Calculus Examples

$y = \frac{1}{6} \cdot {(1 + \cos^{2} (7 t))}^{3}$

Step 1

Since $\frac{1}{6}$ is constant with respect to $t$ , the derivative of $\frac{1}{6} \cdot {(1 + \cos^{2} (7 t))}^{3}$ with respect to $t$ is $\frac{1}{6} \frac{d}{d t} [{(1 + \cos^{2} (7 t))}^{3}]$ .

$\frac{1}{6} \frac{d}{d t} [{(1 + \cos^{2} (7 t))}^{3}]$

Step 2

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = t^{3}$ and $g (t) = 1 + \cos^{2} (7 t)$ .

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Step 2.1

To apply the Chain Rule, set $u_{1}$ as $1 + \cos^{2} (7 t)$ .

$\frac{1}{6} (\frac{d}{d u_{1}} [{u_{1}}^{3}] \frac{d}{d t} [1 + \cos^{2} (7 t)])$

Step 2.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{1}} [{u_{1}}^{n}]$ is $n {u_{1}}^{n - 1}$ where $n = 3$ .

$\frac{1}{6} (3 {u_{1}}^{2} \frac{d}{d t} [1 + \cos^{2} (7 t)])$

Step 2.3

Replace all occurrences of $u_{1}$ with $1 + \cos^{2} (7 t)$ .

$\frac{1}{6} (3 {(1 + \cos^{2} (7 t))}^{2} \frac{d}{d t} [1 + \cos^{2} (7 t)])$

Step 3

Differentiate.

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Step 3.1

Combine $3$ and $\frac{1}{6}$ .

$\frac{3}{6} ({(1 + \cos^{2} (7 t))}^{2} \frac{d}{d t} [1 + \cos^{2} (7 t)])$

Step 3.2

Simplify terms.

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Step 3.2.1

Combine ${(1 + \cos^{2} (7 t))}^{2}$ and $\frac{3}{6}$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2} \cdot 3}{6} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.2.2

Move $3$ to the left of ${(1 + \cos^{2} (7 t))}^{2}$ .

$\frac{3 \cdot {(1 + \cos^{2} (7 t))}^{2}}{6} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.2.3

Cancel the common factor of $3$ and $6$ .

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Step 3.2.3.1

Factor $3$ out of $3 {(1 + \cos^{2} (7 t))}^{2}$ .

$\frac{3 ({(1 + \cos^{2} (7 t))}^{2})}{6} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.2.3.2

Cancel the common factors.

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Step 3.2.3.2.1

Factor $3$ out of $6$ .

$\frac{3 {(1 + \cos^{2} (7 t))}^{2}}{3 \cdot 2} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.2.3.2.2

Cancel the common factor.

$\frac{3 {(1 + \cos^{2} (7 t))}^{2}}{3 \cdot 2} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.2.3.2.3

Rewrite the expression.

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} \frac{d}{d t} [1 + \cos^{2} (7 t)]$

Step 3.3

By the Sum Rule, the derivative of $1 + \cos^{2} (7 t)$ with respect to $t$ is $\frac{d}{d t} [1] + \frac{d}{d t} [\cos^{2} (7 t)]$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} (\frac{d}{d t} [1] + \frac{d}{d t} [\cos^{2} (7 t)])$

Step 3.4

Since $1$ is constant with respect to $t$ , the derivative of $1$ with respect to $t$ is $0$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} (0 + \frac{d}{d t} [\cos^{2} (7 t)])$

Step 3.5

Add $0$ and $\frac{d}{d t} [\cos^{2} (7 t)]$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} \frac{d}{d t} [\cos^{2} (7 t)]$

Step 4

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = t^{2}$ and $g (t) = \cos (7 t)$ .

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Step 4.1

To apply the Chain Rule, set $u_{2}$ as $\cos (7 t)$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} (\frac{d}{d u_{2}} [{u_{2}}^{2}] \frac{d}{d t} [\cos (7 t)])$

Step 4.2

Differentiate using the Power Rule which states that $\frac{d}{d u_{2}} [{u_{2}}^{n}]$ is $n {u_{2}}^{n - 1}$ where $n = 2$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} (2 u_{2} \frac{d}{d t} [\cos (7 t)])$

Step 4.3

Replace all occurrences of $u_{2}$ with $\cos (7 t)$ .

$\frac{{(1 + \cos^{2} (7 t))}^{2}}{2} (2 \cos (7 t) \frac{d}{d t} [\cos (7 t)])$

Step 5

Simplify terms.

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Step 5.1

Combine $2$ and $\frac{{(1 + \cos^{2} (7 t))}^{2}}{2}$ .

$\frac{2 {(1 + \cos^{2} (7 t))}^{2}}{2} (\cos (7 t) \frac{d}{d t} [\cos (7 t)])$

Step 5.2

Combine $\cos (7 t)$ and $\frac{2 {(1 + \cos^{2} (7 t))}^{2}}{2}$ .

$\frac{\cos (7 t) (2 {(1 + \cos^{2} (7 t))}^{2})}{2} \frac{d}{d t} [\cos (7 t)]$

Step 5.3

Move $2$ to the left of $\cos (7 t)$ .

$\frac{2 \cdot \cos (7 t) {(1 + \cos^{2} (7 t))}^{2}}{2} \frac{d}{d t} [\cos (7 t)]$

Step 5.4

Cancel the common factor of $2$ .

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Step 5.4.1

Cancel the common factor.

$\frac{2 \cos (7 t) {(1 + \cos^{2} (7 t))}^{2}}{2} \frac{d}{d t} [\cos (7 t)]$

Step 5.4.2

Divide $\cos (7 t) {(1 + \cos^{2} (7 t))}^{2}$ by $1$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} \frac{d}{d t} [\cos (7 t)]$

Step 6

Differentiate using the chain rule, which states that $\frac{d}{d t} [f (g (t))]$ is $f' (g (t)) g' (t)$ where $f (t) = \cos (t)$ and $g (t) = 7 t$ .

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Step 6.1

To apply the Chain Rule, set $u_{3}$ as $7 t$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (\frac{d}{d u_{3}} [\cos (u_{3})] \frac{d}{d t} [7 t])$

Step 6.2

The derivative of $\cos (u_{3})$ with respect to $u_{3}$ is $- \sin (u_{3})$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- \sin (u_{3}) \frac{d}{d t} [7 t])$

Step 6.3

Replace all occurrences of $u_{3}$ with $7 t$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- \sin (7 t) \frac{d}{d t} [7 t])$

Step 7

Differentiate.

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Step 7.1

Since $7$ is constant with respect to $t$ , the derivative of $7 t$ with respect to $t$ is $7 \frac{d}{d t} [t]$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- \sin (7 t) (7 \frac{d}{d t} [t]))$

Step 7.2

Multiply $7$ by $- 1$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- 7 \sin (7 t) \frac{d}{d t} [t])$

Step 7.3

Differentiate using the Power Rule which states that $\frac{d}{d t} [t^{n}]$ is $n t^{n - 1}$ where $n = 1$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- 7 \sin (7 t) \cdot 1)$

Step 7.4

Simplify the expression.

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Step 7.4.1

Multiply $- 7$ by $1$ .

$\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- 7 \sin (7 t))$

Step 7.4.2

Reorder the factors of $\cos (7 t) {(1 + \cos^{2} (7 t))}^{2} (- 7 \sin (7 t))$ .

$- 7 {(1 + \cos^{2} (7 t))}^{2} \cos (7 t) \sin (7 t)$