Calculus Examples

$lim_{x \to 0} \frac{12 (1 - \cos (x))}{x^{2}}$

Step 1

Move the term $12$ outside of the limit because it is constant with respect to $x$ .

$12 lim_{x \to 0} \frac{1 - \cos (x)}{x^{2}}$

Step 2

Apply L'Hospital's rule.

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Step 2.1

Evaluate the limit of the numerator and the limit of the denominator.

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Step 2.1.1

Take the limit of the numerator and the limit of the denominator.

$12 \frac{lim_{x \to 0} 1 - \cos (x)}{lim_{x \to 0} x^{2}}$

Step 2.1.2

Evaluate the limit of the numerator.

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Step 2.1.2.1

Evaluate the limit.

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Step 2.1.2.1.1

Split the limit using the Sum of Limits Rule on the limit as $x$ approaches $0$ .

$12 \frac{lim_{x \to 0} 1 - lim_{x \to 0} \cos (x)}{lim_{x \to 0} x^{2}}$

Step 2.1.2.1.2

Evaluate the limit of $1$ which is constant as $x$ approaches $0$ .

$12 \frac{1 - lim_{x \to 0} \cos (x)}{lim_{x \to 0} x^{2}}$

Step 2.1.2.1.3

Move the limit inside the trig function because cosine is continuous.

$12 \frac{1 - \cos (lim_{x \to 0} x)}{lim_{x \to 0} x^{2}}$

Step 2.1.2.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$12 \frac{1 - \cos (0)}{lim_{x \to 0} x^{2}}$

Step 2.1.2.3

Simplify the answer.

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Step 2.1.2.3.1

Simplify each term.

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Step 2.1.2.3.1.1

The exact value of $\cos (0)$ is $1$ .

$12 \frac{1 - 1 \cdot 1}{lim_{x \to 0} x^{2}}$

Step 2.1.2.3.1.2

Multiply $- 1$ by $1$ .

$12 \frac{1 - 1}{lim_{x \to 0} x^{2}}$

Step 2.1.2.3.2

Subtract $1$ from $1$ .

$12 \frac{0}{lim_{x \to 0} x^{2}}$

Step 2.1.3

Evaluate the limit of the denominator.

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Step 2.1.3.1

Move the exponent $2$ from $x^{2}$ outside the limit using the Limits Power Rule.

$12 \frac{0}{{(lim_{x \to 0} x)}^{2}}$

Step 2.1.3.2

Evaluate the limit of $x$ by plugging in $0$ for $x$ .

$12 \frac{0}{0^{2}}$

Step 2.1.3.3

Raising $0$ to any positive power yields $0$ .

$12 (\frac{0}{0})$

Step 2.1.3.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$12 (\frac{0}{0})$

Step 2.1.4

The expression contains a division by $0$ . The expression is undefined.

Undefined

$12 (\frac{0}{0})$

Step 2.2

Since $\frac{0}{0}$ is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.

$lim_{x \to 0} \frac{1 - \cos (x)}{x^{2}} = lim_{x \to 0} \frac{\frac{d}{d x} [1 - \cos (x)]}{\frac{d}{d x} [x^{2}]}$

Step 2.3

Find the derivative of the numerator and denominator.

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Step 2.3.1

Differentiate the numerator and denominator.

$12 lim_{x \to 0} \frac{\frac{d}{d x} [1 - \cos (x)]}{\frac{d}{d x} [x^{2}]}$

Step 2.3.2

By the Sum Rule, the derivative of $1 - \cos (x)$ with respect to $x$ is $\frac{d}{d x} [1] + \frac{d}{d x} [- \cos (x)]$ .

$12 lim_{x \to 0} \frac{\frac{d}{d x} [1] + \frac{d}{d x} [- \cos (x)]}{\frac{d}{d x} [x^{2}]}$

Step 2.3.3

Since $1$ is constant with respect to $x$ , the derivative of $1$ with respect to $x$ is $0$ .

$12 lim_{x \to 0} \frac{0 + \frac{d}{d x} [- \cos (x)]}{\frac{d}{d x} [x^{2}]}$

Step 2.3.4

Evaluate $\frac{d}{d x} [- \cos (x)]$ .

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Step 2.3.4.1

Since $- 1$ is constant with respect to $x$ , the derivative of $- \cos (x)$ with respect to $x$ is $- \frac{d}{d x} [\cos (x)]$ .

$12 lim_{x \to 0} \frac{0 - \frac{d}{d x} [\cos (x)]}{\frac{d}{d x} [x^{2}]}$

Step 2.3.4.2

The derivative of $\cos (x)$ with respect to $x$ is $- \sin (x)$ .

$12 lim_{x \to 0} \frac{0 - - 1 \sin (x)}{\frac{d}{d x} [x^{2}]}$

Step 2.3.4.3

Multiply $- 1$ by $- 1$ .

$12 lim_{x \to 0} \frac{0 + 1 \sin (x)}{\frac{d}{d x} [x^{2}]}$

Step 2.3.4.4

Multiply $\sin (x)$ by $1$ .

$12 lim_{x \to 0} \frac{0 + \sin (x)}{\frac{d}{d x} [x^{2}]}$

Step 2.3.5

Add $0$ and $\sin (x)$ .

$12 lim_{x \to 0} \frac{\sin (x)}{\frac{d}{d x} [x^{2}]}$

Step 2.3.6

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$12 lim_{x \to 0} \frac{\sin (x)}{2 x}$

Step 3

Move the term $\frac{1}{2}$ outside of the limit because it is constant with respect to $x$ .

$12 (\frac{1}{2}) lim_{x \to 0} \frac{\sin (x)}{x}$

Step 4

Since $\cos (x) \leq \frac{\sin (x)}{x} \leq 1$ and $lim_{x \to 0} \cos (x) = lim_{x \to 0} 1 = 1$ , apply the squeeze theorem.

$12 (\frac{1}{2}) \cdot 1$

Step 5

Simplify the answer.

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Step 5.1

Cancel the common factor of $2$ .

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Step 5.1.1

Factor $2$ out of $12$ .

$2 (6) \frac{1}{2} \cdot 1$

Step 5.1.2

Cancel the common factor.

$2 \cdot 6 \frac{1}{2} \cdot 1$

Step 5.1.3

Rewrite the expression.

$6 \cdot 1$

Step 5.2

Multiply $6$ by $1$ .

$6$