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Calculus Examples
cot(arccos(x))
Step 1
Draw a triangle in the plane with vertices (x,√12-x2), (x,0), and the origin. Then arccos(x) is the angle between the positive x-axis and the ray beginning at the origin and passing through (x,√12-x2). Therefore, cot(arccos(x)) is x√1-x2.
x√1-x2
Step 2
Step 2.1
Rewrite 1 as 12.
x√12-x2
Step 2.2
Since both terms are perfect squares, factor using the difference of squares formula, a2-b2=(a+b)(a-b) where a=1 and b=x.
x√(1+x)(1-x)
x√(1+x)(1-x)
Step 3
Multiply x√(1+x)(1-x) by √(1+x)(1-x)√(1+x)(1-x).
x√(1+x)(1-x)⋅√(1+x)(1-x)√(1+x)(1-x)
Step 4
Step 4.1
Multiply x√(1+x)(1-x) by √(1+x)(1-x)√(1+x)(1-x).
x√(1+x)(1-x)√(1+x)(1-x)√(1+x)(1-x)
Step 4.2
Raise √(1+x)(1-x) to the power of 1.
x√(1+x)(1-x)√(1+x)(1-x)1√(1+x)(1-x)
Step 4.3
Raise √(1+x)(1-x) to the power of 1.
x√(1+x)(1-x)√(1+x)(1-x)1√(1+x)(1-x)1
Step 4.4
Use the power rule aman=am+n to combine exponents.
x√(1+x)(1-x)√(1+x)(1-x)1+1
Step 4.5
Add 1 and 1.
x√(1+x)(1-x)√(1+x)(1-x)2
Step 4.6
Rewrite √(1+x)(1-x)2 as (1+x)(1-x).
Step 4.6.1
Use n√ax=axn to rewrite √(1+x)(1-x) as ((1+x)(1-x))12.
x√(1+x)(1-x)(((1+x)(1-x))12)2
Step 4.6.2
Apply the power rule and multiply exponents, (am)n=amn.
x√(1+x)(1-x)((1+x)(1-x))12⋅2
Step 4.6.3
Combine 12 and 2.
x√(1+x)(1-x)((1+x)(1-x))22
Step 4.6.4
Cancel the common factor of 2.
Step 4.6.4.1
Cancel the common factor.
x√(1+x)(1-x)((1+x)(1-x))22
Step 4.6.4.2
Rewrite the expression.
x√(1+x)(1-x)((1+x)(1-x))1
x√(1+x)(1-x)((1+x)(1-x))1
Step 4.6.5
Simplify.
x√(1+x)(1-x)(1+x)(1-x)
x√(1+x)(1-x)(1+x)(1-x)
x√(1+x)(1-x)(1+x)(1-x)