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Calculus Examples
3cos(3x)=03cos(3x)=0
Step 1
Step 1.1
Divide each term in 3cos(3x)=03cos(3x)=0 by 33.
3cos(3x)3=033cos(3x)3=03
Step 1.2
Simplify the left side.
Step 1.2.1
Cancel the common factor of 33.
Step 1.2.1.1
Cancel the common factor.
3cos(3x)3=03
Step 1.2.1.2
Divide cos(3x) by 1.
cos(3x)=03
cos(3x)=03
cos(3x)=03
Step 1.3
Simplify the right side.
Step 1.3.1
Divide 0 by 3.
cos(3x)=0
cos(3x)=0
cos(3x)=0
Step 2
Take the inverse cosine of both sides of the equation to extract x from inside the cosine.
3x=arccos(0)
Step 3
Step 3.1
The exact value of arccos(0) is π2.
3x=π2
3x=π2
Step 4
Step 4.1
Divide each term in 3x=π2 by 3.
3x3=π23
Step 4.2
Simplify the left side.
Step 4.2.1
Cancel the common factor of 3.
Step 4.2.1.1
Cancel the common factor.
3x3=π23
Step 4.2.1.2
Divide x by 1.
x=π23
x=π23
x=π23
Step 4.3
Simplify the right side.
Step 4.3.1
Multiply the numerator by the reciprocal of the denominator.
x=π2⋅13
Step 4.3.2
Multiply π2⋅13.
Step 4.3.2.1
Multiply π2 by 13.
x=π2⋅3
Step 4.3.2.2
Multiply 2 by 3.
x=π6
x=π6
x=π6
x=π6
Step 5
The cosine function is positive in the first and fourth quadrants. To find the second solution, subtract the reference angle from 2π to find the solution in the fourth quadrant.
3x=2π-π2
Step 6
Step 6.1
Simplify.
Step 6.1.1
To write 2π as a fraction with a common denominator, multiply by 22.
3x=2π⋅22-π2
Step 6.1.2
Combine 2π and 22.
3x=2π⋅22-π2
Step 6.1.3
Combine the numerators over the common denominator.
3x=2π⋅2-π2
Step 6.1.4
Multiply 2 by 2.
3x=4π-π2
Step 6.1.5
Subtract π from 4π.
3x=3π2
3x=3π2
Step 6.2
Divide each term in 3x=3π2 by 3 and simplify.
Step 6.2.1
Divide each term in 3x=3π2 by 3.
3x3=3π23
Step 6.2.2
Simplify the left side.
Step 6.2.2.1
Cancel the common factor of 3.
Step 6.2.2.1.1
Cancel the common factor.
3x3=3π23
Step 6.2.2.1.2
Divide x by 1.
x=3π23
x=3π23
x=3π23
Step 6.2.3
Simplify the right side.
Step 6.2.3.1
Multiply the numerator by the reciprocal of the denominator.
x=3π2⋅13
Step 6.2.3.2
Cancel the common factor of 3.
Step 6.2.3.2.1
Factor 3 out of 3π.
x=3(π)2⋅13
Step 6.2.3.2.2
Cancel the common factor.
x=3π2⋅13
Step 6.2.3.2.3
Rewrite the expression.
x=π2
x=π2
x=π2
x=π2
x=π2
Step 7
Step 7.1
The period of the function can be calculated using 2π|b|.
2π|b|
Step 7.2
Replace b with 3 in the formula for period.
2π|3|
Step 7.3
The absolute value is the distance between a number and zero. The distance between 0 and 3 is 3.
2π3
2π3
Step 8
The period of the cos(3x) function is 2π3 so values will repeat every 2π3 radians in both directions.
x=π6+2πn3,π2+2πn3, for any integer n
Step 9
Consolidate the answers.
x=π6+πn3, for any integer n