Calculus Examples

$\sum_{k = 1}^{16} k$

Step 1

The formula for the summation of a polynomial with degree $1$ is:

$\sum_{k = 1}^{n} k = \frac{n (n + 1)}{2}$

Step 2

Substitute the values into the formula.

$\frac{16 (16 + 1)}{2}$

Step 3

Simplify.

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Step 3.1

Cancel the common factor of $16$ and $2$ .

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Step 3.1.1

Factor $2$ out of $16 (16 + 1)$ .

$\frac{2 (8 (16 + 1))}{2}$

Step 3.1.2

Cancel the common factors.

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Step 3.1.2.1

Factor $2$ out of $2$ .

$\frac{2 (8 (16 + 1))}{2 (1)}$

Step 3.1.2.2

Cancel the common factor.

$\frac{2 (8 (16 + 1))}{2 \cdot 1}$

Step 3.1.2.3

Rewrite the expression.

$\frac{8 (16 + 1)}{1}$

Step 3.1.2.4

Divide $8 (16 + 1)$ by $1$ .

$8 (16 + 1)$

$8 (16 + 1)$

$8 (16 + 1)$

Step 3.2

Simplify the expression.

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Step 3.2.1

Add $16$ and $1$ .

$8 \cdot 17$

Step 3.2.2

Multiply $8$ by $17$ .

$136$

$136$

$136$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$