Calculus Examples

$2 {(x^{2} + y^{2})}^{2} = 25 (x^{2} - y^{2})$ , $(- 3, - 1)$

Step 1

Find the first derivative and evaluate at $x = - 3$ and $y = - 1$ to find the slope of the tangent line.

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Step 1.1

Differentiate both sides of the equation.

$\frac{d}{d x} (2 {(x^{2} + y^{2})}^{2}) = \frac{d}{d x} (25 (x^{2} - y^{2}))$

Step 1.2

Differentiate the left side of the equation.

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Step 1.2.1

Since $2$ is constant with respect to $x$ , the derivative of $2 {(x^{2} + y^{2})}^{2}$ with respect to $x$ is $2 \frac{d}{d x} [{(x^{2} + y^{2})}^{2}]$ .

$2 \frac{d}{d x} [{(x^{2} + y^{2})}^{2}]$

Step 1.2.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = x^{2} + y^{2}$ .

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Step 1.2.2.1

To apply the Chain Rule, set $u_{1}$ as $x^{2} + y^{2}$ .

$2 (\frac{d}{d u_{1}} [{u_{1}}^{2}] \frac{d}{d x} [x^{2} + y^{2}])$

Step 1.2.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 2$ .

$2 (2 u_{1} \frac{d}{d x} [x^{2} + y^{2}])$

Step 1.2.2.3

Replace all occurrences of $u_{1}$ with $x^{2} + y^{2}$ .

$2 (2 (x^{2} + y^{2}) \frac{d}{d x} [x^{2} + y^{2}])$

Step 1.2.3

Differentiate.

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Step 1.2.3.1

Multiply $2$ by $2$ .

$4 ((x^{2} + y^{2}) \frac{d}{d x} [x^{2} + y^{2}])$

Step 1.2.3.2

By the Sum Rule, the derivative of $x^{2} + y^{2}$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}]$ .

$4 (x^{2} + y^{2}) (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [y^{2}])$

Step 1.2.3.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$4 (x^{2} + y^{2}) (2 x + \frac{d}{d x} [y^{2}])$

Step 1.2.4

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 1.2.4.1

To apply the Chain Rule, set $u_{2}$ as $y$ .

$4 (x^{2} + y^{2}) (2 x + \frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d x} [y])$

Step 1.2.4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$4 (x^{2} + y^{2}) (2 x + 2 u_{2} \frac{d}{d x} [y])$

Step 1.2.4.3

Replace all occurrences of $u_{2}$ with $y$ .

$4 (x^{2} + y^{2}) (2 x + 2 y \frac{d}{d x} [y])$

Step 1.2.5

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$4 (x^{2} + y^{2}) (2 x + 2 y y')$

Step 1.2.6

Simplify.

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Step 1.2.6.1

Apply the distributive property.

$(4 x^{2} + 4 y^{2}) (2 x + 2 y y')$

Step 1.2.6.2

Reorder the factors of $(4 x^{2} + 4 y^{2}) (2 x + 2 y y')$ .

$(2 x + 2 y y') (4 x^{2} + 4 y^{2})$

Step 1.3

Differentiate the right side of the equation.

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Step 1.3.1

Differentiate.

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Step 1.3.1.1

Since $25$ is constant with respect to $x$ , the derivative of $25 (x^{2} - y^{2})$ with respect to $x$ is $25 \frac{d}{d x} [x^{2} - y^{2}]$ .

$25 \frac{d}{d x} [x^{2} - y^{2}]$

Step 1.3.1.2

By the Sum Rule, the derivative of $x^{2} - y^{2}$ with respect to $x$ is $\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- y^{2}]$ .

$25 (\frac{d}{d x} [x^{2}] + \frac{d}{d x} [- y^{2}])$

Step 1.3.1.3

Differentiate using the Power Rule which states that $\frac{d}{d x} [x^{n}]$ is $n x^{n - 1}$ where $n = 2$ .

$25 (2 x + \frac{d}{d x} [- y^{2}])$

Step 1.3.1.4

Since $- 1$ is constant with respect to $x$ , the derivative of $- y^{2}$ with respect to $x$ is $- \frac{d}{d x} [y^{2}]$ .

$25 (2 x - \frac{d}{d x} [y^{2}])$

Step 1.3.2

Differentiate using the chain rule, which states that $\frac{d}{d x} [f (g (x))]$ is $f' (g (x)) g' (x)$ where $f (x) = x^{2}$ and $g (x) = y$ .

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Step 1.3.2.1

To apply the Chain Rule, set $u$ as $y$ .

$25 (2 x - (\frac{d}{d u} [u^{2}] \frac{d}{d x} [y]))$

Step 1.3.2.2

Differentiate using the Power Rule which states that $\frac{d}{d u} [u^{n}]$ is $n u^{n - 1}$ where $n = 2$ .

$25 (2 x - (2 u \frac{d}{d x} [y]))$

Step 1.3.2.3

Replace all occurrences of $u$ with $y$ .

$25 (2 x - (2 y \frac{d}{d x} [y]))$

Step 1.3.3

Multiply $2$ by $- 1$ .

$25 (2 x - 2 (y \frac{d}{d x} [y]))$

Step 1.3.4

Rewrite $\frac{d}{d x} [y]$ as $y'$ .

$25 (2 x - 2 y y')$

Step 1.3.5

Simplify.

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Step 1.3.5.1

Apply the distributive property.

$25 (2 x) + 25 (- 2 y y')$

Step 1.3.5.2

Combine terms.

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Step 1.3.5.2.1

Multiply $2$ by $25$ .

$50 x + 25 (- 2 y y')$

Step 1.3.5.2.2

Multiply $- 2$ by $25$ .

$50 x - 50 y y'$

Step 1.3.5.3

Reorder terms.

$- 50 y y' + 50 x$

Step 1.4

Reform the equation by setting the left side equal to the right side.

$(2 x + 2 y y') (4 x^{2} + 4 y^{2}) = - 50 y y' + 50 x$

Step 1.5

Solve for $y'$ .

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Step 1.5.1

Simplify $(2 x + 2 y y') (4 x^{2} + 4 y^{2})$ .

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Step 1.5.1.1

Rewrite.

$0 + 0 + (2 x + 2 y y') (4 x^{2} + 4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.2

Simplify by adding zeros.

$(2 x + 2 y y') (4 x^{2} + 4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.3

Expand $(2 x + 2 y y') (4 x^{2} + 4 y^{2})$ using the FOIL Method.

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Step 1.5.1.3.1

Apply the distributive property.

$2 x (4 x^{2} + 4 y^{2}) + 2 y y' (4 x^{2} + 4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.3.2

Apply the distributive property.

$2 x (4 x^{2}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2} + 4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.3.3

Apply the distributive property.

$2 x (4 x^{2}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4

Simplify each term.

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Step 1.5.1.4.1

Rewrite using the commutative property of multiplication.

$2 \cdot 4 x \cdot x^{2} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.2

Multiply $x$ by $x^{2}$ by adding the exponents.

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Step 1.5.1.4.2.1

Move $x^{2}$ .

$2 \cdot 4 (x^{2} x) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.2.2

Multiply $x^{2}$ by $x$ .

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Step 1.5.1.4.2.2.1

Raise $x$ to the power of $1$ .

$2 \cdot 4 (x^{2} x^{1}) + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.2.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$2 \cdot 4 x^{2 + 1} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.2.3

Add $2$ and $1$ .

$2 \cdot 4 x^{3} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.3

Multiply $2$ by $4$ .

$8 x^{3} + 2 x (4 y^{2}) + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.4

Rewrite using the commutative property of multiplication.

$8 x^{3} + 2 \cdot 4 x y^{2} + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.5

Multiply $2$ by $4$ .

$8 x^{3} + 8 x y^{2} + 2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.6

Multiply $4$ by $2$ .

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y y' (4 y^{2}) = - 50 y y' + 50 x$

Step 1.5.1.4.7

Multiply $y$ by $y^{2}$ by adding the exponents.

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Step 1.5.1.4.7.1

Move $y^{2}$ .

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 (y^{2} y) y' \cdot 4 = - 50 y y' + 50 x$

Step 1.5.1.4.7.2

Multiply $y^{2}$ by $y$ .

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Step 1.5.1.4.7.2.1

Raise $y$ to the power of $1$ .

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 (y^{2} y^{1}) y' \cdot 4 = - 50 y y' + 50 x$

Step 1.5.1.4.7.2.2

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y^{2 + 1} y' \cdot 4 = - 50 y y' + 50 x$

Step 1.5.1.4.7.3

Add $2$ and $1$ .

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 2 y^{3} y' \cdot 4 = - 50 y y' + 50 x$

Step 1.5.1.4.8

Multiply $4$ by $2$ .

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' = - 50 y y' + 50 x$

Step 1.5.2

Add $50 y y'$ to both sides of the equation.

$8 x^{3} + 8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x$

Step 1.5.3

Move all terms not containing $y'$ to the right side of the equation.

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Step 1.5.3.1

Subtract $8 x^{3}$ from both sides of the equation.

$8 x y^{2} + 8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3}$

Step 1.5.3.2

Subtract $8 x y^{2}$ from both sides of the equation.

$8 y y' x^{2} + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.4

Factor $2 y y'$ out of $8 y y' x^{2} + 8 y^{3} y' + 50 y y'$ .

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Step 1.5.4.1

Factor $2 y y'$ out of $8 y y' x^{2}$ .

$2 y y' (4 x^{2}) + 8 y^{3} y' + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.4.2

Factor $2 y y'$ out of $8 y^{3} y'$ .

$2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) + 50 y y' = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.4.3

Factor $2 y y'$ out of $50 y y'$ .

$2 y y' (4 x^{2}) + 2 y y' (4 y^{2}) + 2 y y' \cdot 25 = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.4.4

Factor $2 y y'$ out of $2 y y' (4 x^{2}) + 2 y y' (4 y^{2})$ .

$2 y y' (4 x^{2} + 4 y^{2}) + 2 y y' \cdot 25 = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.4.5

Factor $2 y y'$ out of $2 y y' (4 x^{2} + 4 y^{2}) + 2 y y' \cdot 25$ .

$2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$

Step 1.5.5

Divide each term in $2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$ by $2 y (4 x^{2} + 4 y^{2} + 25)$ and simplify.

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Step 1.5.5.1

Divide each term in $2 y y' (4 x^{2} + 4 y^{2} + 25) = 50 x - 8 x^{3} - 8 x y^{2}$ by $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$\frac{2 y y' (4 x^{2} + 4 y^{2} + 25)}{2 y (4 x^{2} + 4 y^{2} + 25)} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.2

Simplify the left side.

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Step 1.5.5.2.1

Cancel the common factor of $2$ .

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Step 1.5.5.2.1.1

Cancel the common factor.

Step 1.5.5.2.1.2

Rewrite the expression.

$\frac{y y' (4 x^{2} + 4 y^{2} + 25)}{y (4 x^{2} + 4 y^{2} + 25)} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.2.2

Cancel the common factor of $y$ .

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Step 1.5.5.2.2.1

Cancel the common factor.

Step 1.5.5.2.2.2

Rewrite the expression.

$\frac{y' (4 x^{2} + 4 y^{2} + 25)}{4 x^{2} + 4 y^{2} + 25} = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.2.3

Cancel the common factor of $4 x^{2} + 4 y^{2} + 25$ .

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Step 1.5.5.2.3.1

Cancel the common factor.

Step 1.5.5.2.3.2

Divide $y'$ by $1$ .

$y' = \frac{50 x}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3

Simplify the right side.

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Step 1.5.5.3.1

Simplify each term.

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Step 1.5.5.3.1.1

Cancel the common factor of $50$ and $2$ .

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Step 1.5.5.3.1.1.1

Factor $2$ out of $50 x$ .

$y' = \frac{2 (25 x)}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.1.2

Cancel the common factors.

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Step 1.5.5.3.1.1.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{2 (25 x)}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.1.2.2

Cancel the common factor.

$y' = \frac{2 (25 x)}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.1.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x^{3}}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.2

Cancel the common factor of $- 8$ and $2$ .

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Step 1.5.5.3.1.2.1

Factor $2$ out of $- 8 x^{3}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.2.2

Cancel the common factors.

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Step 1.5.5.3.1.2.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.2.2.2

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x^{3})}{2 (y (4 x^{2} + 4 y^{2} + 25))} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.2.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.3

Move the negative in front of the fraction.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 8 x y^{2}}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.4

Cancel the common factor of $- 8$ and $2$ .

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Step 1.5.5.3.1.4.1

Factor $2$ out of $- 8 x y^{2}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.4.2

Cancel the common factors.

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Step 1.5.5.3.1.4.2.1

Factor $2$ out of $2 y (4 x^{2} + 4 y^{2} + 25)$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 (y (4 x^{2} + 4 y^{2} + 25))}$

Step 1.5.5.3.1.4.2.2

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{2 (- 4 x y^{2})}{2 (y (4 x^{2} + 4 y^{2} + 25))}$

Step 1.5.5.3.1.4.2.3

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.5

Cancel the common factor of $y^{2}$ and $y$ .

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Step 1.5.5.3.1.5.1

Factor $y$ out of $- 4 x y^{2}$ .

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{y (- 4 x y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.5.2

Cancel the common factors.

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Step 1.5.5.3.1.5.2.1

Cancel the common factor.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{y (- 4 x y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.1.5.2.2

Rewrite the expression.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{- 4 x y}{4 x^{2} + 4 y^{2} + 25}$

Step 1.5.5.3.1.6

Move the negative in front of the fraction.

$y' = \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$

Step 1.5.5.3.2

To write $- \frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$ as a fraction with a common denominator, multiply by $\frac{y}{y}$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y}{4 x^{2} + 4 y^{2} + 25} \cdot \frac{y}{y}$

Step 1.5.5.3.3

Write each expression with a common denominator of $y (4 x^{2} + 4 y^{2} + 25)$ , by multiplying each by an appropriate factor of $1$ .

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Step 1.5.5.3.3.1

Multiply $\frac{4 x y}{4 x^{2} + 4 y^{2} + 25}$ by $\frac{y}{y}$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y \cdot y}{(4 x^{2} + 4 y^{2} + 25) y}$

Step 1.5.5.3.3.2

Reorder the factors of $(4 x^{2} + 4 y^{2} + 25) y$ .

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x}{y (4 x^{2} + 4 y^{2} + 25)} - \frac{4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.4

Combine the numerators over the common denominator.

$y' = - \frac{4 x^{3}}{y (4 x^{2} + 4 y^{2} + 25)} + \frac{25 x - 4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.5

Combine the numerators over the common denominator.

$y' = \frac{- 4 x^{3} + 25 x - 4 x y \cdot y}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.6

Multiply $y$ by $y$ by adding the exponents.

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Step 1.5.5.3.6.1

Move $y$ .

$y' = \frac{- 4 x^{3} + 25 x - 4 x (y \cdot y)}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.6.2

Multiply $y$ by $y$ .

$y' = \frac{- 4 x^{3} + 25 x - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.7

Factor $x$ out of $- 4 x^{3} + 25 x - 4 x y^{2}$ .

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Step 1.5.5.3.7.1

Factor $x$ out of $- 4 x^{3}$ .

$y' = \frac{x (- 4 x^{2}) + 25 x - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.7.2

Factor $x$ out of $25 x$ .

$y' = \frac{x (- 4 x^{2}) + x \cdot 25 - 4 x y^{2}}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.7.3

Factor $x$ out of $- 4 x y^{2}$ .

$y' = \frac{x (- 4 x^{2}) + x \cdot 25 + x (- 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.7.4

Factor $x$ out of $x (- 4 x^{2}) + x \cdot 25$ .

$y' = \frac{x (- 4 x^{2} + 25) + x (- 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.7.5

Factor $x$ out of $x (- 4 x^{2} + 25) + x (- 4 y^{2})$ .

$y' = \frac{x (- 4 x^{2} + 25 - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.8

Factor $- 1$ out of $- 4 x^{2}$ .

$y' = \frac{x (- (4 x^{2}) + 25 - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.9

Rewrite $25$ as $- 1 (- 25)$ .

$y' = \frac{x (- (4 x^{2}) - 1 (- 25) - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.10

Factor $- 1$ out of $- (4 x^{2}) - 1 (- 25)$ .

$y' = \frac{x (- (4 x^{2} - 25) - 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.11

Factor $- 1$ out of $- 4 y^{2}$ .

$y' = \frac{x (- (4 x^{2} - 25) - (4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.12

Factor $- 1$ out of $- (4 x^{2} - 25) - (4 y^{2})$ .

$y' = \frac{x (- (4 x^{2} - 25 + 4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.13

Simplify the expression.

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Step 1.5.5.3.13.1

Rewrite $- (4 x^{2} - 25 + 4 y^{2})$ as $- 1 (4 x^{2} - 25 + 4 y^{2})$ .

$y' = \frac{x (- 1 (4 x^{2} - 25 + 4 y^{2}))}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.5.5.3.13.2

Move the negative in front of the fraction.

$y' = - \frac{x (4 x^{2} - 25 + 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.6

Replace $y'$ with $\frac{d y}{d x}$ .

$\frac{d y}{d x} = - \frac{x (4 x^{2} - 25 + 4 y^{2})}{y (4 x^{2} + 4 y^{2} + 25)}$

Step 1.7

Evaluate at $x = - 3$ and $y = - 1$ .

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Step 1.7.1

Replace the variable $x$ with $- 3$ in the expression.

$- \frac{(- 3) (4 {(- 3)}^{2} - 25 + 4 y^{2})}{y (4 {(- 3)}^{2} + 4 y^{2} + 25)}$

Step 1.7.2

Replace the variable $y$ with $- 1$ in the expression.

$- \frac{(- 3) (4 {(- 3)}^{2} - 25 + 4 {(- 1)}^{2})}{(- 1) (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3

Simplify the numerator.

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Step 1.7.3.1

Raise $- 3$ to the power of $2$ .

$- \frac{- 3 (4 \cdot 9 - 25 + 4 {(- 1)}^{2})}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3.2

Multiply $4$ by $9$ .

$- \frac{- 3 (36 - 25 + 4 {(- 1)}^{2})}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3.3

Raise $- 1$ to the power of $2$ .

$- \frac{- 3 (36 - 25 + 4 \cdot 1)}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3.4

Multiply $4$ by $1$ .

$- \frac{- 3 (36 - 25 + 4)}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3.5

Subtract $25$ from $36$ .

$- \frac{- 3 (11 + 4)}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.3.6

Add $11$ and $4$ .

$- \frac{- 3 \cdot 15}{- 1 (4 {(- 3)}^{2} + 4 {(- 1)}^{2} + 25)}$

Step 1.7.4

Simplify the denominator.

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Step 1.7.4.1

Raise $- 3$ to the power of $2$ .

$- \frac{- 3 \cdot 15}{- 1 (4 \cdot 9 + 4 {(- 1)}^{2} + 25)}$

Step 1.7.4.2

Multiply $4$ by $9$ .

$- \frac{- 3 \cdot 15}{- 1 (36 + 4 {(- 1)}^{2} + 25)}$

Step 1.7.4.3

Raise $- 1$ to the power of $2$ .

$- \frac{- 3 \cdot 15}{- 1 (36 + 4 \cdot 1 + 25)}$

Step 1.7.4.4

Multiply $4$ by $1$ .

$- \frac{- 3 \cdot 15}{- 1 (36 + 4 + 25)}$

Step 1.7.4.5

Add $36$ and $4$ .

$- \frac{- 3 \cdot 15}{- 1 (40 + 25)}$

Step 1.7.4.6

Add $40$ and $25$ .

$- \frac{- 3 \cdot 15}{- 1 \cdot 65}$

Step 1.7.5

Reduce the expression by cancelling the common factors.

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Step 1.7.5.1

Multiply $- 3$ by $15$ .

$- \frac{- 45}{- 1 \cdot 65}$

Step 1.7.5.2

Multiply $- 1$ by $65$ .

$- \frac{- 45}{- 65}$

Step 1.7.5.3

Cancel the common factor of $- 45$ and $- 65$ .

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Step 1.7.5.3.1

Factor $- 5$ out of $- 45$ .

$- \frac{- 5 (9)}{- 65}$

Step 1.7.5.3.2

Cancel the common factors.

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Step 1.7.5.3.2.1

Factor $- 5$ out of $- 65$ .

$- \frac{- 5 \cdot 9}{- 5 \cdot 13}$

Step 1.7.5.3.2.2

Cancel the common factor.

$- \frac{- 5 \cdot 9}{- 5 \cdot 13}$

Step 1.7.5.3.2.3

Rewrite the expression.

$- \frac{9}{13}$

Step 2

Plug the slope and point values into the point-slope formula and solve for $y$ .

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Step 2.1

Use the slope $- \frac{9}{13}$ and a given point $(- 3, - 1)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (- 1) = - \frac{9}{13} \cdot (x - (- 3))$

Step 2.2

Simplify the equation and keep it in point-slope form.

$y + 1 = - \frac{9}{13} \cdot (x + 3)$

Step 2.3

Solve for $y$ .

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Step 2.3.1

Simplify $- \frac{9}{13} \cdot (x + 3)$ .

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Step 2.3.1.1

Rewrite.

$y + 1 = 0 + 0 - \frac{9}{13} \cdot (x + 3)$

Step 2.3.1.2

Simplify by adding zeros.

$y + 1 = - \frac{9}{13} \cdot (x + 3)$

Step 2.3.1.3

Apply the distributive property.

$y + 1 = - \frac{9}{13} x - \frac{9}{13} \cdot 3$

Step 2.3.1.4

Combine $x$ and $\frac{9}{13}$ .

$y + 1 = - \frac{x \cdot 9}{13} - \frac{9}{13} \cdot 3$

Step 2.3.1.5

Multiply $- \frac{9}{13} \cdot 3$ .

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Step 2.3.1.5.1

Multiply $3$ by $- 1$ .

$y + 1 = - \frac{x \cdot 9}{13} - 3 (\frac{9}{13})$

Step 2.3.1.5.2

Combine $- 3$ and $\frac{9}{13}$ .

$y + 1 = - \frac{x \cdot 9}{13} + \frac{- 3 \cdot 9}{13}$

Step 2.3.1.5.3

Multiply $- 3$ by $9$ .

$y + 1 = - \frac{x \cdot 9}{13} + \frac{- 27}{13}$

Step 2.3.1.6

Simplify each term.

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Step 2.3.1.6.1

Move $9$ to the left of $x$ .

$y + 1 = - \frac{9 \cdot x}{13} + \frac{- 27}{13}$

Step 2.3.1.6.2

Move the negative in front of the fraction.

$y + 1 = - \frac{9 x}{13} - \frac{27}{13}$

Step 2.3.2

Move all terms not containing $y$ to the right side of the equation.

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Step 2.3.2.1

Subtract $1$ from both sides of the equation.

$y = - \frac{9 x}{13} - \frac{27}{13} - 1$

Step 2.3.2.2

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{13}{13}$ .

$y = - \frac{9 x}{13} - \frac{27}{13} - 1 \cdot \frac{13}{13}$

Step 2.3.2.3

Combine $- 1$ and $\frac{13}{13}$ .

$y = - \frac{9 x}{13} - \frac{27}{13} + \frac{- 1 \cdot 13}{13}$

Step 2.3.2.4

Combine the numerators over the common denominator.

$y = - \frac{9 x}{13} + \frac{- 27 - 1 \cdot 13}{13}$

Step 2.3.2.5

Simplify the numerator.

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Step 2.3.2.5.1

Multiply $- 1$ by $13$ .

$y = - \frac{9 x}{13} + \frac{- 27 - 13}{13}$

Step 2.3.2.5.2

Subtract $13$ from $- 27$ .

$y = - \frac{9 x}{13} + \frac{- 40}{13}$

Step 2.3.2.6

Move the negative in front of the fraction.

$y = - \frac{9 x}{13} - \frac{40}{13}$

Step 2.3.3

Write in $y = m x + b$ form.

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Step 2.3.3.1

Reorder terms.

$y = - (\frac{9}{13} x) - \frac{40}{13}$

Step 2.3.3.2

Remove parentheses.

$y = - \frac{9}{13} x - \frac{40}{13}$

Step 3