Calculus Examples

$120 x + \frac{73 x^{- 3}}{2} - \frac{50 x^{- 6}}{3} + 15 x^{- 7} = 0$

Step 1

Simplify each term.

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Step 1.1

Move $x^{- 3}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$120 x + \frac{73}{2 x^{3}} - \frac{50 x^{- 6}}{3} + 15 x^{- 7} = 0$

Step 1.2

Move $x^{- 6}$ to the denominator using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$120 x + \frac{73}{2 x^{3}} - \frac{50}{3 x^{6}} + 15 x^{- 7} = 0$

Step 1.3

Rewrite the expression using the negative exponent rule $b^{- n} = \frac{1}{b^{n}}$ .

$120 x + \frac{73}{2 x^{3}} - \frac{50}{3 x^{6}} + 15 \frac{1}{x^{7}} = 0$

Step 1.4

Combine $15$ and $\frac{1}{x^{7}}$ .

$120 x + \frac{73}{2 x^{3}} - \frac{50}{3 x^{6}} + \frac{15}{x^{7}} = 0$

Step 2

Graph each side of the equation. The solution is the x-value of the point of intersection.

No solution