Calculus Examples

Evaluate the Limit limit as x approaches 0 of (arctan(2x))/(3x)
limx0arctan(2x)3x
Step 1
Move the term 13 outside of the limit because it is constant with respect to x.
13limx0arctan(2x)x
Step 2
Apply L'Hospital's rule.
Tap for more steps...
Step 2.1
Evaluate the limit of the numerator and the limit of the denominator.
Tap for more steps...
Step 2.1.1
Take the limit of the numerator and the limit of the denominator.
13limx0arctan(2x)limx0x
Step 2.1.2
Evaluate the limit of the numerator.
Tap for more steps...
Step 2.1.2.1
Evaluate the limit of x by plugging in 0 for x.
130limx0x
Step 2.1.2.2
Substitute t for 2x and let t approach 0 since limx02x=0.
13limt0arctan(t)limx0x
Step 2.1.2.3
Evaluate the limits by plugging in 0 for all occurrences of t.
Tap for more steps...
Step 2.1.2.3.1
Evaluate the limit of x by plugging in 0 for x.
13arctan(0)limx0x
Step 2.1.2.3.2
The exact value of arctan(0) is 0.
130limx0x
130limx0x
130limx0x
Step 2.1.3
Evaluate the limit of x by plugging in 0 for x.
1300
Step 2.1.4
The expression contains a division by 0. The expression is undefined.
Undefined
1300
Step 2.2
Since 00 is of indeterminate form, apply L'Hospital's Rule. L'Hospital's Rule states that the limit of a quotient of functions is equal to the limit of the quotient of their derivatives.
limx0arctan(2x)x=limx0ddx[arctan(2x)]ddx[x]
Step 2.3
Find the derivative of the numerator and denominator.
Tap for more steps...
Step 2.3.1
Differentiate the numerator and denominator.
13limx0ddx[arctan(2x)]ddx[x]
Step 2.3.2
Differentiate using the chain rule, which states that ddx[f(g(x))] is f(g(x))g(x) where f(x)=arctan(x) and g(x)=2x.
Tap for more steps...
Step 2.3.2.1
To apply the Chain Rule, set u as 2x.
13limx0ddu[arctan(u)]ddx[2x]ddx[x]
Step 2.3.2.2
The derivative of arctan(u) with respect to u is 11+u2.
13limx011+u2ddx[2x]ddx[x]
Step 2.3.2.3
Replace all occurrences of u with 2x.
13limx011+(2x)2ddx[2x]ddx[x]
13limx011+(2x)2ddx[2x]ddx[x]
Step 2.3.3
Factor 2 out of 2x.
13limx011+(2(x))2ddx[2x]ddx[x]
Step 2.3.4
Apply the product rule to 2(x).
13limx011+22x2ddx[2x]ddx[x]
Step 2.3.5
Raise 2 to the power of 2.
13limx011+4x2ddx[2x]ddx[x]
Step 2.3.6
Since 2 is constant with respect to x, the derivative of 2x with respect to x is 2ddx[x].
13limx011+4x22ddx[x]ddx[x]
Step 2.3.7
Combine 2 and 11+4x2.
13limx021+4x2ddx[x]ddx[x]
Step 2.3.8
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
13limx021+4x21ddx[x]
Step 2.3.9
Multiply 21+4x2 by 1.
13limx021+4x2ddx[x]
Step 2.3.10
Reorder terms.
13limx024x2+1ddx[x]
Step 2.3.11
Differentiate using the Power Rule which states that ddx[xn] is nxn-1 where n=1.
13limx024x2+11
13limx024x2+11
Step 2.4
Multiply the numerator by the reciprocal of the denominator.
13limx024x2+11
Step 2.5
Multiply 24x2+1 by 1.
13limx024x2+1
13limx024x2+1
Step 3
Evaluate the limit.
Tap for more steps...
Step 3.1
Move the term 2 outside of the limit because it is constant with respect to x.
132limx014x2+1
Step 3.2
Split the limit using the Limits Quotient Rule on the limit as x approaches 0.
132limx01limx04x2+1
Step 3.3
Evaluate the limit of 1 which is constant as x approaches 0.
1321limx04x2+1
Step 3.4
Split the limit using the Sum of Limits Rule on the limit as x approaches 0.
1321limx04x2+limx01
Step 3.5
Move the term 4 outside of the limit because it is constant with respect to x.
13214limx0x2+limx01
Step 3.6
Move the exponent 2 from x2 outside the limit using the Limits Power Rule.
13214(limx0x)2+limx01
Step 3.7
Evaluate the limit of 1 which is constant as x approaches 0.
13214(limx0x)2+1
13214(limx0x)2+1
Step 4
Evaluate the limit of x by plugging in 0 for x.
1321402+1
Step 5
Simplify the answer.
Tap for more steps...
Step 5.1
Combine 13 and 2.
231402+1
Step 5.2
Simplify the denominator.
Tap for more steps...
Step 5.2.1
Raising 0 to any positive power yields 0.
23140+1
Step 5.2.2
Multiply 4 by 0.
2310+1
Step 5.2.3
Add 0 and 1.
2311
2311
Step 5.3
Cancel the common factor of 1.
Tap for more steps...
Step 5.3.1
Cancel the common factor.
2311
Step 5.3.2
Rewrite the expression.
231
231
Step 5.4
Multiply 23 by 1.
23
23
Step 6
The result can be shown in multiple forms.
Exact Form:
23
Decimal Form:
0.6
 [x2  12  π  xdx ]