Calculus Examples

$y = 12 x - x^{2} - x^{3}$ , $y = 0$

Step 1

Solve by substitution to find the intersection between the curves.

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Step 1.1

Eliminate the equal sides of each equation and combine.

$12 x - x^{2} - x^{3} = 0$

Step 1.2

Solve $12 x - x^{2} - x^{3} = 0$ for $x$ .

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Step 1.2.1

Factor the left side of the equation.

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Step 1.2.1.1

Let $u = x$ . Substitute $u$ for all occurrences of $x$ .

$12 u - u^{2} - u^{3} = 0$

Step 1.2.1.2

Factor $u$ out of $12 u - u^{2} - u^{3}$ .

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Step 1.2.1.2.1

Factor $u$ out of $12 u$ .

$u \cdot 12 - u^{2} - u^{3} = 0$

Step 1.2.1.2.2

Factor $u$ out of $- u^{2}$ .

$u \cdot 12 + u (- u) - u^{3} = 0$

Step 1.2.1.2.3

Factor $u$ out of $- u^{3}$ .

$u \cdot 12 + u (- u) + u (- u^{2}) = 0$

Step 1.2.1.2.4

Factor $u$ out of $u \cdot 12 + u (- u)$ .

$u \cdot (12 - u) + u (- u^{2}) = 0$

Step 1.2.1.2.5

Factor $u$ out of $u \cdot (12 - u) + u (- u^{2})$ .

$u (12 - u - u^{2}) = 0$

Step 1.2.1.3

Factor.

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Step 1.2.1.3.1

Factor by grouping.

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Step 1.2.1.3.1.1

Reorder terms.

$u (- u^{2} - u + 12) = 0$

Step 1.2.1.3.1.2

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot 12 = - 12$ and whose sum is $b = - 1$ .

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Step 1.2.1.3.1.2.1

Factor $- 1$ out of $- u$ .

$u (- u^{2} - (u) + 12) = 0$

Step 1.2.1.3.1.2.2

Rewrite $- 1$ as $3$ plus $- 4$

$u (- u^{2} + (3 - 4) u + 12) = 0$

Step 1.2.1.3.1.2.3

Apply the distributive property.

$u (- u^{2} + 3 u - 4 u + 12) = 0$

Step 1.2.1.3.1.3

Factor out the greatest common factor from each group.

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Step 1.2.1.3.1.3.1

Group the first two terms and the last two terms.

$u ((- u^{2} + 3 u) - 4 u + 12) = 0$

Step 1.2.1.3.1.3.2

Factor out the greatest common factor (GCF) from each group.

$u (u (- u + 3) + 4 (- u + 3)) = 0$

Step 1.2.1.3.1.4

Factor the polynomial by factoring out the greatest common factor, $- u + 3$ .

$u ((- u + 3) (u + 4)) = 0$

Step 1.2.1.3.2

Remove unnecessary parentheses.

$u (- u + 3) (u + 4) = 0$

Step 1.2.1.4

Replace all occurrences of $u$ with $x$ .

$x (- x + 3) (x + 4) = 0$

Step 1.2.2

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$x = 0$

$- x + 3 = 0$

$x + 4 = 0 + y = 0$

Step 1.2.3

Set $x$ equal to $0$ .

$x = 0$

Step 1.2.4

Set $- x + 3$ equal to $0$ and solve for $x$ .

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Step 1.2.4.1

Set $- x + 3$ equal to $0$ .

$- x + 3 = 0$

Step 1.2.4.2

Solve $- x + 3 = 0$ for $x$ .

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Step 1.2.4.2.1

Subtract $3$ from both sides of the equation.

$- x = - 3$

Step 1.2.4.2.2

Divide each term in $- x = - 3$ by $- 1$ and simplify.

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Step 1.2.4.2.2.1

Divide each term in $- x = - 3$ by $- 1$ .

$\frac{- x}{- 1} = \frac{- 3}{- 1}$

Step 1.2.4.2.2.2

Simplify the left side.

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Step 1.2.4.2.2.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{- 3}{- 1}$

Step 1.2.4.2.2.2.2

Divide $x$ by $1$ .

$x = \frac{- 3}{- 1}$

Step 1.2.4.2.2.3

Simplify the right side.

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Step 1.2.4.2.2.3.1

Divide $- 3$ by $- 1$ .

$x = 3$

Step 1.2.5

Set $x + 4$ equal to $0$ and solve for $x$ .

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Step 1.2.5.1

Set $x + 4$ equal to $0$ .

$x + 4 = 0$

Step 1.2.5.2

Subtract $4$ from both sides of the equation.

$x = - 4$

Step 1.2.6

The final solution is all the values that make $x (- x + 3) (x + 4) = 0$ true.

$x = 0, 3, - 4$

Step 1.3

Substitute $0$ for $x$ .

$y = 0$

Step 1.4

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(0, 0)$

$(3, 0)$

$(- 4, 0)$

$(0, 0)$

$(3, 0)$

$(- 4, 0)$

Step 2

Simplify $12 x - x^{2} - x^{3}$ .

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Step 2.1

Move $12 x$ .

$y = - x^{2} - x^{3} + 12 x$

Step 2.2

Reorder $- x^{2}$ and $- x^{3}$ .

$y = - x^{3} - x^{2} + 12 x$

Step 3

The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.

$A r e a = \int_{- 4}^{0} 0 d x - \int_{- 4}^{0} - x^{3} - x^{2} + 12 x d x$

Step 4

Integrate to find the area between $- 4$ and $0$ .

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Step 4.1

Combine the integrals into a single integral.

$\int_{- 4}^{0} 0 - (- x^{3} - x^{2} + 12 x) d x$

Step 4.2

Subtract $- x^{3} - x^{2} + 12 x$ from $0$ .

$\int_{- 4}^{0} - (- x^{3} - x^{2} + 12 x) d x$

Step 4.3

Apply the distributive property.

$\int_{- 4}^{0} x^{3} + x^{2} - (12 x) d x$

Step 4.4

Simplify.

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Step 4.4.1

Multiply $- - x^{3}$ .

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Step 4.4.1.1

Multiply $- 1$ by $- 1$ .

$1 x^{3} - - x^{2} - (12 x)$

Step 4.4.1.2

Multiply $x^{3}$ by $1$ .

$x^{3} - - x^{2} - (12 x)$

Step 4.4.2

Multiply $- - x^{2}$ .

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Step 4.4.2.1

Multiply $- 1$ by $- 1$ .

$x^{3} + 1 x^{2} - (12 x)$

Step 4.4.2.2

Multiply $x^{2}$ by $1$ .

$x^{3} + x^{2} - (12 x)$

Step 4.4.3

Multiply $12$ by $- 1$ .

$x^{3} + x^{2} - 12 x$

$\int_{- 4}^{0} x^{3} + x^{2} - 12 x d x$

Step 4.5

Split the single integral into multiple integrals.

$\int_{- 4}^{0} x^{3} d x + \int_{- 4}^{0} x^{2} d x + \int_{- 4}^{0} - 12 x d x$

Step 4.6

By the Power Rule, the integral of $x^{3}$ with respect to $x$ is $\frac{1}{4} x^{4}$ .

$\frac{1}{4} x^{4}]_{- 4}^{0} + \int_{- 4}^{0} x^{2} d x + \int_{- 4}^{0} - 12 x d x$

Step 4.7

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$\frac{1}{4} x^{4}]_{- 4}^{0} + \frac{1}{3} x^{3}]_{- 4}^{0} + \int_{- 4}^{0} - 12 x d x$

Step 4.8

Since $- 12$ is constant with respect to $x$ , move $- 12$ out of the integral.

$\frac{1}{4} x^{4}]_{- 4}^{0} + \frac{1}{3} x^{3}]_{- 4}^{0} - 12 \int_{- 4}^{0} x d x$

Step 4.9

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$\frac{1}{4} x^{4}]_{- 4}^{0} + \frac{1}{3} x^{3}]_{- 4}^{0} - 12 (\frac{1}{2} x^{2}]_{- 4}^{0})$

Step 4.10

Simplify the answer.

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Step 4.10.1

Simplify.

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Step 4.10.1.1

Combine $\frac{1}{4} x^{4}]_{- 4}^{0}$ and $\frac{1}{3} x^{3}]_{- 4}^{0}$ .

$\frac{1}{4} x^{4} + \frac{1}{3} x^{3}]_{- 4}^{0} - 12 (\frac{1}{2} x^{2}]_{- 4}^{0})$

Step 4.10.1.2

Combine $\frac{1}{2}$ and $x^{2}$ .

$\frac{1}{4} x^{4} + \frac{1}{3} x^{3}]_{- 4}^{0} - 12 (\frac{x^{2}}{2}]_{- 4}^{0})$

Step 4.10.2

Substitute and simplify.

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Step 4.10.2.1

Evaluate $\frac{1}{4} x^{4} + \frac{1}{3} x^{3}$ at $0$ and at $- 4$ .

$(\frac{1}{4} \cdot 0^{4} + \frac{1}{3} \cdot 0^{3}) - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 (\frac{x^{2}}{2}]_{- 4}^{0})$

Step 4.10.2.2

Evaluate $\frac{x^{2}}{2}$ at $0$ and at $- 4$ .

$(\frac{1}{4} \cdot 0^{4} + \frac{1}{3} \cdot 0^{3}) - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3

Simplify.

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Step 4.10.2.3.1

Raising $0$ to any positive power yields $0$ .

$\frac{1}{4} \cdot 0 + \frac{1}{3} \cdot 0^{3} - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.2

Multiply $\frac{1}{4}$ by $0$ .

$0 + \frac{1}{3} \cdot 0^{3} - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.3

Raising $0$ to any positive power yields $0$ .

$0 + \frac{1}{3} \cdot 0 - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.4

Multiply $\frac{1}{3}$ by $0$ .

$0 + 0 - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.5

Add $0$ and $0$ .

$0 - (\frac{1}{4} {(- 4)}^{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.6

Raise $- 4$ to the power of $4$ .

$0 - (\frac{1}{4} \cdot 256 + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.7

Combine $\frac{1}{4}$ and $256$ .

$0 - (\frac{256}{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.8

Cancel the common factor of $256$ and $4$ .

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Step 4.10.2.3.8.1

Factor $4$ out of $256$ .

$0 - (\frac{4 \cdot 64}{4} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.8.2

Cancel the common factors.

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Step 4.10.2.3.8.2.1

Factor $4$ out of $4$ .

$0 - (\frac{4 \cdot 64}{4 (1)} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.8.2.2

Cancel the common factor.

$0 - (\frac{4 \cdot 64}{4 \cdot 1} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.8.2.3

Rewrite the expression.

$0 - (\frac{64}{1} + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.8.2.4

Divide $64$ by $1$ .

$0 - (64 + \frac{1}{3} {(- 4)}^{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.9

Raise $- 4$ to the power of $3$ .

$0 - (64 + \frac{1}{3} \cdot - 64) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.10

Combine $\frac{1}{3}$ and $- 64$ .

$0 - (64 + \frac{- 64}{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.11

Move the negative in front of the fraction.

$0 - (64 - \frac{64}{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.12

To write $64$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$0 - (64 \cdot \frac{3}{3} - \frac{64}{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.13

Combine $64$ and $\frac{3}{3}$ .

$0 - (\frac{64 \cdot 3}{3} - \frac{64}{3}) - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.14

Combine the numerators over the common denominator.

$0 - \frac{64 \cdot 3 - 64}{3} - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.15

Simplify the numerator.

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Step 4.10.2.3.15.1

Multiply $64$ by $3$ .

$0 - \frac{192 - 64}{3} - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.15.2

Subtract $64$ from $192$ .

$0 - \frac{128}{3} - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.16

Subtract $\frac{128}{3}$ from $0$ .

$- \frac{128}{3} - 12 ((\frac{0^{2}}{2}) - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.17

Raising $0$ to any positive power yields $0$ .

$- \frac{128}{3} - 12 (\frac{0}{2} - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.18

Cancel the common factor of $0$ and $2$ .

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Step 4.10.2.3.18.1

Factor $2$ out of $0$ .

$- \frac{128}{3} - 12 (\frac{2 (0)}{2} - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.18.2

Cancel the common factors.

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Step 4.10.2.3.18.2.1

Factor $2$ out of $2$ .

$- \frac{128}{3} - 12 (\frac{2 \cdot 0}{2 \cdot 1} - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.18.2.2

Cancel the common factor.

$- \frac{128}{3} - 12 (\frac{2 \cdot 0}{2 \cdot 1} - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.18.2.3

Rewrite the expression.

$- \frac{128}{3} - 12 (\frac{0}{1} - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.18.2.4

Divide $0$ by $1$ .

$- \frac{128}{3} - 12 (0 - \frac{{(- 4)}^{2}}{2})$

Step 4.10.2.3.19

Raise $- 4$ to the power of $2$ .

$- \frac{128}{3} - 12 (0 - \frac{16}{2})$

Step 4.10.2.3.20

Cancel the common factor of $16$ and $2$ .

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Step 4.10.2.3.20.1

Factor $2$ out of $16$ .

$- \frac{128}{3} - 12 (0 - \frac{2 \cdot 8}{2})$

Step 4.10.2.3.20.2

Cancel the common factors.

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Step 4.10.2.3.20.2.1

Factor $2$ out of $2$ .

$- \frac{128}{3} - 12 (0 - \frac{2 \cdot 8}{2 (1)})$

Step 4.10.2.3.20.2.2

Cancel the common factor.

$- \frac{128}{3} - 12 (0 - \frac{2 \cdot 8}{2 \cdot 1})$

Step 4.10.2.3.20.2.3

Rewrite the expression.

$- \frac{128}{3} - 12 (0 - \frac{8}{1})$

Step 4.10.2.3.20.2.4

Divide $8$ by $1$ .

$- \frac{128}{3} - 12 (0 - 1 \cdot 8)$

Step 4.10.2.3.21

Multiply $- 1$ by $8$ .

$- \frac{128}{3} - 12 (0 - 8)$

Step 4.10.2.3.22

Subtract $8$ from $0$ .

$- \frac{128}{3} - 12 \cdot - 8$

Step 4.10.2.3.23

Multiply $- 12$ by $- 8$ .

$- \frac{128}{3} + 96$

Step 4.10.2.3.24

To write $96$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{128}{3} + 96 \cdot \frac{3}{3}$

Step 4.10.2.3.25

Combine $96$ and $\frac{3}{3}$ .

$- \frac{128}{3} + \frac{96 \cdot 3}{3}$

Step 4.10.2.3.26

Combine the numerators over the common denominator.

$\frac{- 128 + 96 \cdot 3}{3}$

Step 4.10.2.3.27

Simplify the numerator.

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Step 4.10.2.3.27.1

Multiply $96$ by $3$ .

$\frac{- 128 + 288}{3}$

Step 4.10.2.3.27.2

Add $- 128$ and $288$ .

$\frac{160}{3}$

Step 5

$A r e a = \int_{0}^{3} - x^{3} - x^{2} + 12 x d x - \int_{0}^{3} 0 d x$

Step 6

Integrate to find the area between $0$ and $3$ .

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Step 6.1

Combine the integrals into a single integral.

$\int_{0}^{3} - x^{3} - x^{2} + 12 x - (0) d x$

Step 6.2

Subtract $0$ from $- x^{3} - x^{2} + 12 x$ .

$\int_{0}^{3} - x^{3} - x^{2} + 12 x d x$

Step 6.3

Split the single integral into multiple integrals.

$\int_{0}^{3} - x^{3} d x + \int_{0}^{3} - x^{2} d x + \int_{0}^{3} 12 x d x$

Step 6.4

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$- \int_{0}^{3} x^{3} d x + \int_{0}^{3} - x^{2} d x + \int_{0}^{3} 12 x d x$

Step 6.5

By the Power Rule, the integral of $x^{3}$ with respect to $x$ is $\frac{1}{4} x^{4}$ .

$- (\frac{1}{4} x^{4}]_{0}^{3}) + \int_{0}^{3} - x^{2} d x + \int_{0}^{3} 12 x d x$

Step 6.6

Combine $\frac{1}{4}$ and $x^{4}$ .

$- (\frac{x^{4}}{4}]_{0}^{3}) + \int_{0}^{3} - x^{2} d x + \int_{0}^{3} 12 x d x$

Step 6.7

Since $- 1$ is constant with respect to $x$ , move $- 1$ out of the integral.

$- (\frac{x^{4}}{4}]_{0}^{3}) - \int_{0}^{3} x^{2} d x + \int_{0}^{3} 12 x d x$

Step 6.8

By the Power Rule, the integral of $x^{2}$ with respect to $x$ is $\frac{1}{3} x^{3}$ .

$- (\frac{x^{4}}{4}]_{0}^{3}) - (\frac{1}{3} x^{3}]_{0}^{3}) + \int_{0}^{3} 12 x d x$

Step 6.9

Combine $\frac{1}{3}$ and $x^{3}$ .

$- (\frac{x^{4}}{4}]_{0}^{3}) - (\frac{x^{3}}{3}]_{0}^{3}) + \int_{0}^{3} 12 x d x$

Step 6.10

Since $12$ is constant with respect to $x$ , move $12$ out of the integral.

$- (\frac{x^{4}}{4}]_{0}^{3}) - (\frac{x^{3}}{3}]_{0}^{3}) + 12 \int_{0}^{3} x d x$

Step 6.11

By the Power Rule, the integral of $x$ with respect to $x$ is $\frac{1}{2} x^{2}$ .

$- (\frac{x^{4}}{4}]_{0}^{3}) - (\frac{x^{3}}{3}]_{0}^{3}) + 12 (\frac{1}{2} x^{2}]_{0}^{3})$

Step 6.12

Simplify the answer.

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Step 6.12.1

Combine $\frac{1}{2}$ and $x^{2}$ .

$- (\frac{x^{4}}{4}]_{0}^{3}) - (\frac{x^{3}}{3}]_{0}^{3}) + 12 (\frac{x^{2}}{2}]_{0}^{3})$

Step 6.12.2

Substitute and simplify.

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Step 6.12.2.1

Evaluate $\frac{x^{4}}{4}$ at $3$ and at $0$ .

$- ((\frac{3^{4}}{4}) - \frac{0^{4}}{4}) - (\frac{x^{3}}{3}]_{0}^{3}) + 12 (\frac{x^{2}}{2}]_{0}^{3})$

Step 6.12.2.2

Evaluate $\frac{x^{3}}{3}$ at $3$ and at $0$ .

$- (\frac{3^{4}}{4} - \frac{0^{4}}{4}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 (\frac{x^{2}}{2}]_{0}^{3})$

Step 6.12.2.3

Evaluate $\frac{x^{2}}{2}$ at $3$ and at $0$ .

$- (\frac{3^{4}}{4} - \frac{0^{4}}{4}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4

Simplify.

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Step 6.12.2.4.1

Raise $3$ to the power of $4$ .

$- (\frac{81}{4} - \frac{0^{4}}{4}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.2

Raising $0$ to any positive power yields $0$ .

$- (\frac{81}{4} - \frac{0}{4}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.3

Cancel the common factor of $0$ and $4$ .

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Step 6.12.2.4.3.1

Factor $4$ out of $0$ .

$- (\frac{81}{4} - \frac{4 (0)}{4}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.3.2

Cancel the common factors.

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Step 6.12.2.4.3.2.1

Factor $4$ out of $4$ .

$- (\frac{81}{4} - \frac{4 \cdot 0}{4 \cdot 1}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.3.2.2

Cancel the common factor.

$- (\frac{81}{4} - \frac{4 \cdot 0}{4 \cdot 1}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.3.2.3

Rewrite the expression.

$- (\frac{81}{4} - \frac{0}{1}) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.3.2.4

Divide $0$ by $1$ .

$- (\frac{81}{4} - 0) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.4

Multiply $- 1$ by $0$ .

$- (\frac{81}{4} + 0) - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.5

Add $\frac{81}{4}$ and $0$ .

$- \frac{81}{4} - (\frac{3^{3}}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.6

Raise $3$ to the power of $3$ .

$- \frac{81}{4} - (\frac{27}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.7

Cancel the common factor of $27$ and $3$ .

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Step 6.12.2.4.7.1

Factor $3$ out of $27$ .

$- \frac{81}{4} - (\frac{3 \cdot 9}{3} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.7.2

Cancel the common factors.

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Step 6.12.2.4.7.2.1

Factor $3$ out of $3$ .

$- \frac{81}{4} - (\frac{3 \cdot 9}{3 (1)} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.7.2.2

Cancel the common factor.

$- \frac{81}{4} - (\frac{3 \cdot 9}{3 \cdot 1} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.7.2.3

Rewrite the expression.

$- \frac{81}{4} - (\frac{9}{1} - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.7.2.4

Divide $9$ by $1$ .

$- \frac{81}{4} - (9 - \frac{0^{3}}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.8

Raising $0$ to any positive power yields $0$ .

$- \frac{81}{4} - (9 - \frac{0}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.9

Cancel the common factor of $0$ and $3$ .

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Step 6.12.2.4.9.1

Factor $3$ out of $0$ .

$- \frac{81}{4} - (9 - \frac{3 (0)}{3}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.9.2

Cancel the common factors.

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Step 6.12.2.4.9.2.1

Factor $3$ out of $3$ .

$- \frac{81}{4} - (9 - \frac{3 \cdot 0}{3 \cdot 1}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.9.2.2

Cancel the common factor.

$- \frac{81}{4} - (9 - \frac{3 \cdot 0}{3 \cdot 1}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.9.2.3

Rewrite the expression.

$- \frac{81}{4} - (9 - \frac{0}{1}) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.9.2.4

Divide $0$ by $1$ .

$- \frac{81}{4} - (9 - 0) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.10

Multiply $- 1$ by $0$ .

$- \frac{81}{4} - (9 + 0) + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.11

Add $9$ and $0$ .

$- \frac{81}{4} - 1 \cdot 9 + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.12

Multiply $- 1$ by $9$ .

$- \frac{81}{4} - 9 + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.13

To write $- 9$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{81}{4} - 9 \cdot \frac{4}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.14

Combine $- 9$ and $\frac{4}{4}$ .

$- \frac{81}{4} + \frac{- 9 \cdot 4}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.15

Combine the numerators over the common denominator.

$\frac{- 81 - 9 \cdot 4}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.16

Simplify the numerator.

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Step 6.12.2.4.16.1

Multiply $- 9$ by $4$ .

$\frac{- 81 - 36}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.16.2

Subtract $36$ from $- 81$ .

$\frac{- 117}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.17

Move the negative in front of the fraction.

$- \frac{117}{4} + 12 ((\frac{3^{2}}{2}) - \frac{0^{2}}{2})$

Step 6.12.2.4.18

Raise $3$ to the power of $2$ .

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{0^{2}}{2})$

Step 6.12.2.4.19

Raising $0$ to any positive power yields $0$ .

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{0}{2})$

Step 6.12.2.4.20

Cancel the common factor of $0$ and $2$ .

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Step 6.12.2.4.20.1

Factor $2$ out of $0$ .

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{2 (0)}{2})$

Step 6.12.2.4.20.2

Cancel the common factors.

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Step 6.12.2.4.20.2.1

Factor $2$ out of $2$ .

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{2 \cdot 0}{2 \cdot 1})$

Step 6.12.2.4.20.2.2

Cancel the common factor.

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{2 \cdot 0}{2 \cdot 1})$

Step 6.12.2.4.20.2.3

Rewrite the expression.

$- \frac{117}{4} + 12 (\frac{9}{2} - \frac{0}{1})$

Step 6.12.2.4.20.2.4

Divide $0$ by $1$ .

$- \frac{117}{4} + 12 (\frac{9}{2} - 0)$

Step 6.12.2.4.21

Multiply $- 1$ by $0$ .

$- \frac{117}{4} + 12 (\frac{9}{2} + 0)$

Step 6.12.2.4.22

Add $\frac{9}{2}$ and $0$ .

$- \frac{117}{4} + 12 (\frac{9}{2})$

Step 6.12.2.4.23

Combine $12$ and $\frac{9}{2}$ .

$- \frac{117}{4} + \frac{12 \cdot 9}{2}$

Step 6.12.2.4.24

Multiply $12$ by $9$ .

$- \frac{117}{4} + \frac{108}{2}$

Step 6.12.2.4.25

Cancel the common factor of $108$ and $2$ .

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Step 6.12.2.4.25.1

Factor $2$ out of $108$ .

$- \frac{117}{4} + \frac{2 \cdot 54}{2}$

Step 6.12.2.4.25.2

Cancel the common factors.

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Step 6.12.2.4.25.2.1

Factor $2$ out of $2$ .

$- \frac{117}{4} + \frac{2 \cdot 54}{2 (1)}$

Step 6.12.2.4.25.2.2

Cancel the common factor.

$- \frac{117}{4} + \frac{2 \cdot 54}{2 \cdot 1}$

Step 6.12.2.4.25.2.3

Rewrite the expression.

$- \frac{117}{4} + \frac{54}{1}$

Step 6.12.2.4.25.2.4

Divide $54$ by $1$ .

$- \frac{117}{4} + 54$

Step 6.12.2.4.26

To write $54$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$- \frac{117}{4} + 54 \cdot \frac{4}{4}$

Step 6.12.2.4.27

Combine $54$ and $\frac{4}{4}$ .

$- \frac{117}{4} + \frac{54 \cdot 4}{4}$

Step 6.12.2.4.28

Combine the numerators over the common denominator.

$\frac{- 117 + 54 \cdot 4}{4}$

Step 6.12.2.4.29

Simplify the numerator.

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Step 6.12.2.4.29.1

Multiply $54$ by $4$ .

$\frac{- 117 + 216}{4}$

Step 6.12.2.4.29.2

Add $- 117$ and $216$ .

$\frac{99}{4}$

Step 7

Add the areas $\frac{160}{3} + \frac{99}{4}$ .

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Step 7.1

To write $\frac{160}{3}$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$\frac{160}{3} \cdot \frac{4}{4} + \frac{99}{4}$

Step 7.2

To write $\frac{99}{4}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{160}{3} \cdot \frac{4}{4} + \frac{99}{4} \cdot \frac{3}{3}$

Step 7.3

Write each expression with a common denominator of $12$ , by multiplying each by an appropriate factor of $1$ .

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Step 7.3.1

Multiply $\frac{160}{3}$ by $\frac{4}{4}$ .

$\frac{160 \cdot 4}{3 \cdot 4} + \frac{99}{4} \cdot \frac{3}{3}$

Step 7.3.2

Multiply $3$ by $4$ .

$\frac{160 \cdot 4}{12} + \frac{99}{4} \cdot \frac{3}{3}$

Step 7.3.3

Multiply $\frac{99}{4}$ by $\frac{3}{3}$ .

$\frac{160 \cdot 4}{12} + \frac{99 \cdot 3}{4 \cdot 3}$

Step 7.3.4

Multiply $4$ by $3$ .

$\frac{160 \cdot 4}{12} + \frac{99 \cdot 3}{12}$

Step 7.4

Combine the numerators over the common denominator.

$\frac{160 \cdot 4 + 99 \cdot 3}{12}$

Step 7.5

Simplify the numerator.

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Step 7.5.1

Multiply $160$ by $4$ .

$\frac{640 + 99 \cdot 3}{12}$

Step 7.5.2

Multiply $99$ by $3$ .

$\frac{640 + 297}{12}$

Step 7.5.3

Add $640$ and $297$ .

$\frac{937}{12}$

Step 8