Multiply $- 1$ by $- 34$ .

$\frac{8 + 34 (\frac{2}{3}) - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.8.2

Combine $34$ and $\frac{2}{3}$ .

$\frac{8 + \frac{34 \cdot 2}{3} - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.8.3

Multiply $34$ by $2$ .

$\frac{8 + \frac{68}{3} - 1 \cdot 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.9

Multiply $- 1$ by $5$ .

$\frac{8 + \frac{68}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.10

To write $8$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{8 \cdot \frac{3}{3} + \frac{68}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.11

Combine $8$ and $\frac{3}{3}$ .

$\frac{\frac{8 \cdot 3}{3} + \frac{68}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.12

Combine the numerators over the common denominator.

$\frac{\frac{8 \cdot 3 + 68}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.13

Simplify the numerator.

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Step 4.1.13.1

Multiply $8$ by $3$ .

$\frac{\frac{24 + 68}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.13.2

Add $24$ and $68$ .

$\frac{\frac{92}{3} - 5}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.14

To write $- 5$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{\frac{92}{3} - 5 \cdot \frac{3}{3}}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.15

Combine $- 5$ and $\frac{3}{3}$ .

$\frac{\frac{92}{3} + \frac{- 5 \cdot 3}{3}}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.16

Combine the numerators over the common denominator.

$\frac{\frac{92 - 5 \cdot 3}{3}}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.17

Simplify the numerator.

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Step 4.1.17.1

Multiply $- 5$ by $3$ .

$\frac{\frac{92 - 15}{3}}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.1.17.2

Subtract $15$ from $92$ .

$\frac{\frac{77}{3}}{27 {(- \frac{2}{3})}^{2} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2

Simplify the denominator.

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Step 4.2.1

Use the power rule ${(a b)}^{n} = a^{n} b^{n}$ to distribute the exponent.

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Step 4.2.1.1

Apply the product rule to $- \frac{2}{3}$ .

$\frac{\frac{77}{3}}{27 ({(- 1)}^{2} {(\frac{2}{3})}^{2}) + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.1.2

Apply the product rule to $\frac{2}{3}$ .

$\frac{\frac{77}{3}}{27 ({(- 1)}^{2} \frac{2^{2}}{3^{2}}) + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.2

Raise $- 1$ to the power of $2$ .

$\frac{\frac{77}{3}}{27 (1 \frac{2^{2}}{3^{2}}) + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.3

Multiply $\frac{2^{2}}{3^{2}}$ by $1$ .

$\frac{\frac{77}{3}}{27 \frac{2^{2}}{3^{2}} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.4

Raise $2$ to the power of $2$ .

$\frac{\frac{77}{3}}{27 \frac{4}{3^{2}} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.5

Raise $3$ to the power of $2$ .

$\frac{\frac{77}{3}}{27 (\frac{4}{9}) + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.6

Cancel the common factor of $9$ .

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Step 4.2.6.1

Factor $9$ out of $27$ .

$\frac{\frac{77}{3}}{9 (3) \frac{4}{9} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.6.2

Cancel the common factor.

$\frac{\frac{77}{3}}{9 \cdot 3 \frac{4}{9} + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.6.3

Rewrite the expression.

$\frac{\frac{77}{3}}{3 \cdot 4 + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.7

Multiply $3$ by $4$ .

$\frac{\frac{77}{3}}{12 + 72 (- \frac{2}{3}) - 1 \cdot 4}$

Step 4.2.8

Cancel the common factor of $3$ .

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Step 4.2.8.1

Move the leading negative in $- \frac{2}{3}$ into the numerator.

$\frac{\frac{77}{3}}{12 + 72 (\frac{- 2}{3}) - 1 \cdot 4}$

Step 4.2.8.2

Factor $3$ out of $72$ .

$\frac{\frac{77}{3}}{12 + 3 (24) \frac{- 2}{3} - 1 \cdot 4}$

Step 4.2.8.3

Cancel the common factor.

$\frac{\frac{77}{3}}{12 + 3 \cdot 24 \frac{- 2}{3} - 1 \cdot 4}$

Step 4.2.8.4

Rewrite the expression.

$\frac{\frac{77}{3}}{12 + 24 \cdot - 2 - 1 \cdot 4}$

Step 4.2.9

Multiply $24$ by $- 2$ .

$\frac{\frac{77}{3}}{12 - 48 - 1 \cdot 4}$

Step 4.2.10

Multiply $- 1$ by $4$ .

$\frac{\frac{77}{3}}{12 - 48 - 4}$

Step 4.2.11

Subtract $48$ from $12$ .

$\frac{\frac{77}{3}}{- 36 - 4}$

Step 4.2.12

Subtract $4$ from $- 36$ .

$\frac{\frac{77}{3}}{- 40}$

Step 4.3

Multiply the numerator by the reciprocal of the denominator.

$\frac{77}{3} \cdot \frac{1}{- 40}$

Step 4.4

Move the negative in front of the fraction.

$\frac{77}{3} (- \frac{1}{40})$

Step 4.5

Multiply $\frac{77}{3} (- \frac{1}{40})$ .

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Step 4.5.1

Multiply $\frac{77}{3}$ by $\frac{1}{40}$ .

$- \frac{77}{3 \cdot 40}$

Step 4.5.2

Multiply $3$ by $40$ .

$- \frac{77}{120}$

Step 5

The result can be shown in multiple forms.

Exact Form:

$- \frac{77}{120}$

Decimal Form:

$- 0.641\overline{6}$