Calculus Examples

$\frac{0.13411983}{\ln (1 + 0.08333 \cdot 0.1)}$

Step 1

Simplify the denominator.

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Step 1.1

Multiply $0.08333$ by $0.1$ .

$\frac{0.13411983}{\ln (1 + 0.008333)}$

Step 1.2

Add $1$ and $0.008333$ .

$\frac{0.13411983}{\ln (1.008333)}$

Step 2

Replace $e$ with an approximation.

$\frac{0.13411983}{\log_{2.71828182} (1.008333)}$

Step 3

Log base $2.71828182$ of $1.008333$ is approximately $0.00829847$ .

$\frac{0.13411983}{0.00829847}$

Step 4

Divide $0.13411983$ by $0.00829847$ .

$16.16199056$