Calculus Examples

$15 = 5 + 27 t - 16 t^{2}$

Step 1

Rewrite the equation as $5 + 27 t - 16 t^{2} = 15$ .

$5 + 27 t - 16 t^{2} = 15$

Step 2

Move all terms to the left side of the equation and simplify.

Tap for more steps...

Step 2.1

Subtract $15$ from both sides of the equation.

$5 + 27 t - 16 t^{2} - 15 = 0$

Step 2.2

Subtract $15$ from $5$ .

$27 t - 16 t^{2} - 10 = 0$

Step 3

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 4

Substitute the values $a = - 16$ , $b = 27$ , and $c = - 10$ into the quadratic formula and solve for $t$ .

$\frac{- 27 \pm \sqrt{27^{2} - 4 \cdot (- 16 \cdot - 10)}}{2 \cdot - 16}$

Step 5

Simplify.

Tap for more steps...

Step 5.1

Simplify the numerator.

Tap for more steps...

Step 5.1.1

Raise $27$ to the power of $2$ .

$t = \frac{- 27 \pm \sqrt{729 - 4 \cdot - 16 \cdot - 10}}{2 \cdot - 16}$

Step 5.1.2

Multiply $- 4 \cdot - 16 \cdot - 10$ .

Tap for more steps...

Step 5.1.2.1

Multiply $- 4$ by $- 16$ .

$t = \frac{- 27 \pm \sqrt{729 + 64 \cdot - 10}}{2 \cdot - 16}$

Step 5.1.2.2

Multiply $64$ by $- 10$ .

$t = \frac{- 27 \pm \sqrt{729 - 640}}{2 \cdot - 16}$

Step 5.1.3

Subtract $640$ from $729$ .

$t = \frac{- 27 \pm \sqrt{89}}{2 \cdot - 16}$

Step 5.2

Multiply $2$ by $- 16$ .

$t = \frac{- 27 \pm \sqrt{89}}{- 32}$

Step 5.3

Simplify $\frac{- 27 \pm \sqrt{89}}{- 32}$ .

$t = \frac{27 \pm \sqrt{89}}{32}$

Step 6

The final answer is the combination of both solutions.

$t = \frac{27 + \sqrt{89}}{32}, \frac{27 - \sqrt{89}}{32}$

Step 7

The result can be shown in multiple forms.

Exact Form:

$t = \frac{27 + \sqrt{89}}{32}, \frac{27 - \sqrt{89}}{32}$

Decimal Form:

$t = 1.13856191 \dots, 0.54893808 \dots$