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Calculus Examples
, , ,
Step 1
Step 1.1
Eliminate the equal sides of each equation and combine.
Step 1.2
Solve for .
Step 1.2.1
Take the inverse cosine of both sides of the equation to extract from inside the cosine.
Step 1.2.2
Simplify the right side.
Step 1.2.2.1
The exact value of is .
Step 1.2.3
Divide each term in by and simplify.
Step 1.2.3.1
Divide each term in by .
Step 1.2.3.2
Simplify the left side.
Step 1.2.3.2.1
Cancel the common factor of .
Step 1.2.3.2.1.1
Cancel the common factor.
Step 1.2.3.2.1.2
Divide by .
Step 1.2.3.3
Simplify the right side.
Step 1.2.3.3.1
Multiply the numerator by the reciprocal of the denominator.
Step 1.2.3.3.2
Multiply .
Step 1.2.3.3.2.1
Multiply by .
Step 1.2.3.3.2.2
Multiply by .
Step 1.2.4
The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from to find the solution in the fourth quadrant.
Step 1.2.5
Solve for .
Step 1.2.5.1
Simplify.
Step 1.2.5.1.1
To write as a fraction with a common denominator, multiply by .
Step 1.2.5.1.2
Combine and .
Step 1.2.5.1.3
Combine the numerators over the common denominator.
Step 1.2.5.1.4
Multiply by .
Step 1.2.5.1.5
Subtract from .
Step 1.2.5.2
Divide each term in by and simplify.
Step 1.2.5.2.1
Divide each term in by .
Step 1.2.5.2.2
Simplify the left side.
Step 1.2.5.2.2.1
Cancel the common factor of .
Step 1.2.5.2.2.1.1
Cancel the common factor.
Step 1.2.5.2.2.1.2
Divide by .
Step 1.2.5.2.3
Simplify the right side.
Step 1.2.5.2.3.1
Multiply the numerator by the reciprocal of the denominator.
Step 1.2.5.2.3.2
Multiply .
Step 1.2.5.2.3.2.1
Multiply by .
Step 1.2.5.2.3.2.2
Multiply by .
Step 1.2.6
Find the period of .
Step 1.2.6.1
The period of the function can be calculated using .
Step 1.2.6.2
Replace with in the formula for period.
Step 1.2.6.3
The absolute value is the distance between a number and zero. The distance between and is .
Step 1.2.7
The period of the function is so values will repeat every radians in both directions.
, for any integer
Step 1.2.8
Consolidate the answers.
, for any integer
, for any integer
Step 1.3
Substitute for .
Step 1.4
List all of the solutions.
Step 2
The area of the region between the curves is defined as the integral of the upper curve minus the integral of the lower curve over each region. The regions are determined by the intersection points of the curves. This can be done algebraically or graphically.
Step 3
Step 3.1
Combine the integrals into a single integral.
Step 3.2
Subtract from .
Step 3.3
Since is constant with respect to , move out of the integral.
Step 3.4
Let . Then , so . Rewrite using and .
Step 3.4.1
Let . Find .
Step 3.4.1.1
Differentiate .
Step 3.4.1.2
Since is constant with respect to , the derivative of with respect to is .
Step 3.4.1.3
Differentiate using the Power Rule which states that is where .
Step 3.4.1.4
Multiply by .
Step 3.4.2
Substitute the lower limit in for in .
Step 3.4.3
Cancel the common factor of .
Step 3.4.3.1
Factor out of .
Step 3.4.3.2
Cancel the common factor.
Step 3.4.3.3
Rewrite the expression.
Step 3.4.4
Substitute the upper limit in for in .
Step 3.4.5
Cancel the common factor of .
Step 3.4.5.1
Cancel the common factor.
Step 3.4.5.2
Rewrite the expression.
Step 3.4.6
The values found for and will be used to evaluate the definite integral.
Step 3.4.7
Rewrite the problem using , , and the new limits of integration.
Step 3.5
Combine and .
Step 3.6
Since is constant with respect to , move out of the integral.
Step 3.7
The integral of with respect to is .
Step 3.8
Evaluate at and at .
Step 3.9
Simplify.
Step 3.9.1
The exact value of is .
Step 3.9.2
Multiply by .
Step 3.10
Simplify.
Step 3.10.1
Simplify each term.
Step 3.10.1.1
Apply the reference angle by finding the angle with equivalent trig values in the first quadrant.
Step 3.10.1.2
The exact value of is .
Step 3.10.2
Subtract from .
Step 3.10.3
Multiply .
Step 3.10.3.1
Multiply by .
Step 3.10.3.2
Multiply by .
Step 4