Calculus Examples

$\frac{lim_{x \to 2} x^{2} - 6 x + 8}{x^{2} - 4}$

Step 1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $2$ .

$\frac{lim_{x \to 2} x^{2} - lim_{x \to 2} 6 x + lim_{x \to 2} 8}{x^{2} - 4}$

Step 2

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$\frac{{(lim_{x \to 2} x)}^{2} - lim_{x \to 2} 6 x + lim_{x \to 2} 8}{x^{2} - 4}$

Step 3

Move the term $6$ outside of the limit because it is constant with respect to $x$ .

$\frac{{(lim_{x \to 2} x)}^{2} - 6 lim_{x \to 2} x + lim_{x \to 2} 8}{x^{2} - 4}$

Step 4

Evaluate the limit of $8$ which is constant as $x$ approaches $2$ .

$\frac{{(lim_{x \to 2} x)}^{2} - 6 lim_{x \to 2} x + 8}{x^{2} - 4}$

Step 5

Evaluate the limits by plugging in $2$ for all occurrences of $x$ .

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Step 5.1

Evaluate the limit of $x$ by plugging in $2$ for $x$ .

$\frac{2^{2} - 6 lim_{x \to 2} x + 8}{x^{2} - 4}$

Step 5.2

Evaluate the limit of $x$ by plugging in $2$ for $x$ .

$\frac{2^{2} - 6 \cdot 2 + 8}{x^{2} - 4}$

Step 6

Simplify the answer.

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Step 6.1

Simplify the numerator.

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Step 6.1.1

Raise $2$ to the power of $2$ .

$\frac{4 - 6 \cdot 2 + 8}{x^{2} - 4}$

Step 6.1.2

Multiply $- 6$ by $2$ .

$\frac{4 - 12 + 8}{x^{2} - 4}$

Step 6.1.3

Subtract $12$ from $4$ .

$\frac{- 8 + 8}{x^{2} - 4}$

Step 6.1.4

Add $- 8$ and $8$ .

$\frac{0}{x^{2} - 4}$

Step 6.2

Simplify the denominator.

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Step 6.2.1

Rewrite $4$ as $2^{2}$ .

$\frac{0}{x^{2} - 2^{2}}$

Step 6.2.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = x$ and $b = 2$ .

$\frac{0}{(x + 2) (x - 2)}$

Step 6.3

Divide $0$ by $(x + 2) (x - 2)$ .

$0$